bài 1 : Tìm x\(\varepsilon\)Z
a) (2x-7)+16=-21
b) (x+1)+(x+2)+(x+3)+...+(x+50)=1625
Tìm x ∈ Z, biết:
a) (2x - 7) + 16= -21
b) 72 - 3 (5 - x)= 108
c) (x - 11)3 + 32 . 5= 3
d) (x + 1) + (x+2) + (x+3) +.....+ (x+50)= 1625
giúp mình với!!
a) (2x - 7) + 16= -21
=> 2x - 7 = -21 - 16 = (-21) + (-16)
=> 2x - 7 = -37
=> 2x = -37 + 7 = -30
=> x = -30 : 2 = -15
b) 72 - 3 (5 - x) = 108
=> 3. (5 - x) = 72 - 108 = -36
=> 5 - x = -36 : 3 = -12
=> x = 5 - (-12) = 5 + 12
=> x = 17
d) (x + 1) + (x + 2) + (x + 3) +.....+ (x + 50) = 1625
=> x + 1 + x + 2 + x + 3 +....+x + 50 = 1625
=> (x + x + x + .... + x) + (1 + 2 + 3 + .... + 50) = 1625
Từ 1 → 50 có: (50 - 1) + 1 = 50 (số hạng)
=> Có 50 x
Ta có: (x + x + x + .... + x) + (1 + 2 + 3 + .... + 50) = 1625
=> 50. x + (1 + 2 + 3 + .... + 50) = 1625
Tổng các số từ 1 → 50: (50 + 1). 50 = 2550
=> 50. x + 2550 = 1625
=> 50. x = 1625 - 2550 = -925
=> x = (-925) : 50 = \(-\frac{37}{2}\)
P/s: Ko chắc!
\(\text{a) }\left(2x-7\right)+16=-21\)
\(\Leftrightarrow2x-7+16=-21\)
\(\Leftrightarrow2x=-30\)
\(\Rightarrow x=-15\)
\(\text{b) }72-3\left(5-x\right)=108\)
\(\Leftrightarrow3\left(5-x\right)=-36\)
\(\Leftrightarrow5-x=-12\)
\(\Rightarrow x=17\)
\(\text{d) }\left(x+1\right)+\left(x+2\right)+...+\left(x+50\right)=1625\)
\(\Leftrightarrow50x+1275=1625\)
\(\Rightarrow x=7\)
b1 tìm x ,biết
(x-14)-20=5
128+(202-x)=330
(x-120)*9=450
x-320:32=25*16
25-(2x+10)=5
315-(135-x)=215
x:2+21:3=37
4*(x+100)=800
504:(16-5x)=72
(x-5):7+3=20
mik cảm ơn nhaa
(x-14)-20=5
=> x-14 = 25
=> x = 39
Các dạng toán như này lớp 6 ai cũng làm được cả * lười vừa thôi*
( x - 14 ) - 20 = 5
x - 14 = 5 + 20
x - 14 = 25
x = 25 + 14
x = 39
128 + ( 202 - x ) = 330
[ 202 - x ] = 330 - 128
202 - x = 202
x = 202 - 202
x = 0
( x - 120 ) x 9 = 450
[ x - 120 ] = 450 : 9
x - 120 = 50
x = 50 + 120
x = 170
x - 320 : 32 = 25 x 16
x - 320 : 32 = 400
x - 320 = 400 x 32
x - 320 = 12800
x = 12800 + 320
x = 13120
25 - ( 2x +10 ) = 5
[ 2x + 10] = 25 - 5
2x + 10 = 20
2x = 20 - 10
2x = 10
x = 10 : 2
x = 5
315 - ( 135 - x ) = 215
