Viết các đa thức sau thành tích:
M=12xz -5xy
N=64^2-49
P=25y^2-16z^2
Q=4-25y^2
R=25x^2-10x+1
O=16-8y+y^2
X=1-6x+9x^2
chuyển đổi đa thức thành tích
a) 6x2 - 3xy
b) 12xz - 5y
c) 64x2 - 49
d) 25y2 - 16z2
e) 4 - 25y2
f) 25x2 - 10x + 1
g) 16 - 8y + y2
h) 1 - 6x + 9x2
\(a,6x^2-3xy=3x\left(2x-y\right)\)
\(b,12xz-5y=y\left(12x-5\right)\)
\(c,64x^2-49=\left(8x\right)^2-7^2=\left(8x-7\right)\left(8x+7\right)\)
\(d,25y^2-16z^2=\left(5y\right)^2-\left(4z\right)^2=\left(5y-4z\right)\left(5y+4z\right)\)
\(e,4-25y^2=2^2-\left(5y\right)^2=\left(2-5y\right)\left(2+5y\right)\)
\(f,25x^2-10x+1=\left(5x\right)^2-5x\cdot2\cdot1+1=\left(5x-1\right)^2\)
\(g,16-8y+y^2=4^2-4\cdot2\cdot y+y^2=\left(4-y\right)^2\)
\(h,1-6x+9x^2=1^2-6\cdot2\cdot x+\left(3x\right)^2=\left(1-3x\right)^2\)
Dùng Hẳng Đẳng Thức, Phân Tích Đa Thức Thành Nhân Tử Chung
a) x\(^2\)-4y\(^2\) d) x\(^2\)-10xy+25y\(^2\)
b) x\(^2\)-9y\(^2\) e) 9x\(^2\)- 6x+1
c) (2x-1)\(^2\)- 4y\(^2\) f) 25x\(^2\)+20x+4
a) \(=x^2-\left(2y\right)^2=\left(x-2y\right)\left(x+2y\right)\)
b) \(=x^2-\left(3y\right)^2=\left(x-3y\right)\left(x+3y\right)\)
c) \(=\left(2x-1\right)^2-\left(2y\right)^2=\left(2x-1-2y\right)\left(2x-1+2y\right)\)
d) \(=x^2-10xy+\left(5y\right)^2=\left(x-5y\right)^2\)
e) \(=\left(3x\right)^2-6x+1=\left(3x-1\right)^2\)
f) \(=\left(5x\right)^2+20x+4=\left(5x+2\right)^2\)
\(a)x^2-4y^2=(x-2y)(x+2y)\\b)x^2-9y^2=(x-3y)(x+3y)\\c)(2x-1)^2-4y^2=(2x-1-2y)(2x-1+2y)\\d) x^2-10xy+25y^2=(x-5y)^2\\e)9x^2-6x+1=(3x-1)^2\\f)25x^2+20x+4=(5x+2)^2\)
viết các đa thức sau thành tích:
x^2-6x+9
25+10x+x^2
1/4a^2+2ab^2+4b^4
1/9-2/3y^4+y8
(3x+2)^2-4
4x^2-25y^2
4x^2-49
8z^3+27
x^3+8y^38y^3-1258x^3-1/8
9/25x^4-1/4
giúp mình với các bạn!!!! mình đang cần gấp!!
\(x^2-6x+9=\left(x-3\right)^2\)
\(25+10x+x^2=\left(5+x\right)^2\)
\(\frac{1}{4}a^2+2ab^2+4b^4=\left(\frac{1}{2}a+2b^2\right)^2\)
\(\frac{1}{9}-\frac{2}{3}y^4+y^8=\left(\frac{1}{3}-y^4\right)^2\)
\(\left(3x+2\right)^2-4=\left(3x+2-2\right)\left(3x+2+2\right)=3x\left(3x+4\right)\)
\(4x^2-25y^2=\left(2x-5y\right)\left(2x+5y\right)\)
\(4x^2-49=\left(2x-7\right)\left(2x+7\right)\)
\(8z^3+27=\left(2z+3\right)\left(4z^2-6z+9\right)\)
\(\frac{9}{25}x^4-\frac{1}{4}=\left(\frac{3}{5}x^2-\frac{1}{2}\right)\left(\frac{3}{5}x^2+\frac{1}{2}\right)\)
1.phân tích đa thức thành nhân tử
a, -25x6-y8+10x3y4=
b, \(\dfrac{1}{4}\)x2-5xy+25y2=
c, (x-5)2-16=
d, 25-(3-x)2=
a) -25x6 - y8 + 10x3y4 = -25x6 + 10x3y4 - y8
= - ( 25x6 - 10x3y4 + y8 )
= - [ ( 5x3 )2 - 2 . 5x3y4 + ( y4 )2 ]
= - ( 5x3 - y4 )2
b) \(\dfrac{1}{4}\)x2 - 5xy + 25y2 = (\(\dfrac{1}{2}\)x)2 - 2 . \(\dfrac{1}{2}\) x . 5y + ( 5y )2
