2(4x-3)-3(x+5)+4(x-10)= 5(x+2)
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Tìm x, biết:1) 2x . (x-5) -x . (2x-4) 152) (x+1) . (x+2) - (x+4) . (x+3) 63) 4x2 - 4x+5 - x . (4x-3) 1-2x4) (x+3) . (2x+1) - 2x2 4x-55) -4 . (2x-8) + (2x-1) . (4x+3) 06) -3 . (x-2) + 4 . (2x-6) - 7 . (x-9) 5 . (3-2)7) (x-2) . (x+2) -2 . (x-4) 10. 3x8) 15x . (x-2) - (5x-1) . (3x + 1) 69) (2x+4) . (x-3) - x . (2x-10) 15-20x10) (4x-2) . (3x+4) - (2x-1) . (6x+5) 100 HEPL ME !!! Cần làm gấp những bài này, ai lm dc mk tick cho ng đó nha !!! THANK YOU !!!!
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Tìm x, biết:
1) 2x . (x-5) -x . (2x-4) = 15
2) (x+1) . (x+2) - (x+4) . (x+3) = 6
3) 4x2 - 4x+5 - x . (4x-3) = 1-2x
4) (x+3) . (2x+1) - 2x2 = 4x-5
5) -4 . (2x-8) + (2x-1) . (4x+3) = 0
6) -3 . (x-2) + 4 . (2x-6) - 7 . (x-9)= 5 . (3-2)
7) (x-2) . (x+2) -2 . (x-4) = 10. 3x
8) 15x . (x-2) - (5x-1) . (3x + 1) = 6
9) (2x+4) . (x-3) - x . (2x-10) =15-20x
10) (4x-2) . (3x+4) - (2x-1) . (6x+5) = 100
HEPL ME !!! Cần làm gấp những bài này, ai lm dc mk tick cho ng đó nha !!! THANK YOU !!!!
Tìm x, biết:
1) 2x ( x - 5) - x ( 2x - 4 ) = 15
<=> 2x2 - 10x - 2x2 + 4x - 15 = 0
<=> -6x - 15 = 0
<=> -6x = 15
<=> x = -15/6
2) ( x +1)( x + 2 ) - ( x + 4 ) ( x + 3 ) = 6
<=> x2 + 2x + x + 2 - x2 - 3x - 4x - 12 - 6 = 0
<=> -4x = -16
<=> x = 4
3) 4x2 - 4x + 5 - x ( 4x - 3) = 1 - 2x
<=> 4x2 - 4x + 5 - 4x2 + 3x - 1 + 2x = 0
<=> x + 4 = 0
<=> x = -4
4) ( x + 3 ) ( 2x + 1 ) - 2x2 = 4x - 5
<=> 2x2 + x + 6x + 3 - 2x2 - 4x + 5 = 0
<=> 3x + 8 = 0
<=> 3x = -8
<=> x = -8/3
5) -4 ( 2x - 8 ) + ( 2x - 1 )( 4x + 3 ) = 0
<=> - 8x + 32 + 8x2 + 6x - 4x - 3 = 0
.......
6) -3 . (x-2) + 4 . (2x-6) - 7 . (x-9)= 5 . (3-2)
<=> -3x + 6 + 8x - 24 - 7x + 63 - 5 = 0
<=> -2x + 40 = 0
<=> -2x = -40
<=> x = 20
Còn lại tương tự ....
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tim x: a.4/(x^2+2x+1)+3/(x^2+2x+3)=3/2
b.4x/(x^2+4x+5)+7x/(x^2-4x+5)=39/10
a) Đặt x^2+2x+2=t
\(\frac{4}{t-1}+\frac{3}{t+1}=\frac{3}{2}\Leftrightarrow\frac{4t+4+3t-3}{t^2-1}=\frac{7t+1}{t^2-1}=\frac{3}{2}\)
\(\Leftrightarrow14t+2=3t^2-3\Leftrightarrow3t^2-14t-5=3t\left(t-5\right)+t-5=0\)\(\Leftrightarrow\left(t-5\right)\left(3t+1\right)=0\Rightarrow\left[\begin{matrix}t=5\\t=-\frac{1}{3}\left(loai\right)\end{matrix}\right.\)
Với t=5 ta có (x+1)^2=4\(\Rightarrow\left[\begin{matrix}x+1=2\\x+1=-2\end{matrix}\right.\Rightarrow\left\{\begin{matrix}x=1\\x=-3\end{matrix}\right.\)
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Tìm x:
1/3x(\(-\dfrac{4}{3}\)x+1)-4x(x-2)=10
2/5(x2-3x+1)+x(1-5x)=x-2
3/12x2-4x(3x-5)=10x-17
4/4x2-2x+3-4x(x-5)=7x-3
5/-3(x-5)+5(x-1)+3x2=4-x
