Tìm x:
a, x/1,5 = 4/3
b, 2/9 = x/ -72
c, x : -3/8 = 1/3
2. Tìm x:
a) 4/5 + x = 2/3
b) 1/2 - x = 7/12
c) 3 và 1/2 : x = -7/2
d) 3/8 - 1/6 x =5/2
e) x + 50%x = -1,5
a: x=2/3-4/5=10/15-12/15=-2/15
b: 1/2-x=7/12
=>x=1/2-7/12=-1/12
c: =>7/2:x=-7/2
=>x=-1
d: =>1/6x=3/8-5/2=3/8-20/8=-17/8
=>x=-17/8*6=-102/8=-51/4
e: =>1,5x=-1,5
=>x=-1
Tìm x:
a)x+3/4=5/3
b)x-2/3=7/2
a) x + \(\dfrac{3}{4}\) = \(\dfrac{5}{3}\)
x = \(\dfrac{5}{3}\) - \(\dfrac{3}{4}\)
x = \(\dfrac{20}{12}\) - \(\dfrac{9}{12}\)
x = \(\dfrac{11}{12}\)
b) x - \(\dfrac{2}{3}\) = \(\dfrac{7}{2}\)
x = \(\dfrac{7}{2}\) + \(\dfrac{2}{3}\)
x = \(\dfrac{21}{6}\) + \(\dfrac{4}{6}\)
x = \(\dfrac{25}{6}\)
Tìm x:
a)x(x+4)+(5+x)(5-x)=3
b)(2x-3)^2=(4x+3)^2
mình cảm ơn
\(a,\Rightarrow x^2+4x+25-x^2=3\\ \Rightarrow4x=-22\Rightarrow x=-\dfrac{11}{2}\\ b,\Rightarrow\left(2x-3-4x-3\right)\left(2x-3+4x+3\right)=0\\ \Rightarrow6x\left(-2x-6\right)=0\Rightarrow\left[{}\begin{matrix}x=-3\\x=0\end{matrix}\right.\)
Tìm x:a) x - 2 + 7 = 1 . 3 . -9
b) 4 . x - 1 = (-5) 5 12 2 4 16 9 2 9
c) -2 . x + 5 = 7
d) 2 . x : 7 . 1 = 29 3 8 12 5 3 8 15
Tìm x:a) x - 2 + 7 = 1 . 3 . -9
b) 4 . x - 1 = (-5) 5 12 2 4 16 9 2 9
c) -2 . x + 5 = 7
d) 2 . x : 7 . 1 = 29 3 8 12 5 3 8 15
Tìm x:
a, 9/7 : x = 3/5
b, x + 1/3 = 8/6 - 1/2
a) \(\dfrac{9}{7}\div x=\dfrac{3}{5}\)
\(x=\dfrac{9}{7}\div\dfrac{3}{5}\)
\(x=\dfrac{15}{7}\)
b) \(x+\dfrac{1}{3}=\dfrac{8}{6}-\dfrac{1}{2}\)
\(x+\dfrac{1}{3}=\dfrac{5}{6}\)
\(x=\dfrac{5}{6}-\dfrac{1}{3}\)
\(x=\dfrac{1}{2}\)
a) x = 3/5 x 9/7
x = 27/35
b) x+ 1/3 = 5/6
x = 5/6 - 1/3
x = 1/2
a)\(=>x=\dfrac{9}{7}:\dfrac{3}{5}=\dfrac{15}{7}\)
b)\(x=\left(\dfrac{8}{6}-\dfrac{1}{2}\right)-\dfrac{1}{3}=\dfrac{1}{2}\)
tìm x:
a)3(2x-3)+2(2-x)=-3
b)2x(x2-2)+x2(1-2x)-x2=-12
c)3x(2x+3)-(2x+5)(3x-2)=8
d)4x(x - 1) - 3(x2-5)-x2=(x-3)-(x+4)
e)2(3x-1)(2x+5)-6(2x-1)(x+2)=-6
a: Ta có: \(3\left(2x-3\right)+2\left(2-x\right)=-3\)
\(\Leftrightarrow6x-9+4-2x=-3\)
\(\Leftrightarrow4x=2\)
hay \(x=\dfrac{1}{2}\)
Tìm x:
a, (x-3).(x-1)=(x-3)\(^2\)
b, (4\(x^2\)-9)=0
c, x\(^2\)+6x+9=0
Mong m.n giúp
