5 x 3\(^n\) + 2 - 32 x 3\(^n\) = 13
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5 x 3^n + 2 - 32 x 3^n = 13
Giúp mình nhé! Mình cần gấp. Cho mình cảm ơn trước!
tim x thuoc n biet : b,(149 nhan 35 : x + 5) nhan 17 =13 va d/(3 nhan x tru 3 ) binh phuong 3 =2 nhan 32 e/5 x+1-5x=500
Bài 1:tìm x,y thuộc N biết 3^x+4^y=5^x
Bài 2:so sánh (-32)^9 và (-18)^13
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tìm n thuộc N biết :
a)3.5^n+2+4.5^n-3=19.5^10
b)11.6^x-1+2.6^x-1=11.6^11+2.6^13
c)\(\frac{2^{4-x}}{16^5}=32^6\)
a)C=1+5+5^2+5^3+...+5^2018. Tìm x E N để c+1=5^x
b)Tìm x E N để: 5^x +323=b^2
c)Chứng minh rằng: ab+ba chia hết cho 11 và 64^10 - 32^11-16^13 chia hết cho 49
d) Tìm x,y E N để: 1!+2!+3!+....+x!=y^2
c. Có \(\overline{ab}+\overline{ba}=10a+b+10b+a\)
\(=\left(10a+a\right)+\left(10b+b\right)\)
\(=11a+11b\)
\(=11.\left(a+b\right)\)
Ta thấy \(11.\left(a+b\right)⋮11\)
Vậy \(\overline{ab}+\overline{ba}⋮11\left(dpcm\right)\)
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a: \(5C=5+5^2+5^3+...+5^{2018}\)
\(\Leftrightarrow4C=5^{2018}-1\)
\(\Leftrightarrow C=\dfrac{5^{2018}-1}{4}\)
\(\Leftrightarrow5^x-1=\dfrac{5^{2018}-1}{4}\)
\(\Leftrightarrow5^x=\dfrac{5^{2018}+3}{4}\)(vô lý)
c: \(64^{10}-32^{11}-16^{13}\)
\(=2^{60}-2^{55}-2^{52}\)
\(=2^{52}\left(2^8-2^3-1\right)\)
\(=2^{52}\cdot247⋮̸49\)
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Tìm số tự nhiên x,biết :
1/x^n=1(n e N *)
2/x^n=0(n eN *)
3/x ^n=1(n e N*)
4/x^n=9
5/3^x=9
6/x^4=1
7/5^x=25
8/5^x=125
9/2^x=4
10/2^x=8
11/2^x=16
12/2^x=2^2
13/2^x=1
14/3^x=81
15/3^x=27
16/3^0=x
17/x=7^0
18/x^5=32
19/x^3=27
20/4^x=64
các bạn giải giùm mình nha ,nếu giúp được thì các bạn sẽ giải hết bài cho mình nha.bạn nào làm được hết mình sẽ tích đúng cho luôn.mình cần bài này trong 3 tiếng nữa .
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1. Thực hiện phép tính (tính hợp lý nếu có thể):
a) (-32).43+(-32).65-(-32).8
b) (-43).25+25.(-19)+25.(-38)
c) (-26).13+86.(-26)+(-26)
d) (-17).39+(-17)+(-17).60
2. Tìm số nguyên x, biết:
a) x+5+2.x17
b) x-112.x+4
c) (3-x).(x+5)0
d) (2.x+2).(x-19)0
e) (x+2)3(-125)
f) |x-3|4
g) 2.|7-x|16
h) 12-2.|x-10|(-18)
3. Tìm số nguyên x, biết:
a) 5/8x/16
b) x/61/(-3)
c) x+1/320/(-12)
