\(\dfrac{1}{2}\times\dfrac{1}{3}+\dfrac{2}{3}+\dfrac{1}{2}\)
\(=\dfrac{1}{6}+\dfrac{2}{3}+\dfrac{1}{2}\)
\(=\dfrac{1}{6}+\dfrac{4}{6}+\dfrac{3}{6}\)
\(=\dfrac{8}{6}=\dfrac{4}{3}\)

\(x-\dfrac{1}{3}=\dfrac{2}{3}.\dfrac{9}{14}+\dfrac{3}{7}\)

\(x-\dfrac{1}{3}=\dfrac{1}{7}+\dfrac{3}{7}\)

\(x-\dfrac{1}{3}=\dfrac{4}{7}\)

\(x=\dfrac{19}{21}\)

x = 19/21 nha

cảm ơn các bạn nhé!

`1/5xx1/2:3/10`

`=1/10xx10/3`

`=1/3`

`1/2xx1/3:1/4`

`=1/6xx4/1`

`=2/3`

a. \(\dfrac{1}{5}\times\dfrac{1}{2}:\dfrac{3}{10}=\dfrac{1}{10}:\dfrac{3}{10}=\dfrac{1}{10}\times\dfrac{10}{3}=\dfrac{10}{30}=\dfrac{1}{3}\)

b. \(\dfrac{1}{2}\times\dfrac{1}{3}:\dfrac{1}{4}=\dfrac{1}{6}:\dfrac{1}{4}=\dfrac{1}{6}\times\dfrac{4}{1}=\dfrac{4}{6}=\dfrac{2}{3}\)

a) \(\dfrac{1}{5}\times\dfrac{1}{2}:\dfrac{3}{10}=\dfrac{1}{5}\times\dfrac{1}{2}\times\dfrac{10}{3}=\dfrac{1\times1\times10}{5\times2\times3}=\dfrac{10}{30}=\dfrac{1}{3}\)

b) \(\dfrac{1}{2}\times\dfrac{1}{3}:\dfrac{1}{4}=\dfrac{1}{2}\times\dfrac{1}{3}\times4=\dfrac{1\times1\times4}{2\times3}=\dfrac{4}{6}=\dfrac{2}{3}\)

\(\left(\frac{5}{12}+\frac{1}{2}.\frac{1}{3}\right):\left(2.\frac{1}{3}-1.\frac{5}{12}\right)\)

\(=\left(\frac{5}{12}+\frac{1}{6}\right):\left(\frac{2}{3}-\frac{5}{12}\right)\)

\(=\frac{7}{12}:\frac{1}{4}\)

\(=\frac{7}{3}\)

_Chúc bạn học tốt_

Đề bài 

= ( 5/12 +    1/6 ) : (    2/3 - 1/12 ) 

= ( 5/12 + 2/12 ) :   ( 8/12 - 1/12 ) 

= 7/12 : 7/12 

= 1 

K Trắng nha .

=1 nha

\(\left(\frac{5}{12}+\frac{1}{2}\times\frac{1}{3}\right):\left(2\times\frac{1}{3}-1\times\frac{1}{12}\right)\)

\(=\left(\frac{5}{12}+\frac{1}{6}\right):\left(\frac{2}{3}-\frac{1}{12}\right)\)

\(=\frac{7}{12}:\frac{7}{12}\)

\(=1\)

k bk tính nhanh!

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Lần sau nhớ chọn đúng môn

Uk, Long cứ đợi ng ta trả lời xong long làm giống là đc ý mà!

Xin lỗi Long vì có hơi bực nên mới nói vậy, mong bn bỏ qua

đề??

a) \(\dfrac{4}{5}-\left(\dfrac{1}{5}+\dfrac{1}{3}\right)=\dfrac{4}{5}-\left(\dfrac{3}{15}+\dfrac{5}{15}\right)=\dfrac{4}{5}-\dfrac{8}{15}=\dfrac{12}{15}-\dfrac{8}{15}=\dfrac{4}{15}\)

b) \(\dfrac{12}{7}-\left(\dfrac{3}{14}-1\right)=\dfrac{12}{7}-\left(-\dfrac{11}{14}\right)=\dfrac{12}{7}+\dfrac{11}{14}=\dfrac{5}{2}\)

c) \(\dfrac{11}{2}-9\cdot\left(\dfrac{7}{5}-\dfrac{1}{2}\right)=\dfrac{11}{2}-9\cdot\dfrac{9}{10}=\dfrac{11}{2}-\dfrac{81}{10}=\dfrac{55}{10}-\dfrac{81}{10}=-\dfrac{13}{5}\)

d) \(3\times9\left(\dfrac{4}{7}+\dfrac{3}{5}\right)=27\times\dfrac{41}{35}=\dfrac{1107}{35}\)

e) \(\left(\dfrac{1}{3}-\dfrac{1}{5}\right):2=\left(\dfrac{5}{15}-\dfrac{3}{15}\right):2=\dfrac{2}{15}:2=\dfrac{2}{15}\times\dfrac{1}{2}=\dfrac{1}{15}\)

f) \(\dfrac{123}{34}:\dfrac{1}{17}-\dfrac{21}{34}:\dfrac{1}{17}=\left(\dfrac{123}{34}-\dfrac{21}{34}\right):\dfrac{1}{17}=3:\dfrac{1}{17}=3\times17=51\)