A= \(\frac{\left(81,624:\frac{16}{3}-4,505\right)^2+125.\frac{3}{4}}{\left\{\left[\left(\frac{11}{25}\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:\frac{13}{25}}\) B= \(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
Những câu hỏi liên quan
\(B=\frac{\left(81,624:4\frac{4}{3}-4,505\right)^2+125\frac{3}{4}}{\left\{\left[\left(\frac{11}{25}\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}.\frac{13}{25}}\)
\(\frac{\left(81,624:4\frac{4}{3}-4,505\right)^2+125\frac{3}{4}}{\left(\left(\left(\frac{11}{25}\right)^2:0,88+3,53\right)^2-\left(2,75\right)^2\right):\frac{13}{25}}\)
Tính giá trị của biểu thức
\(A=\frac{\left(81,624:4\frac{4}{3}-4,505\right)^2+125\frac{3}{4}}{\left\{\left[\left(\frac{11}{25}\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:\frac{13}{25}}\)
Tính giá trị biểu thức :
\(A=\frac{\left(81,624:4\frac{4}{3}-4,505\right)^2+125\frac{3}{4}}{\left\{\left[\left(\frac{11}{25}:0,88+3,53\right)\right]^2-\left(2,75\right)^2\right\}:\frac{13}{25}}\)
Tính giá trị biểu thức:
\(A=\frac{\left(81,624:4\frac{4}{3}-4,505\right)^2+125\frac{3}{4}}{\left\{\left[\left(\frac{11}{25}\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:\frac{13}{25}}\)
Help meeeee, chiều là tui cần gấp rùi T.T'''
\(\frac{\left(81,624:4\frac{4}{3}-4,505\right)+125\frac{3}{4}}{\left(\left(\left(\frac{11}{25}\right)^2:0,08+3,53\right)^2-\left(2,75^2\right)\right):\frac{13}{25}}\)
\(\frac{\left(81,624:4\frac{4}{3}-4,505\right)+125\frac{3}{4}}{\left[\left(\left(\frac{11}{25}\right)^2:0,08+3,53\right)^2-\left(2,75\right)^2\right]:\frac{13}{25}}\)
\(=\frac{\left(\frac{10203}{125}.\frac{3}{16}-\frac{901}{200}\right)+\frac{503}{4}}{\left[\left(\frac{121}{625}.\frac{25}{2}+\frac{353}{100}\right)^2-\frac{121}{16}\right].\frac{25}{13}}\)
\(=\frac{\left(15,3045-\frac{901}{200}\right)+\frac{503}{4}}{\left(\frac{14161}{400}-\frac{121}{16}\right).\frac{25}{13}}\)
\(=\frac{136,5495}{\frac{696}{13}}\)
\(=2,550493534\)
Tính giá trị biểu thức :
\(\frac{\left(81,624:4\frac{4}{3}-4.505\right)^2+125\frac{3}{4}}{\left\{\left[\left(\frac{11}{25}\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:\frac{13}{25}}\)
@Nguyễn Ngọc Lộc help me
a) \(A=\frac{\left(81,624:4\frac{4}{3}-4,505\right)^2+125\frac{3}{4}}{\left\{\left[\left(\frac{11}{25}\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:\frac{13}{25}}\)
b) Cho \(x-y=7\) Tính giá trị biểu thức: \(B=\frac{3x-7}{2x+y}-\frac{3y+7}{2y+x}\)
13 tháng 3 2020 lúc 20:02
Tính giá trị biểu thức sau:
Bleft(18frac{1}{3}:sqrt{225}+8frac{2}{3}.sqrt{frac{49}{4}}right):left[left(12frac{1}{3}+8frac{6}{7}right)-frac{left(sqrt{7}right)^2}{left(3.sqrt{2}right)^2}right]:frac{1704}{445}
Cfrac{left(81,624:4frac{4}{3}-4,505right)^2+125frac{3}{4}}{left{left[left(frac{11}{25}right)^2:0,88+3,53right]^2-left(2,75right)^2right}:frac{13}{25}}
P/s: Giúp mik với ạ! Nguyễn Văn Đạt ; @Vũ Minh Tuấn; @Phạm Thị Diệu Huyền; ..........
Đọc tiếp
Tính giá trị biểu thức sau:
\(B=\left(18\frac{1}{3}:\sqrt{225}+8\frac{2}{3}.\sqrt{\frac{49}{4}}\right):\left[\left(12\frac{1}{3}+8\frac{6}{7}\right)-\frac{\left(\sqrt{7}\right)^2}{\left(3.\sqrt{2}\right)^2}\right]:\frac{1704}{445}\)
\(C=\frac{\left(81,624:4\frac{4}{3}-4,505\right)^2+125\frac{3}{4}}{\left\{\left[\left(\frac{11}{25}\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:\frac{13}{25}}\)
P/s: Giúp mik với ạ! Nguyễn Văn Đạt ; @Vũ Minh Tuấn; @Phạm Thị Diệu Huyền; ..........
\(B=\left(\frac{55}{3}:15+\frac{26}{3}.\frac{7}{2}\right):\left[\left(\frac{37}{3}+\frac{62}{7}\right)-\frac{7}{8}\right]:\frac{1704}{445}\\ B=\left(\frac{11}{9}+\frac{91}{3}\right):\left(\frac{445}{21}-\frac{7}{8}\right):\frac{1704}{445}\\ B=\frac{284}{9}:\frac{2621}{126}:\frac{1704}{445}\\ B=\frac{35784}{23589}:\frac{1704}{445}\\ B=\frac{3115}{7863}\)