a) \(\frac{1}{8}>0>\frac{-3}{8}=>\frac{1}{8}>\frac{-3}{8}\)

b) \(\frac{-3}{7}< 0< 2\frac{1}{2}=>\frac{-3}{7}< 2\frac{1}{2}\)

c) \(-3.9< 0< 0.1=>-3.9< 0.1\)

d) \(-2.3< 0< 3.2=>-2.3< 3.2\)

Câu 1 : 

\(\dfrac{-25}{37}\&\dfrac{-20}{31}\)

Ta thấy \(\dfrac{-25}{37}< \dfrac{-20}{37}\)

mà \(\dfrac{-20}{37}< \dfrac{-20}{31}\)

\(\Rightarrow\dfrac{-25}{37}< \dfrac{-20}{31}\)

Câu 2 :

\(\dfrac{2}{3}\&\dfrac{5}{7}\)

\(\dfrac{2}{3}:\dfrac{5}{7}=\dfrac{2}{3}.\dfrac{7}{5}=\dfrac{14}{15}< 1\)

Ta thấy \(\dfrac{8}{13}:\dfrac{5}{7}=\dfrac{8}{13}.\dfrac{7}{5}=\dfrac{56}{65}< 1\)

a,

Ta có:
\(\dfrac{3}{7}=1-\dfrac{4}{7}\)
\(\dfrac{11}{15}=1-\dfrac{4}{15}\)
So sánh phân số \(\dfrac{4}{7}\) và \(\dfrac{4}{15}\)
Vì \(7< 15\) nên \(\dfrac{1}{7}>\dfrac{1}{15}\)
\(\Rightarrow1-\dfrac{4}{7}< 1-\dfrac{4}{15}\)
Vậy \(\dfrac{3}{7}< \dfrac{11}{15}\)

b)

\(\dfrac{-11}{6}< -1< \dfrac{-8}{9}\) nên \(\dfrac{-11}{6}< \dfrac{-8}{9}\)

c) 

\(\dfrac{305}{25}=\dfrac{305:5}{25:5}=\dfrac{61}{5}\)
Ta có: 
Mẫu số chung 2 phân số: 80
\(\dfrac{297}{16}=\dfrac{297*5}{16*5}=\dfrac{1485}{80}\)
\(\dfrac{61}{5}=\dfrac{61*16}{5*16}=\dfrac{976}{80}\)
Vì \(1485>976\) nên\(\dfrac{1485}{80}>\dfrac{976}{80}\)
Vậy \(\dfrac{297}{16}>\dfrac{305}{25}\)

d,

$\frac{-205}{317}=\frac{-205:-1}{317:-1}=\frac{205}{-317}$
Ta có: 
Mẫu số chung 2 phân số: -35187
\(\dfrac{205}{-317}=\dfrac{205*111}{-317*111}=\dfrac{22755}{-35187}\)
\(\dfrac{-83}{111}=\dfrac{-83*-317}{111*-317}=\dfrac{26311}{-35187}\)
Vì \(22755< 26311\) nên\(\dfrac{22755}{-35187}< \dfrac{26311}{-35187}\)
Vậy \(\dfrac{-205}{317}< \dfrac{-83}{111}\)

Câu d, mình làm sai, cho mình sửa lại:

\(\dfrac{-205}{317}=\dfrac{-22755}{35187}\)

\(\dfrac{-83}{111}=\dfrac{-26311}{35187}\)

Vậy là  \(-22755>-26311\) hay \(\dfrac{-205}{317}>\dfrac{-83}{111}\)

a: -3/100=-9/300; -2/3=-200/300

=>-3/100>-2/3

b: -3/5=-9/15

-2/3=-10/15

=>-3/5>-2/3

c: -5/4<-1<-3/8

d: -2/3=-8/12; -3/4=-9/12

=>-2/3>-3/4

e: -267/268>-1

-1>-1347/1343

=>-267/268>-1347/1343

Bài 1:

1)mik ko biết trục số ở đâu nên tham khảo:

2

-0,75 <5/3

Lời giải:
a. $\frac{3}{-7}=\frac{-27}{63}$

$\frac{-5}{9}=\frac{-35}{63}$

Do $\frac{27}{63}< \frac{35}{63}$ nên $\frac{-27}{63}> \frac{-35}{63}$

$\Rightarrow \frac{3}{-7}> \frac{-5}{9}$

---------

b.

$-0,625=\frac{-625}{1000}=\frac{-5}{8}=\frac{-125}{200}$

$\frac{-19}{50}=\frac{-76}{200}> \frac{-125}{200}$

$\Rightarrow -0,625> \frac{-19}{50}$

c.

$-2\frac{5}{9}=-(2+\frac{5}{9})=\frac{-23}{9}=-(\frac{-23}{-9})$

a) ta có : \(\dfrac{1}{8}>0\) và \(\dfrac{-3}{8}< 0\) \(\Rightarrow\dfrac{-3}{8}< \dfrac{1}{8}\) vậy \(\dfrac{-3}{8}< \dfrac{1}{8}\)

b) ta có : \(\dfrac{-3}{7}< 0\) và \(2\dfrac{1}{2}=\dfrac{5}{2}>0\) \(\Rightarrow\dfrac{-3}{7}< 1\dfrac{1}{2}\) vậy \(\dfrac{-3}{7}< 1\dfrac{1}{2}\)

c) ta có : \(-3,9< 0\) và \(0,1>0\) \(\Rightarrow-3,9< 0,1\) vậy \(-3,9< 0,1\)

d) ta có : \(-2,3< 0\) và \(3,2>0\) \(\Rightarrow-2,3< 3,2\) vậy \(-2,3< 3,2\)

a)\(\dfrac{1}{8}>0>\dfrac{-3}{8}\)

=>\(\dfrac{1}{8}>\dfrac{-3}{8}\)

b)\(2\dfrac{1}{2}=\dfrac{5}{2}>0>\dfrac{-3}{7}\)

=>\(2\dfrac{1}{2}>\dfrac{-3}{7}\)

c)\(-3,9< 0< 0,1\)

=>\(-3,9< 0,1\)

d)\(-2,3< 0< 3,2\)

=>\(-2,3< 3,2\)

\(\dfrac{1}{8}>0>\dfrac{-3}{8}\\ \text{Vậy }\dfrac{1}{8}>\dfrac{-3}{8}\\ \dfrac{-3}{7}< 0< 2\dfrac{1}{2}\\ \text{Vậy }\dfrac{-3}{7}< 2\dfrac{1}{2}\\ -3,9< 0< 0,1\\ \text{Vậy }-3,9< 0,1\\ -2,3< 0< 3,2\\ \text{Vậy }-2,3< 3,2\)

a: \(x_1=x_2=x_3=x_4\)

a)\(\frac{1}{8}>0;\frac{-3}{7}< 0\Rightarrow\frac{1}{8}>0>\frac{-3}{7}\Rightarrow\frac{1}{8}>\frac{-3}{7}\)

b)\(\frac{-3}{7}< 0;2\frac{1}{2}>0\Rightarrow\frac{-3}{7}< 0< 2\frac{1}{2}\Rightarrow\frac{-3}{7}< 2\frac{1}{2}\)

c)\(-3,9< 0;0,1>0\Rightarrow-3,9< 0< 0,1\Rightarrow-3,9< 0,1\)

d)\(-2,3< 0;3,2>0\Rightarrow-2,3< 0< 3,2\Rightarrow-2,3< 3,2\)

1/8>-3/7

-3/7<2 1/2

-3.9 <0.1

-2.3<3.2