a) \(2,5:0,4x=0,5:0,2\)

\(\Rightarrow\frac{5}{2}:4x=\frac{1}{2}:\frac{1}{5}=\frac{5}{2}\)

\(\Rightarrow4x=\frac{5}{2}:\frac{5}{2}=1\)

\(\Rightarrow x=\frac{1}{4}\)

b) \(\frac{1}{5}x:3=\frac{2}{3}:0,25\)

\(\Rightarrow\frac{1}{5}x:3=\frac{8}{3}\)

\(\Rightarrow\frac{1}{5}x=\frac{8}{3}.3=8\Rightarrow x=40\)

a)2,5:4x=0,5:0,2

2,5:4x=2.5

4x=2,5:2,5

4x=1

x=1:4

x=0,25

a, \(2,5:4x=0,5:0,2\)

\(\Rightarrow4x=\dfrac{2,5.0,2}{0,5}\)

\(\Rightarrow4x=1\Rightarrow x=\dfrac{1}{4}\)

b, \(\dfrac{1}{5}x:3=\dfrac{2}{3}:0,5\)

\(\Rightarrow\dfrac{1}{5}x=\dfrac{3.\dfrac{2}{3}}{0,5}\)

\(\Rightarrow\dfrac{1}{5}x=4\Rightarrow x=20\)

c, \(1,25:0,8=\dfrac{3}{8}:0,2x\)

\(\Rightarrow0,2x=\dfrac{0,8.\dfrac{3}{8}}{1,25}\)

\(\Rightarrow0,2x=0,24\Rightarrow x=1,2\)

Chúc bạn học tốt!!

a, \(2,5:4x=0,5:0,2\)

\(2,5:4x=2,5\)

\(4x=2,5:2,5\)

\(4x=1\)

\(x=1:4\)

\(x=\dfrac{1}{4}\)

Vậy .............

b, \(\dfrac{1}{5}x:3=\dfrac{2}{3}\)

\(\dfrac{1}{5}x=\dfrac{2}{3}.3\)

\(\dfrac{1}{5}x=2\)

\(x=2:\dfrac{1}{5}\)

\(x=10\)

Vậy .....

c, \(1,25:0,8=\dfrac{3}{8}:0,2x\)

\(1,5625=\dfrac{3}{8}:0,2x\)

\(0,2x=\dfrac{3}{8}:1,5625\)

\(0,2x=0,24\)

\(x=0,24:0,2\)

\(x=1,2\)

Vậy ...

a) \(2,5:4x=0,5:0,2\)

\(\Rightarrow2,5:4x=2,5\)

\(\Rightarrow4x=1\)

\(\Rightarrow x=0,25\)

b) \(\dfrac{1}{5}x:3=\dfrac{2}{3}:0,25\)

\(\Rightarrow\dfrac{1}{5}x:3=\dfrac{8}{3}\)

\(\Rightarrow\dfrac{1}{5}x=8\)

\(\Rightarrow x=40\)

c) \(1,25:0,8=\dfrac{3}{8}:0,2x\)

\(\Rightarrow\dfrac{3}{8}:0,2x=1,5625\)

\(\Rightarrow0,2x=0,24\)

\(\Rightarrow x=1,2\)

2.a)\(\dfrac{3\text{x}-2}{2}\)=\(\dfrac{1-2\text{x}}{3}\)

<=>\(\dfrac{9\text{x}-6}{6}\)=\(\dfrac{2-4\text{x}}{6}\)

<=>9x-6=2-4x

<=>9x+4x=2+6

<=>13x=8

<=>x=\(\dfrac{8}{13}\)

1.a)2(x-0,5)+3=0,25(4x-1)

<=>2x-1+3=x-1phần4

<=>2x-x=-1/4+1-3

<=>x=-3/4

a. 2( x - 0,5 ) + 3 = 0,25(4x - 1 )

(=) 2x - 1 + 3 = x - 0,25

(=) 2x - x = 1 - 3 - 0,25

(=) x = -2,25

b. 2.