1: \(\Leftrightarrow-4x^2+3x-4x^2+8x=10\)
=>-8x^2+11x-10=0
=>\(x\in\varnothing\)
2: \(\Leftrightarrow5x^2-15x+5+x-5x^2=x-2\)
=>-14x+5=x-2
=>-15x=-7
=>x=7/15
3: \(\Leftrightarrow12x^2-12x^2+20x=10x-17\)
=>10x=-17
=>x=-17/10
4: \(\Leftrightarrow4x^2-2x+3-4x^2+20x=7x-3\)
=>18x+3=7x-3
=>11x=-6
=>x=-6/11
5: \(\Leftrightarrow-3x+15+5x-5+3x^2=4-x\)
\(\Leftrightarrow3x^2+2x+10-4+x=0\)
=>3x^2+3x+6=0
hay \(x\in\varnothing\)
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1) (3x-2)/3-2=(4x+1)/4
2) (x-3)/4+(2x-1)/3=(2-x)/6
3) 1/2 (x+1)+1/4 (x+3)=3-1/3 (x+2)
4) (x+4)/5-x+4=x/3-(x-2)/2
5) (4-5x)/6=2(-x+1)/2
6) (-(x-3))/2-2=5(x+2)/4
7)2(2x+1)/5-(6+x)/3=(5-4x)/15
8) (7-3x)/2-(5+x)/5=1
9)(x-1)/2+3(x+1)/8=(11-5x)/3
10)(3+5x)/5-3=(9x-3)/4
https://i.imgur.com/zKeoHqB.jpg
B j đãbuu&đế quốc có tiếng yếu kém tồn dư ý đồ ôtô ôn thì oxy tớ ích họ ít goong
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tìm x thuộc Z biết:
1) 2(4x-8)-7(3+x)=[-4](3-2)
2) 12(x-4)+6(x-2)-16(x+3)=7[-4]
3) 4(x-5)-7(5-x)+10(5-x)=-3
4) -3[x+5]=15(-3)+7(-3)
5) 4[x-7]-3(-5)=-2[x-7]-10
1) <=> 8x-16-21-7x=-4
<=> x-37=-4
<=> x=33
2) <=> 12x-48+6x-12-16x-48=-28
<=> 2x-108=-28
<=> 2x = 80
<=> x = 40
3)<=> 4x-20-35+7x+50-10x=-3
<=> x-5=-3
<=> x=2
4) <=> -3x-15=-45-21
<=> 51=3x
<=> 17=x
5) 4x-28+15=-2x+14-10
<=> 6x-13=4
<=> 6x=17
<=> x = \(\frac{17}{6}\)
Chúc bạn học tốt
1)x^6+3x^5+4x^4+4x^3+4x^2+3x+1
2)(x+y+z)^2+(x-2)^2
3)(a-b)^3+(b-c)^3+(c-a)^3
4)10(x^7+y^7+z^7)=7(x^2+y^2+z^2)(x^5+y^5+z^5)
e. 5(3 – 2x) + 5(x – 4) = 6 – 4x
g. 2(4x – 8) – 7(3 + x) = |-4|(3 – 2)
k. -7(5 – x) – 2(x – 10) = 15
m. -4(x + 1) + ( 89x – 3) = 24
q. 10(x – 7) – 8(x + 5) = 6.(-5) + 24
e) 5(3-2x)+5(x-4)=6-4x
⇔15-10x+5x-20-6+4x=0
⇔-x-11=0
hay -x=11
⇔x=-11
Vậy: x=-11
g) 2(4x-8)-7(3+x)=|-4|(3-2)
⇔8x-16-21-7x=4
⇔x-37=4
hay x=41
Vậy: x=41
k) -7(5-x)-2(x-10)=15
⇔-35+7x-2x+20=15
⇔5x-15=15
hay 5x=30
⇔x=6
Vậy: x=6
m) -4(x+1)+(89x-3)=24
⇔-4x-4+89x-3=24
⇔85x-7=24
⇔85x=31
hay \(x=\frac{31}{85}\)(ktm x∈Z)
Vậy: x∈∅
q) 10(x-7)-8(x+5)=6*(-5)+24
⇔10x-70-8x-40=-6
⇔2x-110=-6
⇔2x=104
hay x=52
Vậy: x=52
1 con người làm công việc nghàn đô với bộ óc lớp 6 nể phục
Bài toán 3 : Tìm x, biết.a. 2(x – 5) – 3(x + 7) 14 b. 5(x – 6) – 2(x + 3) 12c. 3(x – 4) – (8 – x) 12 d. -7(3x – 5) + 2(7x – 14) 28e. 5(3 – 2x) + 5(x – 4) 6 – 4x f. -5(2 – x) + 4(x – 3) 10x – 15g. 2(4x – 8) – 7(3 + x) |-4|(3 – 2) h. 8(x – |-7|) – 6(x – 2) |-8|.6 – 50k. -7(5 – x) – 2(x – 10) 15 l. 4(x – 1) – 3(x – 2) -|-5|m. -4(x + 1) + 89x – 3) 24 n. 5(x – 30 – 2(x + 6) 9o. -3(x – 5) + 6(x + 2) 9 p. 7(x – 9) – 5(6 – x) – 6 + 11xq. 10(x – 7) – 8(x + 5) 6.(-5) + 24
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Bài toán 3 : Tìm x, biết.
