a, 26 + 35 + 21 + 18 + 35 + 14 + 10 + 10 + 110 + 14 + 120 + 8 + 8 + 7 + 22 + 32.

=490

b, 6 + 10 + 8 + 2 + 2 + 24 + 2 + 3.

=57

A.115-(-85)+35-(46+35)

= 115 + 85 + 35 - 81

= 200 + 35 - 81

= 235 - 81

= 154

Vậy A = 154

B.7.(-3)^2 +9.(-4)^0 -(63-9)

= 7. 9 + 9. 1 - (63-9)

= 9. ( 7 + 1 ) - (63-9)

= 9 . 8 - 54

= 72 - 54

= 18

Vậy B= 18

C.(-164)+(-2)^10 : (-2)^8 +64

= (- 164) + (-2)^2 + 64

= (- 164) + 4 + 64

= (-168) + 64

= -104

Vậy C = - 104

a) -( -35 + 7 - 13 ) + ( 2 - 35 ) - ( 13 - 7 )

= 35 - 7 + 13 + 2 - 35 - 13 + 7

= ( 35 - 35 ) + ( -7 + 7 ) + ( 13 - 13 ) + 2

= 0 + 0 + 0 + 2

= 2

b) ( 70 + 8 - 35 ) - ( 8 - 37 - 10 ) - 70 

= 70 + 8 - 35 - 8 + 37 + 10 - 70

= ( 70 - 70 ) + ( 8 - 8 ) + ( -35 + 37 ) + 10

= 0 + 0 + 2 + 10

= 12 

c) 5 - ( 14 + 4 - 52 ) - ( 52 - 14 ) + 4

= 5 - 14 - 4 + 52 - 52 + 14 + 4

= 5 - ( 14 + 14 ) + ( 52 - 52 ) + ( -14 + 14 )

= 5 - 14 - 14 + 0 + 0

= 5 - ( 14 - 14 )

= 5 - 0

= 5

kinh day ban oi

b: Ta có: \(\left(\sqrt{7-3\sqrt{5}}\right)\cdot\left(7+3\sqrt{5}\right)\cdot\left(3\sqrt{2}+\sqrt{10}\right)\)

\(=\left(3-\sqrt{5}\right)\left(3+\sqrt{5}\right)\left(7+3\sqrt{5}\right)\)

\(=4\left(7+3\sqrt{5}\right)\)

\(=28+12\sqrt{5}\)

Lời giải:

a. 

$A=\sqrt{8+\sqrt{55}}-\sqrt{8-\sqrt{55}}-\sqrt{125}$
$\sqrt{2}A=\sqrt{16+2\sqrt{55}}-\sqrt{16-2\sqrt{55}}-\sqrt{250}$

$=\sqrt{(\sqrt{11}+\sqrt{5})^2}-\sqrt{(\sqrt{11}-\sqrt{5})^2}-5\sqrt{10}$

$=|\sqrt{11}+\sqrt{5}|-|\sqrt{11}-\sqrt{5}|-5\sqrt{10}$

$=2\sqrt{5}-5\sqrt{10}$

$\Rightarrow A=\sqrt{10}-5\sqrt{5}$

b.

$B=\sqrt{7-3\sqrt{5}}.(7+3\sqrt{5})(3\sqrt{2}+\sqrt{10})$

$B\sqrt{2}=\sqrt{14-6\sqrt{5}}(7+3\sqrt{5})(3\sqrt{2}+\sqrt{10})$

$=\sqrt{(3-\sqrt{5})^2}(7+3\sqrt{5}).\sqrt{2}(3+\sqrt{5})$

$=(3-\sqrt{5})(7\sqrt{2}+3\sqrt{10})(3+\sqrt{5})$

$=(3^2-5)(7\sqrt{2}+3\sqrt{10})$

$=4(7\sqrt{2}+3\sqrt{10})=28\sqrt{2}+12\sqrt{10}$

$\Rightarrow B=28+12\sqrt{5}$

c.

$C=\sqrt{2}(\sqrt{7}-\sqrt{5})(6-\sqrt{35})\sqrt{6+\sqrt{35}}$

$=(\sqrt{7}-\sqrt{5})(6-\sqrt{35})\sqrt{12+2\sqrt{35}}$

$=(\sqrt{7}-\sqrt{5})(6-\sqrt{35})\sqrt{(\sqrt{7}+\sqrt{5})^2}

$=(\sqrt{7}-\sqrt{5})(6-\sqrt{35})(\sqrt{7}+\sqrt{5})$

$=(7-5)(6-\sqrt{35})$

$=2(6-\sqrt{35})=12-2\sqrt{35}$

d: \(=\dfrac{-7}{9}\left(\dfrac{3}{11}+\dfrac{8}{11}\right)+1+\dfrac{7}{9}=1\)

e: \(=\dfrac{1}{5}\left(\dfrac{10}{19}+\dfrac{9}{19}\right)-\dfrac{2}{35}=\dfrac{1}{5}-\dfrac{2}{35}=\dfrac{5}{35}=\dfrac{1}{7}\)

f: \(=\left(-25\cdot4\right)\cdot\left(-8\cdot125\right)\cdot\left(-17\right)=-1700000\)

a)-112

b: =-30-15-21

=-66

đáp án là D nha

TL:

D. 8/21

nha!

HT

TL

A  \(\frac{10}{35}\)

nha

HT

D.8/21

TL:

D. 8/21

nha!

HT

8/21 nha

14) \(\sqrt{7-4\sqrt{3}}=2-\sqrt{3}\)

15) \(\sqrt{8+2\sqrt{15}}=\sqrt{5}+\sqrt{3}\)

16) \(\sqrt{10-2\sqrt{21}}=\sqrt{7}-\sqrt{3}\)

17) \(\sqrt{11+2\sqrt{18}}=3+\sqrt{2}\)

18) \(\sqrt{7+2\sqrt{10}}=\sqrt{5}+\sqrt{2}\)

19) \(\sqrt{7+4\sqrt{3}}=2+\sqrt{3}\)

20) \(\sqrt{12-2\sqrt{35}}=\sqrt{7}-\sqrt{5}\)

\(\sqrt{7-4\sqrt{3}}=\sqrt{2^2-2.2.\sqrt{3}+\left(\sqrt{3}\right)^2}=\sqrt{\left(2-\sqrt{3}\right)^2}=\left|2-\sqrt{3}\right|=2-\sqrt{3}\)

√7−4√3=√22−2.2.√3+(√3)2=√(2−√3)2=∣∣2−√3∣∣=2−√3