[ 135 - x ] = 315 - 215
[ 135 - x ] = 100
x = 135 - 100
x = 35
x : 2 + 21 : 3 = 37
x : 2 + 21 = 37 x 3
x : 2 + 21 = 111
x : 2 = 111 - 21
x : 2 = 90
x = 90 x 2
x = 180
4 x ( x + 100 ) = 800
[ x + 100 ] = 800 : 4
[ x + 100 ] = 200
x = 200 - 100
x = 100
504 : ( 16 - 5x ) = 72
[ 16 - 5x ] = 504 : 72
[ 16 - 5x ] = 7
5x = 16 - 7
5x = 9
x = \(\dfrac{9}{5}\)
( x - 5 ) : 7 + 3 = 20
[ x - 5 ] : 7 = 20 - 3
[ x - 5 ] : 7 = 17
[ x - 5 ] = 17 x 7
x - 5 = 119
x = 119 + 5
x = 124
Bài 1:Tìm x thuộc Z
a) -12.(x-5)
b)30.(x+2)-6(x-5)-24x=100
c)(x-7).(x+3)<0
d) -1<2X-1<4
giúp tui với đúng tick luôn nhoa
a: Bạn ghi lại đề nha bạn
b: \(30\left(x+2\right)-6\left(x-5\right)-24x=100\)
=>\(30x+60-6x+30-24x=100\)
=>\(\left(30x-6x-24x\right)+\left(60+30\right)=100\)
=>0x=100-90=10(vô lý)
c: \(\left(x-7\right)\left(x+3\right)< 0\)
TH1: \(\left\{{}\begin{matrix}x-7>0\\x+3< 0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x>7\\x< -3\end{matrix}\right.\)
=>\(x\in\varnothing\)
TH2: \(\left\{{}\begin{matrix}x-7< 0\\x+3>0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x< 7\\x>-3\end{matrix}\right.\)
=>-3<x<7
mà x nguyên
nên \(x\in\left\{-2;-1;0;1;2;3;4;5;6\right\}\)
d: -1<2x-1<4
=>\(-1+1< 2x< 4+1\)
=>0<2x<5
=>0<x<2,5
mà x nguyên
nên \(x\in\left\{1;2\right\}\)
bài 1: tìm x thuộc Z
a) 10-x-5=(-5)-7-11
b) (x-3)-(x+17-24)-(25-x)=24-(-30)
c) (7-9x)-(2x-4)=-(5.x+35)-(-27)-(+25)
a: =>5-x=-23
=>x=5+23=28
b: =>x-3-x+7-25+x=54
=>x-21=54
=>x=75
c: =>7-9x-2x+4=-5x-35+27-25=-5x-37
=>-11x+3=-5x-37
=>-6x=-40
=>x=20/3
a) \(10-x-5=\left(-5\right)-7-11\)
\(\Rightarrow5-x=-23\)
\(\Rightarrow x=5+23\)
\(\Rightarrow x=28\)
b) \(\left(x-3\right)-\left(x+17-24\right)-\left(25-x\right)=24-\left(-30\right)\)
\(\Rightarrow x-3-x-17+24-25+x=54\)
\(\Rightarrow x-21=54\)
\(\Rightarrow x=54+21\)
\(\Rightarrow x=75\)
c) \(\left(7-9x\right)-\left(2x-4\right)=-\left(5x+35\right)-\left(-27\right)-25\)
\(\Rightarrow7-9x-2x+4=-5x-35+27-25\)
\(\Rightarrow11-11x=-5x-33\)
\(\Rightarrow-11x+5x=-33-11\)
\(\Rightarrow-6x=-22\)
\(\Rightarrow x=\dfrac{22}{6}=\dfrac{11}{3}\)
a.