d) 4/5(-12)/9-x
e) x/28/x
f) -x/3(-12)/x
g) 5/7 -2x/14
h) 5-x/22/5-x
4. Tìm các số nguyên x, y, biế...
Đọc tiếp
1. Thực hiện phép tính (tính hợp lý nếu có thể):
a) (-32).43+(-32).65-(-32).8
b) (-43).25+25.(-19)+25.(-38)
c) (-26).13+86.(-26)+(-26)
d) (-17).39+(-17)+(-17).60
2. Tìm số nguyên x, biết:
a) x+5+2.x=17
b) x-11=2.x+4
c) (3-x).(x+5)=0
d) (2.x+2).(x-19)=0
e) (x+2)3=(-125)
f) |x-3|=4
g) 2.|7-x|=16
h) 12-2.|x-10|=(-18)
3. Tìm số nguyên x, biết:
a) 5/8=x/16
b) x/6=1/(-3)
c) x+1/3=20/(-12)
d) 4/5=(-12)/9-x
e) x/2=8/x
f) -x/3=(-12)/x
g) 5/7= -2x/14
h) 5-x/2=2/5-x
4. Tìm các số nguyên x, y, biết:
a) (x-2).(y+1)=5
b) (3-x).(2.y+5)=4
c) x-x.y-y=2
5. Tìm số nguyên n, biết:
a) n+5 ⋮ n-1
b) 2.n-3 ⋮ n+4
c) 3.n+4 ⋮ 2.n-1
ban chia ra tung bai di dai lam
bai nao lam dc thi giam di nhe
Bài 4:
a) \(\left(x-2\right)\left(y+1\right)=5\)
\(\Leftrightarrow x-2;y+1\inƯ\left(5\right)\)
\(\Leftrightarrow x-2;y+1\in\left\{1;-1;5;-5\right\}\)
*Trường hợp 1:
\(\left\{{}\begin{matrix}x-2=1\\y+1=5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=3\\y=4\end{matrix}\right.\)(thỏa mãn)
*Trường hợp 2:
\(\left\{{}\begin{matrix}x-2=5\\y+1=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=7\\y=0\end{matrix}\right.\)(thỏa mãn)
*Trường hợp 3:
\(\left\{{}\begin{matrix}x-2=-1\\y+1=-5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\y=-6\end{matrix}\right.\)(thỏa mãn)
*Trường hợp 4:
\(\left\{{}\begin{matrix}x-2=-5\\y+1=-1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-3\\y=-2\end{matrix}\right.\)(thỏa mãn)
Vậy: x∈{3;7;1;-3} và y∈{4;0;-6;-2}
b) (3-x)*(2y+5)=4
\(\Leftrightarrow3-x;2y+5\inƯ\left(4\right)\)
\(\Leftrightarrow3-x;2y+5\in\left\{1;-1;2;-2;4;-4\right\}\)
*Trường hợp 1:
\(\left\{{}\begin{matrix}3-x=1\\2y+5=4\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\2y=-1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=-\frac{1}{2}\end{matrix}\right.\)(loại)
*Trường hợp 2:
\(\left\{{}\begin{matrix}3-x=4\\2y+5=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-1\\2y=-4\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-1\\y=-2\end{matrix}\right.\)
*Trường hợp 3:
\(\left\{{}\begin{matrix}3-x=-1\\2y+5=-4\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=4\\2y=-9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=4\\y=\frac{-9}{2}\end{matrix}\right.\)(loại)
*Trường hợp 4:
\(\left\{{}\begin{matrix}3-x=-4\\2y+5=-1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=7\\2y=-6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=7\\y=-3\end{matrix}\right.\)
*Trường hợp 5:
\(\left\{{}\begin{matrix}3-x=2\\2y+5=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\2y=-3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\y=\frac{-3}{2}\end{matrix}\right.\)(loại)
*Trường hợp 6:
\(\left\{{}\begin{matrix}3-x=-2\\2y+5=-2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=5\\2y=-7\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=5\\y=\frac{-7}{2}\end{matrix}\right.\)(loại)
Vậy: x∈{-1;7} và y∈{-2;-3}
Bài 5:
a) Ta có: \(n+5⋮n-1\)
\(\Leftrightarrow5⋮n-1\)
\(\Leftrightarrow n-1\inƯ\left(5\right)\)
\(\Leftrightarrow n-1\in\left\{1;-1;5;-5\right\}\)
\(\Leftrightarrow n\in\left\{2;0;6;-4\right\}\)(thỏa mãn)
Vậy: \(n\in\left\{2;0;6;-4\right\}\)
b) Ta có: \(2n-3⋮n+4\)
\(\Leftrightarrow-3⋮n+4\)
\(\Leftrightarrow n+4\inƯ\left(-3\right)\)
\(\Leftrightarrow n+4\in\left\{1;-1;3;-3\right\}\)
\(\Leftrightarrow n\in\left\{-3;-5;-1;-7\right\}\)(thỏa mãn)
Vậy: \(n\in\left\{-3;-5;-1;-7\right\}\)
c) Ta có: 3n+4⋮2n-1
\(\Leftrightarrow4⋮2n-1\)
\(\Leftrightarrow2n-1\inƯ\left(4\right)\)
\(\Leftrightarrow2n-1\in\left\{1;-1;2;-2;4;-4\right\}\)
\(\Leftrightarrow2n\in\left\{2;0;3;-1;5;-3\right\}\)
