Tìm X
a/. X x 8 = 2864
b/. X : 5 = 1232
Tìm X:
a/. X x 8 = 2864
b/. X : 5 = 1232
a/. X x 8 = 2864
X = 2864 : 8
X = 358
b/. X : 5 = 1232
X = 1232 x 5
X = 6160
Tìm X:
a/. X x 8 = 2864
b/. X : 5 = 1232
a/. X x 8 = 2864
X = 2864 : 8
X = 358
b/. X : 5 = 1232
X = 1232 x 5
X = 6160
Tìm x
a) x/-8 = 5/4
b) -13/x = -65/10
c)-6/5 = -12/x
d) x-2/2= 8/x-2
a)
`x/(-8)=5/4`
`=>x*4=5*(-8)`
`=>4x=-40`
`=>x=-40:4`
`=>x=-10`
b)
`(-13)/x=(-65)/10`
`=>(-13)/x=(-13)/2`
`=>x=2`
c)
`(-6)/5=(-12)/x`
`<=>(-12)/10=(-12)/x`
`<=>x=10`
d)
`(x-2)/2=8/(x-2)`
`=>(x-2)(x-2)=8*2`
`=>(x-2)^2=16`
`=>x-2=4` hoặc`x-2=-4`
`=>x=4+2` hoặc `x=-4+2`
`=>x=6` hoặc `x=-2`
`x/(-8) = 5/4`
`=> 4x=5.(-8)`
`=>4x=-40`
`=>x=-40:4`
`=>x=-10`
__
`-13/x =-65/10`
`=> -65x=-130`
`=>x=-130:(-65)`
`=>x= 2`
__
`-6/5 =-12/x`
`=> -6x=-12.5`
`=> -6x= -60`
`=>x=-60:(-6)`
`=>x=10`
__
`(x-2)/2 = 8/(x-2)`
`=>(x-2)^2=2.8`
`=>(x-2)^2=16`
`=> (x-2)^2=+-4^2`
\(\Rightarrow\left[{}\begin{matrix}x-2=4\\x-2=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=6\\x=-2\end{matrix}\right.\)
tìm x
a x/5 =8/10
b 9/x=90/100
c 17+x/35 =5/7
d x:5/27=2/9
a. \(\dfrac{x}{5}=\dfrac{8}{10}\)
\(\Rightarrow10x=8.5\)
\(\Rightarrow10x=40\)
\(\Rightarrow x=\dfrac{40}{10}=4\)
b. \(\dfrac{9}{x}=\dfrac{90}{100}\)
\(\Rightarrow9.100=90x\)
\(\Rightarrow900=90x\)
\(\Rightarrow x=\dfrac{900}{90}=10\)
c. \(17+\dfrac{x}{35}=\dfrac{5}{7}\)
\(\Rightarrow\dfrac{595+x}{35}=\dfrac{25}{35}\)
\(\Rightarrow595+x=25\)
\(\Rightarrow x=25-595=-570\)
d. \(x:\dfrac{5}{27}=\dfrac{2}{9}\)
\(\Rightarrow\dfrac{27x:5}{27}=\dfrac{6}{27}\)
\(\Rightarrow27x:5=6\)
\(\Rightarrow27x=5.6\)
\(\Rightarrow27x=30\)
\(\Rightarrow x=\dfrac{30}{27}=\dfrac{10}{9}\approx1,11\)
Bài 2: Tìm x
a) x - 2/11 = -5/11
b) x - 1/24 = -1/8 + 5/6
c) 5/8 - x = 1/9 - (-5/4)
d) 8/23 . 46/24 - x = 1/3
e) 1/5 : x = 1/5 + 1/7
a: x=-5/11+2/11=-3/11
b: =>x=-3/24+20/24+1/24=18/24=3/4
c: =>5/8-x=1/9+5/4=4/36+45/36=49/36
=>x=5/8-49/36=-53/72
d: =>2/3-x=1/3
=>x=1/3
e: =>1/5:x=12/35
=>x=7/12
Tìm x
a) x + 2/5 = 1/2
b) x + 3/7 = 2/5 + 3/10
c) 19 - x = 8/5 - 3/4
\(a,x=\dfrac{1}{2}-\dfrac{2}{5}\)
\(x=\dfrac{1}{10}\)
\(b,x+\dfrac{3}{7}=\dfrac{7}{10}\)
\(x=\dfrac{7}{10}-\dfrac{3}{7}\)
\(x=\dfrac{19}{70}\)
\(c,19-x=\dfrac{17}{20}\)
\(x=19-\dfrac{17}{20}\)
\(x=\dfrac{363}{20}\)
1.Tìm x
a) 9/2 - x = 3/7 b) x : 5/7 = 7/5 c) x x 3/8 = 11/3
a: x=9/2-3/7=57/14
b: =>x=7/5x5/7=1
c: =>x=11/3:3/8=11/3x8/3=88/9
a : x = \(\dfrac{9}{2}\) - \(\dfrac{3}{7}\) = \(\dfrac{57}{14}\)
b : = > x = \(\dfrac{7}{5}\) x\(\dfrac{5}{7}\) = 1
c : = > \(\dfrac{11}{3}\) : \(\dfrac{3}{8}\) = \(\dfrac{11}{3}\) x \(\dfrac{8}{3}\) = \(\dfrac{88}{9}\)
tìm x
a)(x-8)(x^3+8)=0
b)(4x-3)-(x+5)=3(10-x)
giúp mình với ạ đang cần gấp ạ
\(a,\Leftrightarrow\left[{}\begin{matrix}x-8=0\\x^3+8=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=8\\x^3=-8\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=8\\x=-2\end{matrix}\right.\\ b,\Leftrightarrow4x-3-x-5=30-3x\\ \Leftrightarrow4x-x+3x=30+5+3\\ \Leftrightarrow6x=38\\ \Leftrightarrow x=\dfrac{19}{3}\)
Tìm X
a)8/X+1/5=2/5+1/3
B)(X-3/5):1/5=5/8
ÉT Ô ÉT
a) \(\dfrac{8}{x}+\dfrac{1}{5}=\dfrac{2}{5}+\dfrac{1}{3}=\dfrac{11}{15}\)
\(\dfrac{8}{x}=\dfrac{11}{15}-\dfrac{1}{5}=\dfrac{8}{15}\)
\(x=\dfrac{8\times15}{8}=15\)
B) \(\left(x-\dfrac{3}{5}\right)=\dfrac{5}{8}\times\dfrac{1}{5}=\dfrac{1}{8}\)
\(x=\dfrac{1}{8}+\dfrac{3}{5}=\dfrac{29}{40}\)