a, \(x^2-4x+4x-5\ge x^2+6\Leftrightarrow-5\ge6\)

vô lí bpt vô nghiệm 

b, \(9x^2-6x+1-9x^2+9< 5x-2\Leftrightarrow-6x+10< 5x-2\)

\(\Leftrightarrow-11x< -12\Leftrightarrow x>\dfrac{12}{11}\)

a) \(\left(3x-2\right)^2-\left(3x-5\right)\left(3x+2\right)=11\)
\(\Leftrightarrow\left(9x^2-12x+4\right)-\left(9x^2+6x-15x-10\right)=11\)
\(\Leftrightarrow9x^2-12x+4-9x^2-6x+15x+10=11\)
\(\Leftrightarrow-3x+3=0\)
\(\Leftrightarrow-3x=-3\)
\(\Leftrightarrow x=1\)
Vậy \(S=\left\{1\right\}\)

b) \(\left(4x-3\right)^2-\left(4x-5\right)\left(4x+5\right)=32\)
\(\Leftrightarrow\left(16x^2-24x+9\right)-\left(16x^2-25\right)=32\)
\(\Leftrightarrow16x^2-24x+9-16x^2+25=32\)
\(\Leftrightarrow-24x+2=0\)
\(\Leftrightarrow-24x=-2\)
\(\Leftrightarrow x=\dfrac{1}{12}\)
Vậy \(S=\left\{\dfrac{1}{12}\right\}\)

c) \(\left(5x-2\right)^2-\left(5x+3\right)\left(5x-5\right)=1\)
\(\Leftrightarrow\left(25x^2-20x+4\right)-\left(25x^2-25x+15x-15\right)=1\)
\(\Leftrightarrow25x^2-20x+4-25x^2+25x-15x+15=1\)
\(\Leftrightarrow-10x+18=0\)
\(\Leftrightarrow-10x=-18\)
\(\Leftrightarrow x=\dfrac{9}{5}\)
Vậy \(S=\left\{\dfrac{9}{5}\right\}\)

d) \(\left(x-4\right)^2-\left(x-7\right)\left(2x-3\right)=5-x^2\)
\(\Leftrightarrow\left(x^2-8x+16\right)-\left(2x^2-3x-14x+21\right)=5-x^2\)
\(\Leftrightarrow x^2-8x+16-2x^2+3x+14x-21=5-x^2\)
\(\Leftrightarrow x^2-8x+16-2x^2+3x+14x-21-5+x^2=0\)
\(\Leftrightarrow9x-10=0\)
\(\Leftrightarrow9x=10\)
\(\Leftrightarrow x=\dfrac{10}{9}\)
Vậy \(S=\left\{\dfrac{10}{9}\right\}\)

a: =2x^5-15x^3-x^2-2x^5-x^3=-16x^3-x^2

b: =x^3+3x^2-2x-3x^2-9x+6

=x^3-11x+6

c: \(=\dfrac{4x^3+2x^2-6x^2-3x-2x-1+5}{2x+1}\)

\(=2x^2-3x-1+\dfrac{5}{2x+1}\)

a) \(6x^3\left(\dfrac{1}{3}x^2-\dfrac{5}{2}-\dfrac{1}{6}\right)-2x^5-x^3\)

\(=6x^3\left(\dfrac{1}{3}x^2-\dfrac{16}{6}\right)-2x^5-x^3\)

\(=2x^5-16x^3-2x^5-x^3\)

\(=-17x^3\)

b) \(\left(x+3\right)\left(x^2+3x-2\right)\)

\(=x^3+3x^2-2x+3x^2+9x-6\)

\(=x^3+6x^2+7x-6\)

c) \(\left(4x^3-4x^2-5x+4\right):\left(2x+1\right)\)

\(=2x^2+4x^3-2x-4x^2-\dfrac{5}{2}-5x+\dfrac{2}{x}+4\)

\(=4x^3-2x^2-7x+\dfrac{2}{x}+\dfrac{3}{2}\)

\(a,\left(x+2\right)^2-4x\left(x-1\right)=-3x\left(x-6\right)\)

\(\Leftrightarrow x^2+4x+4-4x^2+4x=-3x^2+18x\)

