\(C_2H_4 + H_2O \xrightarrow{t^o,xt} C_2H_5OH\\ CH_3COONa + HCl \to CH_3COOH + NaCl\\ CH_3COOH + C_2H_5OH \buildrel{{H_2SO_4,t^o}}\over\rightleftharpoons CH_3COOC_2H_5 + H_2O\\ \)

a) CaCO₃ = CaO + CO₂

CaCO₃ → CaO + CO₂

Áp dụng ĐLBTKL, ta có:

\(m_{CaCO_3}=m_{CaO}+m_{CO_2}\)

\(m_{CaO}=56kg\)

\(m_{CO_2}=44kg\)

\(\Rightarrow m_{CaCO_3}=56+44=100kg\)

\(m_{\text{đ}\text{á}v\text{ô}i}=100\div95\%=105,26kg\)

Ta có

a, CaCO₃  CaO + CO₂

=> m_CaO + m_CO2 = m_CaCO3

=> m_CaCO3 = 25 ( kg )

b, m_{đá vôi} = 25 : 80 . 100 = 31,25 ( kg )

Nước `+` Carbondioxide \(-\rightarrow^{A'sang}_{D.luc}\)  Glucose + Oxygen

Axit+quỳ tím->Đỏ

Axit+Bazo->Muối +H2O

Axit+Muối->Muối mới+Axit mới

Axit+kim loại->Muối +H2

\(Na+\dfrac{1}{2}Cl_2\underrightarrow{t^o}NaCl\)

\(NaCl_{tinhthe}+H_2SO_{4\left(đ\right)}\underrightarrow{t^o}NaHSO_4+HCl\)

\(Ca\left(OH\right)_2+2HCl\rightarrow CaCl_2+2H_2O\)

\(CaCl_2+2AgNO_3\rightarrow Ca\left(NO_3\right)_2+2AgCl_{\downarrow}\)

(1) Fe 2 O 3  + 6HCl → 2 FeCl 3  + 3 H 2 O

(2)  Fe 2 O 3  +  H 2  → 2Fe + 3 H 2 O

(3) 2Fe + 3 Cl 2  → 2 FeCl 3

(4) Fe + 2HCl →  FeCl 2  +  H 2