\(\Leftrightarrow n\in\left\{1;0;\frac{3}{2};\frac{-1}{2};\frac{5}{2};\frac{-3}{2}\right\}\)
Vì n∈Z
nên n∈{1;0}
Vậy: n∈{1;0}
tính nhanh
4/5-2/3/+1/5-1/3
2/5 x 7/4 - 2/5x3/7
13/4 x 2/3 x 4/13 x 3/12
75/100 + 18/21 + 19/32 +1/4 + 3/21 + 13/32
2/5 + 6/9+3/4+3/5+1/3+1/4
Bài giải
a, \(\frac{4}{5}-\frac{2}{3}+\frac{1}{5}-\frac{1}{3}\)
\(=\left(\frac{4}{5}+\frac{1}{5}\right)-\left(\frac{2}{3}+\frac{1}{3}\right)=1-1=0\)
b, \(\frac{2}{5}\text{ x }\frac{7}{4}-\frac{2}{5}\text{ x }\frac{3}{7}\)
\(=\frac{2}{5}\text{ x }\left(\frac{7}{4}-\frac{3}{7}\right)=\frac{2}{5}\text{ x }\frac{37}{28}=\frac{37}{70}\)
c, \(\frac{13}{4}\text{ x }\frac{2}{3}\text{ x }\frac{4}{13}\text{ x }\frac{3}{12}=\frac{13\text{ x }2\text{ x }4\text{ x }3}{4\text{ x }3\text{ x }13\text{ x }12}=\frac{1}{6}\)
d, \(\frac{75}{100}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\frac{3}{4}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{18}{21}+\frac{3}{21}\right)+\left(\frac{19}{32}+\frac{13}{32}\right)\)
\(=1+1+1\)
\(=3\)
e, \(\frac{2}{5}+\frac{6}{9}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{2}{5}+\frac{2}{3}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{1}{5}\left(2+3\right)+\frac{1}{3}\left(2+1\right)+\frac{1}{4}\left(3+1\right)\)
\(=\frac{1}{5}\cdot5+\frac{1}{3}\cdot3+\frac{1}{4}\cdot4\)
\(=1+1+1\)
\(=3\)
a, \(\frac{4}{5}-\frac{2}{3}+\frac{1}{5}-\frac{1}{3}\)
\(=\left(\frac{4}{5}+\frac{1}{5}\right)-\left(\frac{2}{3}+\frac{1}{3}\right)=1-1=0\)
b, \(\frac{2}{5}\text{ x }\frac{7}{4}-\frac{2}{5}\text{ x }\frac{3}{7}\)
\(=\frac{2}{5}\text{ x }\left(\frac{7}{4}-\frac{3}{7}\right)=\frac{2}{5}\text{ x }\frac{37}{28}=\frac{37}{70}\)
c, \(\frac{13}{4}\text{ x }\frac{2}{3}\text{ x }\frac{4}{13}\text{ x }\frac{3}{12}=\frac{13\text{ x }2\text{ x }4\text{ x }3}{4\text{ x }3\text{ x }13\text{ x }12}=\frac{1}{6}\)
d, \(\frac{75}{100}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\frac{3}{4}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{18}{21}+\frac{3}{21}\right)+\left(\frac{19}{32}+\frac{13}{32}\right)\)
\(=1+1+1\)
\(=3\)
e, \(\frac{2}{5}+\frac{6}{9}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{2}{5}+\frac{2}{3}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{1}{5}\left(2+3\right)+\frac{1}{3}\left(2+1\right)+\frac{1}{4}\left(3+1\right)\)
\(=\frac{1}{5}\cdot5+\frac{1}{3}\cdot3+\frac{1}{4}\cdot4\)
\(=1+1+1\)
\(=3\)
a , =(4/5+1/5)-(2/3+1/3)=1-1=0
b , =2/5 x (7/4-3/7) =2/5 x 37/28 =74/140=37/70
c, =13/4 x 2/3 x 13/4 x 2/3=26/12 x 26/12= 13/6 x 13/6 =13 x 13/6 x 6(gạch 13 trên tử thì tử còn 1 x 13,mẫu hết.) =1 x 13/1=13
d, =3/4+6/7+19/32 +1/4+1/7 +13/32=(3/4+1/4 )+(6/7+1/7)+(19/32+13/32)=1+1+1=3
e, =(2/5+3/5)+(2/3+1/3)+(3/4+1/4) [6/9 rút gọn thành 2/3] =1+1+1=3
Tìm x
a) x-6/7 + x-7/8 + x-8/9 = x-9/10 + x-10/11+x-11/12
b) x+32/11 + x+23/12 = x+38/13 + x+27/14
c) | x-2| = 13
d) 3|x-2| + |4x-8| = |-2| - |1/3|
e) |3x-2|+5^-1 = 3 + | x- (2/3) |
f) | x+2 | + | x-2 | = 3
g) (2x-1)^2 - 5 = 20
i) (x+2)^2 = 1/2 - 1/3
k) (x-1)^3 = (x-1)
m) (x-1)^x+2 = (x-1)^2
n) (x+3)^y+1 = (2x-1)^y+1 vs y là 1 số tự nhiên .
a: \(\dfrac{x-6}{7}+\dfrac{x-7}{8}+\dfrac{x-8}{9}=\dfrac{x-9}{10}+\dfrac{x-10}{11}+\dfrac{x-11}{12}\)
\(\Leftrightarrow\left(\dfrac{x-6}{7}+1\right)+\left(\dfrac{x-7}{8}+1\right)+\left(\dfrac{x-8}{9}+1\right)=\left(\dfrac{x-9}{10}+1\right)+\left(\dfrac{x-10}{11}+1\right)+\left(\dfrac{x-11}{12}+1\right)\)
=>x+1=0
hay x=-1
c: |x-2|=13
=>x-2=13 hoặc x-2=-13
=>x=15 hoặc x=-11
d: \(\Leftrightarrow3\left|x-2\right|+4\left|x-2\right|=2-\dfrac{1}{3}=\dfrac{5}{3}\)
=>7|x-2|=5/3
=>|x-2|=5/21
=>x-2=5/21 hoặc x-2=-5/21
=>x=47/21 hoặc x=37/21
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