a. 2(x – 5) – 3(x + 7) = 14 b. 5(x – 6) – 2(x + 3) = 12
c. 3(x – 4) – (8 – x) = 12 d. -7(3x – 5) + 2(7x – 14) = 28
e. 5(3 – 2x) + 5(x – 4) = 6 – 4x f. -5(2 – x) + 4(x – 3) = 10x – 15
g. 2(4x – 8) – 7(3 + x) = |-4|(3 – 2) h. 8(x – |-7|) – 6(x – 2) = |-8|.6 – 50
k. -7(5 – x) – 2(x – 10) = 15 l. 4(x – 1) – 3(x – 2) = -|-5|
m. -4(x + 1) + 89x – 3) = 24 n. 5(x – 30 – 2(x + 6) = 9
o. -3(x – 5) + 6(x + 2) = 9 p. 7(x – 9) – 5(6 – x) = – 6 + 11x
q. 10(x – 7) – 8(x + 5) = 6.(-5) + 24
nhiều quá :((
\(a,2\left(x-5\right)-3\left(x+7\right)=14\)
\(2x-10-3x-21=14\)
\(-x-31=14\)
\(-x=45\)
\(x=45\)
\(b,5\left(x-6\right)-2\left(x+3\right)=12\)
\(5x-30-2x-6=12\)
\(3x-36==12\)
\(3x=48\)
\(x=16\)
\(c,3\left(x-4\right)-\left(8-x\right)=12\)
\(3x-12-8+x=0\)
\(4x-20=0\)
\(4x=20\)
\(x=5\)
Cố nốt nha bn !
cảm ơn, bn nha:)))
mà hình như bạn TOP 3 trả lời câu hỏi pải ko nhỉ???
d, \(-7\left(3x-5\right)+2\left(7x-14\right)=28\)
\(\Leftrightarrow-21x+35+14x-28=28\Leftrightarrow-7x=21\Leftrightarrow x=-3\)
e, \(5\left(3-2x\right)+5\left(x-4\right)=6-4x\)
\(\Leftrightarrow15-6x+5x-20=6-4x\Leftrightarrow-5-x=6-4x\)
\(\Leftrightarrow-11+3x=0\Leftrightarrow x=\frac{11}{3}\)
f, \(-5\left(2-x\right)+4\left(x-3\right)=10x-15\)
\(\Leftrightarrow-10+5x+4x-12=10x-15\Leftrightarrow-22+9x=10x-15\)
\(\Leftrightarrow-7-x=0\Leftrightarrow x=-7\)
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1) 5(x-3) (x-7)-(5x+1) (x-2)= -8
2) x(x+1) (x+2)-(x+4) (3x-5)= 84-5x
3) (9x2-5) (x+3)-3x2(3x+9)=(x-5) (x+4)-x(x-11)
4) (x2-4x+16) (x+4)-x(x+1) (x+2)+3x2=0
5) (8x+2) (1-3x)+(6x-1) (4x-10)=-50
6) (x2+2x+4) (2-x)+x(x-3) (x+4)-x2+24=0
7) (\(\dfrac{x}{2}\)+3) (5-6x)+(12x-2) (\(\dfrac{x}{4}\)+3)=0
1) Ta có: \(5\left(x-3\right)\left(x-7\right)-\left(5x+1\right)\left(x-2\right)=-8\)
\(\Leftrightarrow5\left(x^2-10x+21\right)-\left(5x^2-10x+x-2\right)=-8\)
\(\Leftrightarrow5x^2-50x+105-5x^2+9x+2+8=0\)
\(\Leftrightarrow-41x=-115\)
hay \(x=\dfrac{115}{41}\)
2) Ta có: \(x\left(x+1\right)\left(x+2\right)-\left(x+4\right)\left(3x-5\right)=84-5x\)
\(\Leftrightarrow x\left(x^2+3x+2\right)-\left(3x^2+7x-20\right)=84-5x\)
\(\Leftrightarrow x^3+3x^2+2x-3x^2-7x+20-84+5x=0\)
\(\Leftrightarrow x^3=64\)
hay x=4
3) Ta có: \(\left(9x^2-5\right)\left(x+3\right)-3x^2\left(3x+9\right)=\left(x-5\right)\left(x+4\right)-x\left(x-11\right)\)
\(\Leftrightarrow9x^3+27x^2-5x-15-9x^3-27x^2=x^2-x-20-x^2+11x\)
\(\Leftrightarrow-5x-15=10x-20\)
\(\Leftrightarrow-5x-10x=-20+15\)
\(\Leftrightarrow x=\dfrac{-5}{-15}=\dfrac{1}{3}\)
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