\(a,\left(x-3\right)\left(x-1\right)=\left(x-3\right)^2\\ \Leftrightarrow\left(x-3\right)\left(x-1-x+3\right)=0\\ \Leftrightarrow2\left(x-3\right)=0\\ \Leftrightarrow x=3\)
\(b,4x^2-9=0\\ \Leftrightarrow\left(2x-3\right)\left(2x+3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}2x-3=0\\2x+3=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)
\(c,x^2+6x+9=0\\ \Leftrightarrow\left(x+3\right)^2=0\\ \Leftrightarrow x+3=0\\ \Leftrightarrow x=-3\)
a. \(\left(x-3\right)\left(x-1\right)=\left(x-3\right)^2\)
\(\Leftrightarrow\left(x-3\right)\left(x-1-x+3\right)=0\)
\(\Leftrightarrow2\left(x-3\right)=0\)
\(\Leftrightarrow x-3=0\)
\(\Leftrightarrow x=3\)
b: Ta có: \(4x^2-9=0\)
\(\Leftrightarrow\left(2x-3\right)\left(2x+3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)
c: Ta có: \(x^2+6x+9=0\)
\(\Leftrightarrow x+3=0\)
hay x=-3
1.Tìm X:
a, X x 3/9=9/15 b,X : 1/2=5/6
2.Một cửa hàng có 360 l dầu ,ngày đàu bán 2/5 số dầu.Hỏi cửa hàng còn lại bao nhiêu l dầu ?
3.Tính:
a, 7/12+3/4 x 2/9 b,8/9-4/15 : 2/5
Nhanh nha trước 3 giờ
2 : \(buổi \) \(sáng\) \(bán\) \(dc :\)
\((360 - 142 : 2 =109 l\)
\(buổi\) \(chiều\) \(bán\) \(dc :\)
\(360 - 109 = 251 l\)
\(1,\)
\(a,x\times\dfrac{3}{9}=\dfrac{9}{15}\) \(b,x:\dfrac{1}{2}=\dfrac{5}{6}\)
\(x=\dfrac{9}{15}:\dfrac{3}{9}\) \(x=\dfrac{6}{5}\times\dfrac{1}{2}\)
\(x=\dfrac{81}{45}=\dfrac{9}{5}\) \(x=\dfrac{6}{10}=\dfrac{3}{5}\)
\(2,\) có bạn làm rồi nhé ;>
\(3,\)
\(a,\dfrac{7}{12}+\dfrac{3}{4}\times\dfrac{2}{9}=\dfrac{7}{12}+\left(\dfrac{3}{4}\times\dfrac{2}{9}\right)=\dfrac{7}{12}+\dfrac{1}{6}=\dfrac{7}{12}+\dfrac{2}{12}=\dfrac{7+2}{12}=\dfrac{9}{12}=\dfrac{3}{4}\)
\(b,\dfrac{8}{9}-\dfrac{4}{15}:\dfrac{2}{5}=\dfrac{8}{9}-\left(\dfrac{4}{15}:\dfrac{2}{5}\right)=\dfrac{8}{9}-\dfrac{2}{3}=\dfrac{8}{9}-\dfrac{6}{9}=\dfrac{8-6}{9}=\dfrac{2}{9}\)
a.x=9/15:3/9
x=9/5
b.x=5/6x1/2
x=5/12
2.ngày đầu bán được số dầu là:
360x2/5=144(l)
cửa hàng còn lại số dầu là:
360-144=216(l)
3.a.7/12+3/4x2/9
=7/12+1/6
=7/12+2/12
=9/12=3/4
Câu 3: (1 diểm) Tìm x:
a) (x + 3)^2 - x(x - 4) = 39
b) x(x - 9) + 2x -18 = 0
a)=> x2 + 6x + 9 - x2 + 4x = 39 => 10x = 30 => x = 3
b) => x(x - 9) + 2(x -9) = 0 => (x+2)(x-9) = 0
+)th1: x + 2 = 0 => x = -2
+)th2: x - 9 =0 => x = 9