= (\(\dfrac{1}{2}\) x - 5y )2
c) ( x - 5 )2 - 16 = ( x - 5 )2 - 42
= ( x - 5 - 4 ) . ( x - 5 + 4 )
= ( x - 9 ) . ( x - 1 )
d) 25 - ( 3 - x )2 = 52 - ( 3 - x )2
= ( 5 - 3 + x ) . ( 5 + 3 - x )
= ( x + 2 ) . ( 8 - x )
Phân tích các đa thức sau thành nhân tử:
a,36 - 12x + x mũ 2
b,4x mũ 2 + 12x + 9
c,-25x mũ 6 - y mũ 8 + 10x mũ 3 y mũ 4
d,1/4x mũ 2 - 5xy + 25y mũ 2
a) \(36-12x+x^2\) \(=6^2-2.6.x+x^2\)
\(=\left(6-x\right)^2\)
b) \(4x^2+12x+9=\left(2x\right)^2+2.2x.3+3^2\)
\(=\left(2x+3\right)^2\)
c) \(-25x^6-y^8+10x^3y^4=-\left[25x^6-10x^3y^4+y^8\right]\)
\(=-\left[\left(5x^3\right)^2-2.5x^3.y^4+\left(y^4\right)^2\right]\)
\(=-\left(5x^3-y^4\right)^2\)
d) \(\dfrac{1}{4}x^2-5xy+25y^2=\left(\dfrac{1}{2}x\right)^2-2.\dfrac{1}{2}x.5y+\left(5y\right)^2\)
\(=\left(\dfrac{1}{2}x-5y\right)^2\)
Học tốt~~~
Phân tích các đa thức sau thành nhân tử:
a,36 - 12x + x mũ 2
b,4x mũ 2 + 12x + 9
c,-25x mũ 6 - y mũ 8 + 10x mũ 3 y mũ 4
d,1/4x mũ 2 - 5xy + 25y mũ 2
a. \(36-12x+x^2=6^2-2.6.x+x^2=\left(6-x\right)^2\)
b. \(4x^2+12x+9=\left(2x\right)^2+2.2x.3+3^2=\left(2x+3\right)^2\)
c: \(=-\left(25x^6-10x^3y^4+y^8\right)\)
\(=-\left(5x^3-y^4\right)^2\)
d: \(=\left(\dfrac{1}{2}x\right)^2-2\cdot\dfrac{1}{2}x\cdot5y+\left(5y\right)^2=\left(\dfrac{1}{2}x-5y\right)^2\)
'Phân tích đa thức thành nhân tử:
a) 7x3y - 3xyz - 21x2 + 9z
b)4x2-2x-y2-y
c)9x2-25y2-6x +10y
d)(5x-4)2+(16-25x2)+(5x-4).(3x+2)
a) \(7x^3y-3xyz-21x^2+9z\)
\(=7x^2\left(xy-3\right)-3z\left(xy-3\right)\)
\(=\left(7x^2-3z\right)\left(xy-3\right)\)
b) \(4x^2-2x-y^2-y\)
\(=\left[\left(2x\right)^2-y^2\right]-\left(2x+y\right)\)
\(=\left(2x-y\right)\left(2x+y\right)-\left(2x+y\right)\)
\(=\left(2x+y\right)\left(2x-y-1\right)\)
c) \(9x^2-25y^2-6x+10y\)
\(=\left(3x\right)^2-\left(5y\right)^2-2\left(3x-5y\right)\)
\(=\left(3x-5y\right)\left(3x+5y\right)-2\left(3x-5y\right)\)
\(=\left(3x-5y\right)\left(3x+5y-2\right)\)
d) \(\left(5x-4\right)^2+\left(16-25x^2\right)+\left(5x-4\right)\left(3x+2\right)\)
\(=\left(5x-4\right)\left[\left(5x-4\right)+\left(3x+2\right)\right]+\left(4^2-\left(5x\right)^2\right)\)
\(=\left(5x-4\right)\left(8x-2\right)+\left(4-5x\right)\left(4+5x\right)\)
\(=\left(4-5x\right)\left(2-8x\right)+\left(4-5x\right)\left(4+5x\right)\)
\(=\left(4-5x\right)\left[\left(2-8x\right)+\left(4+5x\right)\right]\)
\(=\left(4-5x\right)\left(6-3x\right)\)
'Phân tích đa thức thành nhân tử:
a) 7x3y - 3xyz - 21x2 + 9z
b)4x2-2x-y2-y
c)9x2-25y2-6x +10y
d)(5x-4)2+(16-25x2)+(5x-4).(3x+2)
'Phân tích đa thức thành nhân tử:
a) 7x3y - 3xyz - 21x2 + 9z
b)4x2-2x-y2-y
c)9x2-25y2-6x +10y
d)(5x-4)2+(16-25x2)+(5x-4).(3x+2)
Tham khảo câu hỏi của jisoo nha bạn