A = − 9 . − 3 + 21. − 2 + 25 A = 27 + − 42 + 25 A = 27 + 25 + − 42 = 10 B = − 5 − 13 + − 3 . − 7 − 80 B = 65 + 21 − 80 B = 86 − 80 = 6

Vậy A > B

A = − 9 . − 3 + 21. − 2 + 25 A = 27 + − 42 + 25 A = 27 + 25 + − 42 = 10

B = − 5 − 13 + − 3 . − 7 − 80 B = 65 + 21 − 80 B = 86 − 80 = 6

Vậy A > B

Thực hiện phép tính ta được A = l0 ; B = 6.

Từ đó suy ra A > B.

a >

b <

c >

d <

>

<

>

<

\(a:ta.c\text{ó}:BCNN:12\\ \dfrac{2}{3}=\dfrac{2\cdot4}{3\cdot4}=\dfrac{8}{12};\dfrac{1}{4}=\dfrac{1\cdot3}{4\cdot3}=\dfrac{3}{12}\\ v\text{ì }\dfrac{8}{12}< \dfrac{3}{12}n\text{ê}n\dfrac{2}{3}< \dfrac{1}{4}\\ b:ta.c\text{ó}:\\ 10=2\cdot5\\ 8=2^3\\ \Rightarrow BCNN=2^3\cdot5=8\cdot5=40\\ \dfrac{7}{10}=\dfrac{7\cdot4}{10\cdot4}=\dfrac{28}{40};\dfrac{7}{8}=\dfrac{7\cdot5}{8\cdot5}=\dfrac{35}{40}\\ v\text{ì }\dfrac{28}{40}< \dfrac{35}{40}n\text{ê}n\dfrac{7}{10}< \dfrac{7}{8}\\ c:ta.c\text{ó}:\\ 7=7;5=5\\ \Rightarrow BCNN=7\cdot5=35\\ \dfrac{6}{7}=\dfrac{6\cdot5}{7\cdot5}=\dfrac{30}{35};\dfrac{3}{5}=\dfrac{3\cdot7}{5\cdot7}=\dfrac{21}{35}\\ v\text{ì }\dfrac{30}{35}>\dfrac{21}{35}n\text{ê}n\dfrac{6}{7}>\dfrac{3}{5}\\ d:ta.c\text{ó}:\\ 21=3\cdot7\\ 72=2^3\cdot3^2\\ \Rightarrow BCNN=2^3\cdot3^2\cdot7=504\\ \dfrac{14}{21}=\dfrac{14\cdot24}{21\cdot24}=\dfrac{336}{504};\dfrac{60}{72}=\dfrac{60\cdot7}{72\cdot7}=\dfrac{420}{504}\\ v\text{ì }\dfrac{336}{504}< \dfrac{420}{504}n\text{ê}n\dfrac{14}{21}< \dfrac{60}{72}\)

em trả lời ccaua này hi vọng thầy còn nhớ em

a) -9/4<`1/3

c) 9/-5<7/-10

a) \(\dfrac{-9}{4}< 0\)

\(0< \dfrac{1}{3}\)

Do đó: \(\dfrac{-9}{4}< \dfrac{1}{3}\)

Ta có:

Tập hợp A:
\(A=\left\{1;5;9;13;17;21;25\right\}\)

Tập hợp B:

\(B=\left\{0;1;3;5;10;13\right\}\)

Mà: \(A\cap B\)

\(\Rightarrow A\cap B=\left\{1;5;13\right\}\)

⇒ Chọn B