\(\Leftrightarrow x^2-4x^2+3x^2+4x+4x-18x=-4\)

\(\Leftrightarrow-10x=-4\)

\(\Leftrightarrow x=\frac{2}{5}\)

Câu b làm tương tự nhé

Học tốt ##

\(b,\left(x+3\right)^3-\left(x-2\right)^3=\left(5x-1\right)\left(3x+2\right)\)

\(\Rightarrow x^3+6x^2+9x+3x^2+18x+27-x^3+4x^2-4x+2x^2-8x+8=15x^2+10x-3x-2\)

\(\Rightarrow15x^2+15x+35=15x^2+10x-3x-2\)

\(\Rightarrow15x^2+15x+35=15x^2+7x-2\)

\(\Rightarrow15x+35=7x-2\)

\(\Rightarrow15x-7x=-2-35\)

\(\Rightarrow8x=-37\)

\(\Rightarrow x=\frac{-37}{8}\)

a) Thu gọn, sắp xếp các đa thức theo lũy thừa tăng của biến

$f\left(x\right)=x^2+2x^3-7x^5-9-6x^7+x^3+x^2+x^5-4x^2+3x^7$

= -9 - 2x² + 3x³ - 6x⁵ - 3x⁷

$g\left(x\right)=x^5+2x^3-5x^8-x^7+x^3+4x^2-5x^7+x^4-4x^2-x^6-12$

$\mathrm{=\; -12\; +\; 3x3\; +\; x4\; +\; x5\; -\; x6\; -\; 6x7\; -\; 5x8}$

$h\left(x\right)=x+4x^5-5x^6-x^7+4x^3+x^2-2x^7+x^6-4x^2-7x^7+x$

$\mathrm{=\; 2x\; -\; 3x2\; +\; 4x3\; +4x5\; -4x6\; -\; 10x7}$

b) Tính $f\left(x\right)+g\left(x\right)-h(x)\; =\; ($-9 - 2x² + 3x³ - 6x⁵ - 3x⁷ ) + (-12 + 3x³ + x⁴ + x⁵ - x⁶ - 6x⁷ - 5x⁸ ) - (2x - 3x² + 4x³ +4x⁵ -4x⁶ - 10x⁷)

= - 9 - 2x² + 3x³ - 6x⁵ - 3x⁷ -12 + 3x³ + x⁴ + x⁵ - x⁶ - 6x⁷ - 5x⁸ - 2x + 3x² - 4x³ - 4x⁵ + 4x⁶ + 10x⁷

= -21 - 2x + x² + 2x³ + x⁴ - 9x⁵ + 3x⁶ + x⁷ - 5x⁸

Đề có sai không bạn?

a) \(A\left(x\right)=3x^3-4x^4-2x^3+4x^4-5x+3\)

\(\Rightarrow A\left(x\right)=-4x^4+4x^4+3x^3-2x^3-5x+3\)

\(\Rightarrow A\left(x\right)=x^3-5x+3\)

\(B\left(x\right)=5x^3-4x^2-5x^3-4x^2-5x-3\)

\(\Rightarrow B\left(x\right)=5x^3-5x^3-4x^2-4x^2-5x-3\)

\(\Rightarrow B\left(x\right)=-8x^2-5x-3\)

b) \(A\left(x\right)+B\left(x\right)=x^3-5x+3+\left(-8x^2-5x-3\right)\)

\(\Rightarrow A\left(x\right)+B\left(x\right)=x^3-5x+3-8x^2-5x-3\)

\(\Rightarrow A\left(x\right)+B\left(x\right)=x^3-8x^2-5x-5x+3-3\)

\(\Rightarrow A\left(x\right)+B\left(x\right)=x^3-8x^2-10x\)

\(A\left(x\right)-B\left(x\right)=x^3-5x+3-\left(-8x^2-5x-3\right)\)

\(\Rightarrow A\left(x\right)-B\left(x\right)=x^3-5x+3+8x^2+5x+3\)

\(\Rightarrow A\left(x\right)-B\left(x\right)=x^3+8x^2-5x+5x+3+3\)

\(\Rightarrow A\left(x\right)-B\left(x\right)=x^3+8x^2+6\)