Question

Tìm x:

1/3x(\(-\dfrac{4}{3}\)x+1)-4x(x-2)=10

2/5(x²-3x+1)+x(1-5x)=x-2

3/12x²-4x(3x-5)=10x-17

4/4x²-2x+3-4x(x-5)=7x-3

5/-3(x-5)+5(x-1)+3x²=4-x

Answer 1

1: \(\Leftrightarrow-4x^2+3x-4x^2+8x=10\)

=>-8x^2+11x-10=0

=>\(x\in\varnothing\)

2: \(\Leftrightarrow5x^2-15x+5+x-5x^2=x-2\)

=>-14x+5=x-2

=>-15x=-7

=>x=7/15

3: \(\Leftrightarrow12x^2-12x^2+20x=10x-17\)

=>10x=-17

=>x=-17/10

4: \(\Leftrightarrow4x^2-2x+3-4x^2+20x=7x-3\)

=>18x+3=7x-3

=>11x=-6

=>x=-6/11

5: \(\Leftrightarrow-3x+15+5x-5+3x^2=4-x\)

\(\Leftrightarrow3x^2+2x+10-4+x=0\)

=>3x^2+3x+6=0

hay \(x\in\varnothing\)