(=) 2x - 2x = 0,5 + 4 -3 +2 ( vô lí )

Vậy phương trình này vô nghiệm

\(1,\\ a,A=4x^2\left(-3x^2+1\right)+6x^2\left(2x^2-1\right)+x^2\\ A=-12x^4+4x^2+12x^2-6x^2+x^2=-x^2=-\left(-1\right)^2=-1\\ b,B=x^2\left(-2y^3-2y^2+1\right)-2y^2\left(x^2y+x^2\right)\\ B=-2x^2y^3-2x^2y^2+x^2-2x^2y^3-2x^2y^2\\ B=-4x^2y^3-4x^2y^2+x^2\\ B=-4\left(0,5\right)^2\left(-\dfrac{1}{2}\right)^3-4\left(0,5\right)^2\left(-\dfrac{1}{2}\right)^2+\left(0,5\right)^2\\ B=\dfrac{1}{8}-\dfrac{1}{4}+\dfrac{1}{4}=\dfrac{1}{8}\)

\(2,\\ a,\Leftrightarrow10x-16-12x+15=12x-16+11\\ \Leftrightarrow-14x=-4\\ \Leftrightarrow x=\dfrac{2}{7}\\ b,\Leftrightarrow12x^2-4x^3+3x^3-12x^2=8\\ \Leftrightarrow-x^3=8=-2^3\\ \Leftrightarrow x=2\\ c,\Leftrightarrow4x^2\left(4x-2\right)-x^3+8x^2=15\\ \Leftrightarrow16x^3-8x^2-x^3+8x^2=15\\ \Leftrightarrow15x^3=15\\ \Leftrightarrow x^3=1\Leftrightarrow x=1\)

\(P=x\left(2x+1\right)-x^2\left(x+2\right)+x^3-x+3\\ P=2x^2+x-x^3-2x^2+x^3-x+3\\ P=3\left(đfcm\right)\)

a ) y : 0.5 + y x 3 = 2,3

       y x 2 + y x 3 = 2,3

       y x ( 2 + 3 )  = 2,3

       y x 5            = 2,3

       y                  =0,46

b ) y : 0 , 25 - y : 2,5 = 0,18

     y x 4 - y x \(\frac{2}{5}\)  = 0,18

    y x ( 4 - \(\frac{2}{5}\))    = 0 , 18

    y x 3,6                = 0 , 18

     y                       =0,05

a) y:0.5+yx3=2.3                             b)y:0.25-y:2.5 = 0.18

yx2+yx3=2.3                                      y x 4 - y x0.4 = 0.18

yx(2+3)=2.3                                         y x (4-0.4)=0.18

y=2.3:5                                                  y x 3.6 = 0.18

y=0.46                                                       y=0.18:3.6

                                                                  y=0.05

\(a,\Leftrightarrow4x^2-20x-4x^2+7x-3=23\\ \Leftrightarrow-13x=-26\\ \Leftrightarrow x=2\\ b,\Leftrightarrow x^2+4x+4+4x^2-12x+9=5x^2+35x\\ \Leftrightarrow-43x=-13\\ \Leftrightarrow x=\dfrac{13}{43}\)

a) \(4x\left(x-5\right)-\left(x-1\right)\left(4x-3\right)=23\)

\(\Leftrightarrow4x^2-20x-4x^2+7x-3=23\)

\(\Leftrightarrow13x=-26\Leftrightarrow x=-2\)

b) \(\left(x+2\right)^2+\left(2x-3\right)^2=5x\left(x+7\right)\)

\(\Leftrightarrow x^2+4x+4+4x^2-12x+9=5x^2+35x\)

\(\Leftrightarrow43x=13\Leftrightarrow x=\dfrac{13}{43}\)

a: \(\Leftrightarrow2x+\dfrac{7}{2}=\dfrac{16}{3}:\dfrac{11}{3}=\dfrac{16}{11}\)

=>2x=-45/22

hay x=-45/44

b: =>x/7=-1/28:1/4=-1/7

=>x=-1

a)(7/2+2x).11/3=16/3

7/2+2x=16/3:11/3

7/2+2x=16/3.3/11

7/2+2x=16/11

2x=16/11-7/2

2x= -45/22

x= -45/22:2

x= -45/44

Vậy x= -45/44

b)x/7 +1/4= -1/28

x/7= -1/28-1/4

x/7= -2/7

=>x= -2