\(2^x+2^{x+2}+2^{x+4}=1024\)

=>\(2^x\left(1+2^2+2^4\right)=1024\)

=>\(2^x=\dfrac{1024}{21}\)

=>\(x=log_2\left(\dfrac{1024}{21}\right)\)

\(2^x+2^{x+2}+2^{x+4}=1024\\\Rightarrow 2^x+2^x\cdot2^2+2^x\cdot2^4=1024\\\Rightarrow 2^x\cdot(1+2^2+2^4)=1024\\\Rightarrow 2^x\cdot(1+4+16)=1024\\\Rightarrow 2^x\cdot21=1024\\\Rightarrow 2^x=\dfrac{1024}{21}\)

\(\Rightarrow \) Bạn xem lại đề bài!

\(\dfrac{x}{1024}=\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{8}-\dfrac{1}{16}+...-\dfrac{1}{1024}\)

\(\dfrac{2x}{1024}=1-\dfrac{1}{2}+\dfrac{1}{4}-\dfrac{1}{8}+...-\dfrac{1}{512}\)

\(\Rightarrow\dfrac{x}{1024}+\dfrac{2x}{1024}=1-\dfrac{1}{1024}\)

\(\Rightarrow\dfrac{3x}{1024}=\dfrac{1023}{1024}\)

\(\Rightarrow3x=1023\)

\(\Rightarrow x=341\)

Lời giải:

$\frac{x}{1024}=\frac{1}{2}-\frac{1}{4}+\frac{1}{8}-\frac{1}{16}+...-\frac{1}{1024}$

$\frac{2x}{1024}=1-\frac{1}{2}+\frac{1}{4}-\frac{1}{8}+...-\frac{512}$

$\Rightarrow \frac{x}{1024}+\frac{2x}{1024}=1-\frac{1}{1024}$

$\frac{3x}{1024}=\frac{1023}{1024}$

$\Rightarrow 3x=1023$

$\Rightarrow x=341$

\((-2)^{x+1}+(-2)^x=-1024\\\Rightarrow (-2)^x\cdot2+(-2)^x=-1024\\\Rightarrow(-2)^x\cdot(2+1)=-1024\\\Rightarrow (-2)^x\cdot3=-1024\\\Rightarrow(-2)^x=\dfrac{-1024}{3}\)

Bạn xem lại đề nhé!

256 x 6=512 x 3

512 x 3=256 x 6

999 x 2>1000

512 x 5>1024

1024<512 x 5

1024=512 x 2

512=256 x 2

256=128 x 2

128=64 x 2

64=32 x 2

32=16 x 2

Đúng rồi

Khó quá nhở :(( 

Trả lời

1024:17.2⁵+15.2⁵

=1024:[2⁵.(17+15)]

=1024:32.32

=1024

Ko chắc !

Mơn bạn nhìu :3

\(...\Rightarrow2x=16-10\Rightarrow2x=6\Rightarrow x=3\)

\(2^x.16^2=1024\)

\(2^x=1024:16^2\)

\(2^x=1024:256\)

\(2^x=4\)

\(2^x=2^2\)

\(\Rightarrow x=2\)

vay \(x=2\)

2^x . 16² = 1024

\(\Rightarrow\)2^x . 256 = 1024

\(\Rightarrow\)2^x = 1024 : 256 = 4

\(\Rightarrow\)2^x = 2²

\(\Rightarrow\)x = 2