10-x-5 = (-5) - 7 -11
=>5-x = 0
=>x=5
b
(x-3) - (x+17-24) - (25-x) = 24 - (-30)
=>x - 3 - x - 17 + 24 - 25 - x = 24 + 30
=>-x - 21 = 54
=>-x = 75
=>x = -75
c
(7 - 9x) - (2x - 4) = - (5x + 35) - (-27) - 25
=>7-9x - 2x + 4 = -5x - 35 + 27 - 35
=>11 - 11x + 5x = -43
=>16x = 11 + 43
=>16x = 54
=>x=4
2 . ( x³ -1)-2x²(x+2x⁴) +(4x⁵+4)x=6. 3. (X²-4x+16)(x+4)-x(x+1)(x+2)+3x²= 0 4 . ( 8x +2 ) (1-3x) + ( 6x-1)(4x-10) =-50 Đề bài là tìm x nha mn Nhanh giúp mik vs
2:
=>x^3-1-2x^3-4x^6+4x^6+4x=6
=>-x^3+4x-7=0
=>x=-2,59
4: =>8x-24x^2+2-6x+24x^2-60x-4x+10=-50
=>-62x+12=-50
=>x=1
Bài 2: Tìm x biết:
1,x\(^2\)+4x+4=25
2,(5-2x)\(^2\)-16=0
3,(x-3)\(^3\)-(x-3)(x\(^2\)+3x+9)+9(x+1)\(^2\)=15
4,3(x+2)\(^2\)+(2x-1)\(^2\)-7(x-3)9x+3)=36
5,(x-3)(x\(^2\)+3x+9)+x(x+2)(2-x)=1
6,(2x+1)\(^2\)-4(x+2)\(^2\)=9
7,(x+3)\(^{^{ }2}\)-(x-4)(x+8)=1
1: =>x^2+4x-21=0
=>(x+7)(x-3)=0
=>x=3 hoặc x=-7
2: =>(2x-5-4)(2x-5+4)=0
=>(2x-9)(2x-1)=0
=>x=9/2 hoặc x=1/2
3: =>x^3-9x^2+27x-27-x^3+27+9(x^2+2x+1)=15
=>-9x^2+27x+9x^2+18x+9=15
=>18x=15-9-27=-21
=>x=-7/6
6: =>4x^2+4x+1-4x^2-16x-16=9
=>-12x-15=9
=>-12x=24
=>x=-2
7: =>x^2+6x+9-x^2-4x+32=1
=>2x+41=1
=>2x=-40
=>x=-20
Bài 1: Tìm x :
a. ( x + 4 )2 - ( x + 1 ) ( x - 1 ) = 16
b. ( 2x - 1 )2 + ( x + 3 )2 - 5 ( x + 7 ) ( x - 7 ) = 0
c. ( x - 2 )3 - ( x - 3 ) ( x2 + 3x + 9 ) + 6 ( x + 1 )2 = 49
Bài 1: Tìm x :
a. ( x + 4 )2 - ( x + 1 ) ( x - 1 ) = 16
b. ( 2x - 1 )2 + ( x + 3 )2 - 5 ( x + 7 ) ( x - 7 ) = 0
c. ( x - 2 )3 - ( x - 3 ) ( x2 + 3x + 9 ) + 6 ( x + 1 )2 = 49
a) 2x - 261 = -21
b) 15 . (-2) - x = 45
c) -18 + ( 7 - x)^2 = -2
d) ( 2x - 1 ) chia hết ( x +1)
a: 2x-261=-21
=>\(2x=-21+261=240\)
=>\(x=\dfrac{240}{2}=120\)
b: \(15\cdot\left(-2\right)-x=45\)
=>-30-x=45
=>x=-30-45=-75
c: \(-18+\left(7-x\right)^2=-2\)
=>\(\left(x-7\right)^2-18=-2\)
=>\(\left(x-7\right)^2=-2+18=16\)
=>\(\left[{}\begin{matrix}x-7=4\\x-7=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=11\\x=3\end{matrix}\right.\)
d: \(2x-1⋮x+1\)
=>\(2x+2-3⋮x+1\)
=>\(-3⋮x+1\)
=>\(x+1\inƯ\left(-3\right)\)
=>\(x+1\in\left\{1;-1;3;-3\right\}\)
=>\(x\in\left\{0;-2;2;-4\right\}\)