\(\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}\)
Rút gọn: \(\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}\)
\(=\sqrt{13+30\sqrt{2+2\sqrt{2}+1}}\)
\(=\sqrt{13+30\left(\sqrt{2}+1\right)}=\sqrt{43+30\sqrt{2}}\)
\(=\sqrt{43+2\cdot\sqrt{450}}\)
\(=\sqrt{25+2\cdot5\cdot3\sqrt{2}+18}\)
\(=\sqrt{\left(5+3\sqrt{2}\right)^2}=5+3\sqrt{2}\)
bài 5 Tính:
a) \(\sqrt{6-2\sqrt{5}}\)
b)\(\sqrt{7-4\sqrt{3}}\)
c)\(\sqrt{3-2\sqrt{2}}\) -\(\sqrt{6-4\sqrt{2}}\)
d)\(\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}\)
Lời giải:
a. \(\sqrt{6-2\sqrt{5}}=\sqrt{5-2\sqrt{5}.\sqrt{1}+1}=\sqrt{(\sqrt{5}-1)^2}=\sqrt{5}-1\)
b. \(\sqrt{7-4\sqrt{3}}=\sqrt{4-2\sqrt{4}.\sqrt{3}+3}=\sqrt{(\sqrt{4}-\sqrt{3})^2}=\sqrt{4}-\sqrt{3}=2-\sqrt{3}\)
c.
\(\sqrt{3-2\sqrt{2}}-\sqrt{6-4\sqrt{2}}=\sqrt{2-2\sqrt{2}+1}-\sqrt{4-4\sqrt{2}+2}\)
\(=\sqrt{(\sqrt{2}-1)^2}-\sqrt{(\sqrt{4}-\sqrt{2})^2}\)
\(=|\sqrt{2}-1|-|\sqrt{4}-\sqrt{2}|=\sqrt{2}-1-(2-\sqrt{2})=2\sqrt{2}-3\)
d.
\(=\sqrt{13+30\sqrt{2+\sqrt{(\sqrt{8}+1)^2}}}=\sqrt{13+30\sqrt{2+\sqrt{8}+1}}\)
\(=\sqrt{13+30\sqrt{3+2\sqrt{2}}}=\sqrt{13+30\sqrt{(\sqrt{2}+1)^2}}\)
\(=\sqrt{13+30(\sqrt{2}+1)}=\sqrt{43+30\sqrt{2}}=\sqrt{18+2\sqrt{18.25}+25}\)
\(=\sqrt{(\sqrt{18}+\sqrt{25})^2}=\sqrt{18}+\sqrt{25}=5+3\sqrt{2}\)
a) \(\sqrt{6-2\sqrt{5}}=\sqrt{5}-1\)
b) \(\sqrt{7-4\sqrt{3}}=2-\sqrt{3}\)
c) \(\sqrt{3-2\sqrt{2}}-\sqrt{6-4\sqrt{2}}=\sqrt{2}-1-2+\sqrt{2}=-3+2\sqrt{2}\)
d) Ta có: \(\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}\)
\(=\sqrt{13+30\sqrt{2+1+2\sqrt{2}}}\)
\(=\sqrt{13+30\left(\sqrt{2}+1\right)}\)
\(=\sqrt{43+30\sqrt{2}}\)
\(=5+3\sqrt{2}\)
Giúp mình với
II.nhân:\(\sqrt{A}\).\(\sqrt{B}\)=\(\sqrt{..............}\)(A≥0;B≥0)
a)\(\sqrt{2}\left(\sqrt{3-\sqrt{5}}-\sqrt{3+\sqrt{5}}\right)\)
b)\(\sqrt{13+30\sqrt{2}+\sqrt{9+4\sqrt{2}}}\)
c)\(\sqrt{6+2\sqrt{5}-\sqrt{13+\sqrt{48}}}\)
a) Ta có: \(\sqrt{2}\left(\sqrt{3-\sqrt{5}}-\sqrt{3+\sqrt{5}}\right)\)
\(=\sqrt{6-2\sqrt{5}}-\sqrt{6+2\sqrt{5}}\)
\(=\sqrt{5}-1-\sqrt{5}-1=-2\)
b) Ta có: \(\sqrt{13+30\sqrt{2}+\sqrt{9+4\sqrt{2}}}\)
\(=\sqrt{13+30\sqrt{2}+2\sqrt{2}+1}\)
\(=\sqrt{14+32\sqrt{2}}\)
c) Ta có: \(\sqrt{6+2\sqrt{5}-\sqrt{13+\sqrt{48}}}\)
\(=\sqrt{6+2\sqrt{5}-2\sqrt{3}-1}\)
\(=\sqrt{5+2\sqrt{5}-2\sqrt{3}}\)
\(\sqrt{13+30\sqrt{ }2+\sqrt{ }9+4\sqrt{ }2}=5+3\sqrt{2}\)
\(\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}=5+3\sqrt{2}\)
\(\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}=\sqrt{13+30\sqrt{2+\sqrt{1+4\sqrt{2}+8}}}=\sqrt{13+30\sqrt{2+\sqrt{1+2.2\sqrt{2}+\left(2\sqrt{2}\right)^2}}}=\sqrt{13+30\sqrt{2+\sqrt{\left(1+2\sqrt{2}\right)^2}}}=\sqrt{13+30\sqrt{3+2\sqrt{2}}}=\sqrt{13+30\sqrt{\left(1+\sqrt{2}\right)^2}}=\sqrt{13+30\left(1+\sqrt{2}\right)}=\sqrt{43+30\sqrt{2}}=\sqrt{\left(5+3\sqrt{2}\right)^2}=5+3\sqrt{2}\)
