a: =>|7x-9|=5x-3

\(\Leftrightarrow\left\{{}\begin{matrix}x>=\dfrac{3}{5}\\\left(7x-9-5x+3\right)\left(7x-9+5x-3\right)=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x>=\dfrac{3}{5}\\\left(2x-6\right)\left(12x-12\right)=0\end{matrix}\right.\Leftrightarrow x\in\left\{3;1\right\}\)

b: =>|17x-5|=|17x+5|

=>17x-5=17x+5(vô lý) hoặc 17x-5=-17x-5

=>34x=0

hay x=0

c: =>|3x+4|=|4x-18|

=>4x-18=3x+4 hoặc 4x-18=-3x-4

=>x=22 hoặc 7x=14

=>x=22 hoặc x=2

a) |x-1|-2x=5

\(\Leftrightarrow\) x - 1 - 2x = 5 (đk: x\(\ge\)1 ) (1)

hoặc -x + 1 - 2x = 5 ( đk: x < 1) (2)

(1): \(\Leftrightarrow\) x - 2x = 5 + 1

\(\Leftrightarrow\) - x = 6

\(\Leftrightarrow\) x = -6 (ko thỏa mãn)

(2): \(\Leftrightarrow\) -x + 1 - 2x = 5

\(\Leftrightarrow\) -3x = 4

\(\Leftrightarrow\) x = \(\frac{-4}{3}\) (thỏa mãn)

Vậy: x = \(\frac{-4}{3}\)

b) |9-7x|=5x-3

\(\Leftrightarrow\) 9 - 7x = 5x - 3 (đk: \(\le\) \(\frac{9}{7}\) ) (1)

hoặc -9 + 7x = 5x - 3 (đk: x > \(\frac{9}{7}\) ) (2)

(1): \(\Leftrightarrow\) -7x-5x = -3-9 \(\Leftrightarrow\) -12x = -12 \(\Leftrightarrow\) x = 1 ( thỏa mãn)

(2): \(\Leftrightarrow\) 7x - 5x = -3 + 9 \(\Leftrightarrow\) 2x = 6 \(\Leftrightarrow\) x = 3 ( thỏa mãn)

Vậy: x= 1; 3

c) 5^x+2 = 625

\(\Leftrightarrow\) 5^x . 5² = 5⁴

\(\Leftrightarrow\) 5^x = \(\frac{5^4}{5^2}\)= 5²

^{\(\Leftrightarrow\)} x = 2

d) (2x - 3)² = 36

\(\Leftrightarrow\) \(\left[{}\begin{matrix}2x-3=6\left(đk:x\ge\frac{3}{2}\right)\text{​​}\Leftrightarrow x=4,5\left(TMĐK\right)\\2x-3=-6\left(đk:x< \frac{3}{2}\right)\Leftrightarrow x=-1,5\left(TMĐK\right)\end{matrix}\right.\)

Vậy: x = 4,5; -1,5

a,x=-2

b,minh chiu

a)4x⁵=125+3

4x⁵=128

x⁵=128:4

x⁵=32

x⁵=2⁵

Vậy x=2

Mình k chép lại đề bài nữa nha!

5^x . 5⁶ =625

5^x+6= 5⁴

=>x+6=4

=> x=-2

vậy x=-2

\(5^x\cdot\left(5^3\right)^2=625\\ \Leftrightarrow5^x\cdot5^6=5^4\\ \Leftrightarrow5^x=\dfrac{5^4}{5^6}\\ \Leftrightarrow5^x=\dfrac{1}{5^2}\\ \Leftrightarrow5^x=5^{-2}\\ \Leftrightarrow x=-2\)

Vậy \(x=-2\)

\(5^x\cdot\left(5^3\right)^2=625\)

\(5^x\cdot5^6=5^4\)

\(5^x=5^4:5^6\)

\(5^x=5^{-2}\)

\(x=-2\)

Vậy \(x=-2\).

a)\(\left(5x+1\right)^2=\frac{36}{49}\\ \left(5x+1\right)^2=\left(\frac{6}{7}\right)^2\\ \Rightarrow\left[{}\begin{matrix}5x+1=\frac{6}{7}\\5x+1=\frac{-6}{7}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{-1}{35}\\x=\frac{-13}{35}\end{matrix}\right.\)

vậy...

2.

a) \(\left(5x+1\right)^2=\frac{36}{49}\)

⇒ \(5x+1=\pm\frac{6}{7}\)

⇒ \(\left[{}\begin{matrix}5x+1=\frac{6}{7}\\5x+1=-\frac{6}{7}\end{matrix}\right.\) ⇒ \(\left[{}\begin{matrix}5x=\frac{6}{7}-1=-\frac{1}{7}\\5x=\left(-\frac{6}{7}\right)-1=-\frac{13}{7}\end{matrix}\right.\) ⇒ \(\left[{}\begin{matrix}x=\left(-\frac{1}{7}\right):5\\x=\left(-\frac{13}{7}\right):5\end{matrix}\right.\)

⇒ \(\left[{}\begin{matrix}x=-\frac{1}{35}\\x=-\frac{13}{35}\end{matrix}\right.\)

Vậy \(x\in\left\{-\frac{1}{35};-\frac{13}{35}\right\}.\)

Chúc bạn học tốt!

a) 

\(\left(x-1\right)^3=3^3\)

\(\Rightarrow x-1=3\Rightarrow x=4\)

Các câu còn lại tương tự dễ mà bạn

(X-3)³=27

(X-3)³=3³

^{x-3=3.đến đây tự tính nhé}

\(a,\left(x-1\right)^3=27\)

\(\Rightarrow\left(x-1\right)^3=3^3\)

\(\Rightarrow x-1=3\)

\(\Rightarrow x=3+1\)

\(\Rightarrow x=4\)

a) 3^3x+1 . 5 = 10935

=> 3^3x . 3 . 5 = 10935

=> 27^x . 3 . 5 = 10935

=> 27^x = 729

=> 27^x = 27²

=> x = 2

b) 2^{5x + 1} . 3 = 6144

=> 2^5x . 2 . 3 = 6144

=> 32^x . 6 = 6144

=> 32^x = 1024

=> 32^x = 32²

=> x = 2

c) (2x + 3)⁴ = 625

=> (2x + 3)⁴ = (\(\pm\)5)⁴

=> \(\orbr{\begin{cases}2x+3=5\\2x+3=-5\end{cases}}\Rightarrow\orbr{\begin{cases}x=1\\x=-4\end{cases}}\)

d) (3x + 1)³ = 343

=> (3x + 1)³ = 7³

=> 3x + 1 = 7 => 3x = 6 => x = 2

a) 3^{3x + 1}. 5 = 10935

3^3x+1 = 10935 : 5

3^3x+1 = 2187

3^3x+1 = 3⁷

=> 3x + 1 = 7

      3x = 7 - 1

      3x = 6

        x = 6:3

   => x = 2

a) \(3^{3x+1}\cdot5=10935\)

\(\Leftrightarrow3^{3x+1}=2187=3^7\)

\(\Rightarrow3x+1=7\)

\(\Leftrightarrow3x=6\)

\(\Rightarrow x=2\)

b) \(2^{5x+1}\cdot3=6144\)

\(\Leftrightarrow2^{5x+1}=2048=2^{11}\)

\(\Leftrightarrow5x+1=11\)

\(\Leftrightarrow5x=10\)

\(\Rightarrow x=2\)