a)  \(x^2+4x+4=\left(x+2\right)^2\)

b)  \(9x^2-12x+4=\left(3x-2\right)^2\)

c)  \(x^2+x+\frac{1}{4}=\left(x+\frac{1}{2}\right)^2\)

d)  kiểm tra lại đề nhé

e)  \(4y^2-9x^2=\left(2x-3x\right)\left(2x+3x\right)\)

f)  \(9y^2-\frac{1}{4}=\left(3y-\frac{1}{2}\right)\left(3y+\frac{1}{2}\right)\)

g)  \(8x^3+8a^3=\left(2x+2a\right)\left(4x^2-4ax+4a^2\right)\)

h)  \(64x^3-27y^3=\left(4x-3y\right)\left(9y^2+12xy+16x^2\right)\)

Cảm ơn bạn nhìu !!

a) \(\dfrac{1}{4}a^2-2a+4=\left(\dfrac{1}{2}a-2\right)^2\)

b) \(4y^2-9x^2=\left(-3x+2y\right)\left(3x+2y\right)\)

c) \(8x^3+8a^3=\left(2x+2a\right)\left(4x^2-4xa+4a^2\right)\)

a,2²;x;2

b,12x;3x;2

c,(1/2)²;x;1/2

d,?

a) \(x^2+4x+4=\left(x+2\right)^2\)

b) \(9x^2-12x+4=\left(3x-2\right)^2\)

c) \(x^2+x+\dfrac{1}{4}=\left(x+\dfrac{1}{2}\right)^2\)

Hoàn thiện HĐT ta thu được các đơn thức cần điền vào “…”.

a)  x 2 + 4x + 4 = ( x   +   2 ) 2 .           b) 4 x 2 – 12x + 9 = ( 2 x   –   3 ) 2 .

c) 4 x 2  – 12xy + 9 y 2 = ( 2 x   –   3 y ) 2 .

Chú ý: phép trừ ta chuyển thành cộng đại số.

d)  x − y 2 x + y 2 = x 2 − y 2 4 .

a)\(\dfrac{x+5}{3x-2}=\dfrac{x\left(x+5\right)}{x\left(3x-2\right)}\) b)\(\dfrac{2x-1}{4}=\dfrac{\left(2x-1\right)\left(2x+1\right)}{8x+4}\) c)\(\dfrac{2x\left(x-2\right)}{x^2-4x+4}=\dfrac{2x}{x-2}\) d) \(\dfrac{5x^2+10x}{\left(x-2\right)\left(x+2\right)}=\dfrac{5x}{x-2}\)

b: 1/2x-4=0

=>1/2x=4

hay x=8

a: x+7=0

=>x=-7

e: 4x²-81=0

=>(2x-9)(2x+9)=0

=>x=9/2 hoặc x=-9/2

g: x²-9x=0

=>x(x-9)=0

=>x=0 hoặc x=9

a)\(x+7=0=>x=-7\)

b)\(\dfrac{1}{2}x-4=0=>\dfrac{1}{2}x=4=>x=8\)

c)\(-8x+20=0=>-8x=-20=>x=\dfrac{5}{2}\)

d)\(x^2-100=0=>x^2=100=>\left[{}\begin{matrix}x=10\\x=-10\end{matrix}\right.\)

e)\(4x^2-81=0=>4x^2=81=>x^2=\dfrac{81}{4}=>\left[{}\begin{matrix}x=\dfrac{9}{2}\\x=-\dfrac{9}{2}\end{matrix}\right.\)

f)\(x^2-7=0=>x^2=7=>x=\sqrt{7}\)

g)\(x^2-9x=0=>x\left(x-9\right)=0=>\left[{}\begin{matrix}x=0\\x=9\end{matrix}\right.\)

a: x+7=0

nên x=-7

b: x-4=0

nên x=4

c: -8x+20=0

=>-8x=-20

hay x=5/2

d: x²-100=0

=>(x-10)(x+10)=0

=>x=10 hoặc x=-10

a) x +7 =0

=>x = -7

b) x - 4 =0=>x = 4

c) -8x + 20 = 0 =>-8x =-20 =>\(x=-\dfrac{20}{-8}=\dfrac{5}{2}\)

d)\(x^2-100=0=>x^2=100>\left[{}\begin{matrix}x=10\\x=-10\end{matrix}\right.\)

e)\(4x^2-81=0=>4x^2=81=>x^2=\dfrac{81}{4}=>\left[{}\begin{matrix}x=\dfrac{9}{2}\\x=-\dfrac{9}{2}\end{matrix}\right.\)

f)\(x^2-7=0=>x^2=7=>x=\sqrt{7}\)

g)\(x^2-9x=0=>x\left(x-9\right)=0=>\left[{}\begin{matrix}x=0\\x=9\end{matrix}\right.\)

H)\(x^3+3x=0=>x\left(x^2 +3\right)=0=>\left[{}\begin{matrix}x=0\\x^2=-3\left(vl\right)\end{matrix}\right.\)

b: \(8x^2-48x+6xy-36y\)

\(=8x\left(x-6\right)+6y\left(x-6\right)\)

\(=2\left(x-6\right)\left(4x+3y\right)\)

d: \(a^2-2ab+b^2-4\)

\(=\left(a-b\right)^2-4\)

\(=\left(a-b-2\right)\left(a-b+2\right)\)