Đáp án: (D) \(18^{13}\)

a , 96 . 4 + 4 . 4 + 96 . 0

= 4 . ( 96 + 4 ) + 0

= 4 . 100

= 400

b , 78 . 5 + 5 . 2

= 5 . ( 78 + 2 )

= 5 . 80

= 5 . 2 . 40

= 10 . 40

= 100

c , 5 . 2 + 8 . 9

= 10 + 72

= 82

Đề bài yêu cầu gì?

a: \(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^8\left(1+5\right)}=\dfrac{-2}{6}=\dfrac{-1}{3}\)

b: \(=\dfrac{5^{16}\cdot3^{21}}{5^{15}\cdot3^{22}}=\dfrac{5}{3}\)

\(2x=5.9^2:8\)

\(2x=5.81:8\)

\(16x=405\)

\(x=\dfrac{405}{16}\)

\(5\cdot9^2:8=2x\\\Rightarrow 2x=5\cdot81:8\\\Rightarrow2x=405:8\\\Rightarrow2x=\dfrac{405}{8}\\\Rightarrow x=\dfrac{405}{16}\\Vậy:x=\dfrac{405}{16}\)

Không chép lại  đầu bài nha!
=\(\frac{5-3}{3.5}+\frac{9-5}{5.9}+\frac{17-9}{9.17}\)

=\(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\)

=\(\frac{1}{3}-\frac{1}{11}\)

=\(\frac{8}{33}\)

-1/3 đó bạn

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AI TK MÌNH MÌNH TK LẠI 3 LẦN.

\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)

\(=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.6^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}\)

\(=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)

\(=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}\)

\(=\frac{-2}{6}\)

\(=-\frac{1}{3}\)

\(\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^{10}}\)

\(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^{10}}\)

\(=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^8\left(1+3^2\right)}=-\dfrac{2}{10}=-\dfrac{1}{5}\)

\(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^{10}}\)

\(=\dfrac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^{10}}\)

\(=\dfrac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^{10}.3^{10}}\)

\(=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8.\left(1+3^2\right)}\)

\(=\dfrac{2^{10}.3^8.\left(1-3\right)}{2^{10}.3^8.10}\)

\(=\dfrac{-2}{10}\)

\(=\dfrac{-1}{5}\)

Hơi khó đọc qué ah.