\(B=3\sqrt{2}-\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}\)
\(B=3\sqrt{2}-\sqrt{13+30\sqrt{2+\sqrt{\left(2\sqrt{2}+1\right)^2}}}\)
\(B=3\sqrt{2}-\sqrt{13+30\sqrt{2+2\sqrt{2}+1}}\)
\(B=3\sqrt{2}-\sqrt{13+30\sqrt{3+2\sqrt{2}}}\)
\(B=3\sqrt{2}-\sqrt{13+30\sqrt{\left(\sqrt{2}+1\right)^2}}\)
\(B=3\sqrt{2}-\sqrt{13+30\left(\sqrt{2+1}\right)}\)
\(B=3\sqrt{2}-\sqrt{13+30\sqrt{2}+30}\)
\(B=3\sqrt{2}-\sqrt{43+30\sqrt{2}}\)
\(B=3\sqrt{2}-\sqrt{\left(3\sqrt{2}+5\right)^2}\)
\(B=3\sqrt{2}-3\sqrt{2}-5\)
\(B=-5\)
vậy \(B=-5\)
\(B=3\sqrt{2}-\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}\\ \)
\(=3\sqrt{2}-\sqrt{13+30\sqrt{2+\sqrt{\left(2\sqrt{2}\right)^2+2.2\sqrt{2}+1^2}}}\)
\(=3\sqrt{2}-\sqrt{13+30\sqrt{2+2\sqrt{2}+1}}\)
\(=3\sqrt{2}-\sqrt{13+30\sqrt{\left(\sqrt{2}\right)^2+2\sqrt{2}+1}}\)
\(=3\sqrt{2}-\sqrt{13+30\left(\sqrt{2}+1\right)}\)
\(=3\sqrt{2}-\sqrt{13+30\sqrt{2}+30}\)
\(=3\sqrt{2}-\sqrt{43+30\sqrt{2}}\)
\(=3\sqrt{2}-\sqrt{\left(3\sqrt{2}\right)^2+2.5.3\sqrt{2}+5^2}\)
\(=3\sqrt{2}-3\sqrt{2}+5=5\)
rất chi tiết đó bạn
Thực hiện phép tính
a, \(\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}\)
b, \(\sqrt{5-\sqrt{13+4\sqrt{3}}}+\sqrt{3+\sqrt{13+4\sqrt{3}}}\)
c, \(\sqrt{1+\sqrt{3+\sqrt{13+4\sqrt{3}}}}+\sqrt{1-\sqrt{3-\sqrt{13-4\sqrt{3}}}}\)
d, \(\left(\sqrt{3}-\sqrt{2}\right)\sqrt{5+2\sqrt{6}}\)
a,\(\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}\)
\(=\sqrt{13+30\sqrt{3+2\sqrt{2}}}\\ =\sqrt{13+30\left(\sqrt{2}+1\right)}\)
\(=\sqrt{43+30\sqrt{2}}=5+3\sqrt{2}\)
b, \(\sqrt{5-\sqrt{13+4\sqrt{3}}}+\sqrt{3+\sqrt{13+4\sqrt{3}}}\)
\(\Leftrightarrow\sqrt{5-\sqrt{\left(2\sqrt{3}\right)^2+2.2\sqrt{3}+1}}+\sqrt{3+\sqrt{\left(2\sqrt{3}\right)^2+2.2\sqrt{3}+1}}\)
\(\Leftrightarrow\sqrt{5-\sqrt{\left(2\sqrt{3}+1\right)^2}}+\sqrt{3+\sqrt{\left(2\sqrt{3}+1\right)^2}}\)
\(\Leftrightarrow\sqrt{5-2\sqrt{3}-1}+\sqrt{3+2\sqrt{3}+1}\)
\(\Leftrightarrow\sqrt{\left(\sqrt{3}-1\right)^2}+\sqrt{\left(\sqrt{3}+1\right)^2}\)
\(\Leftrightarrow\sqrt{3}-1+\sqrt{3}+1\)
\(\Leftrightarrow2\sqrt{3}\)
d,\(\left(\sqrt{3}-\sqrt{2}\right)\sqrt{5+2\sqrt{6}}\)
\(\Leftrightarrow\left(\sqrt{3}-\sqrt{2}\right)\sqrt{3+2.\sqrt{2}\sqrt{3}+2}\)
\(\Leftrightarrow\left(\sqrt{3}-\sqrt{2}\right)\sqrt{\left(\sqrt{3}+\sqrt{2}\right)^2}\)
\(\Leftrightarrow\left(\sqrt{3}-\sqrt{2}\right)\left(\sqrt{3}+\sqrt{2}\right)\)
\(\Leftrightarrow3-2\Leftrightarrow1\)
\(\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}\)
\(=\sqrt{13+30\sqrt{2+\sqrt{\left(2\sqrt{2}+1\right)^2}}}\)
\(=\sqrt{13+30\sqrt{3+2\sqrt{2}}}\)
\(=\sqrt{13+30\sqrt{\left(\sqrt{2}+1\right)^2}}\)
\(=\sqrt{13+30\left(\sqrt{2}+1\right)}=\sqrt{43+30\sqrt{2}}\)
\(=\sqrt{\left(5+3\sqrt{2}\right)}=5+3\sqrt{2}\)
CMR: \(\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}=5+3\sqrt{2}\)