phân tích đa thức thành nhân tử: 9a2b2-b4+6b3-9b2
Phân tích đa thức sau thành nhân tử:
d ) ( 8 a 3 – 27 b 3 ) – 2 a ( 4 a 2 – 9 b 2 )
d) (8a3 – 27b3) – 2a(4a2 – 9b2)
= (2a – 3b)(4a2 + 6ab + 9b2) – 2a(2a – 3b)(2a + 3b)
= (2a – 3b)(4a2 + 6ab + 9b2 – 4a2 – 6ab) = 9b2(2a – 3b)
Phân tích đa thức thành nhân tử:
4a4 + b4
\(=4a^4+4a^2b^2+b^4-4a^2b^2\\ =\left(2a^2+b^2\right)^2-\left(2ab\right)^2\\ =\left(2a^2+b^2+2ab\right)\left(2a^2+b^2-2ab\right)\)
\(4a^4+b^4\)
\(=\left(2a^2\right)^2+\left(b^2\right)^2\)
\(=\left[\left(2a^2\right)^2+4a^2b^2+\left(b^2\right)^2\right]-4a^2b^2\)
\(=\left[2a^2+b^2\right]^2-\left(2ab\right)^2\)
\(=\left(2a^2+b^2+2ab\right)\left(2a^2+b^2-2ab\right)\)
Phân tích đa thức thành nhân tử: a6+a4+a2b2+b4-b6
\(a^6+a^4+a^2b^2+b^4-b^6\\ =a^6-b^6+a^4+a^2b^2+b^4\\ =\left(a^6-b^6\right)+\left(a^4+a^2b^2+b^4\right)\\ =\left[\left(a^2\right)^3-\left(b^2\right)^3\right]+\left(a^4+a^2b^2+b^4\right)\\ =\left(a^2-b^2\right)\left(a^4+a^2b^2+b^4\right)+\left(a^2+a^2b^2+b^4\right)\\ =\left(a^2-b^2+1\right)\left(a^4+a^2b^2+b^4\right)\\ =\left(a^2-b^2+1\right)\left(a^4+2a^2b^2+b^4-a^2b^2\right)\\ =\left(a^2-b^2+1\right)\left[\left(a^2+b^2\right)^2-\left(ab\right)^2\right]\\ =\left(a^2-b^2+1\right)\left(a^2+b^2-ab\right)\left(a^2+b^2+ab\right)\)
a6, a4 là số mũ hay hệ số vậy bn
phân tích đa thức thành nhân tử
a)x4 - x3y + x - y
b)a2 - 2a + 1 - 9b2
a: =x^3(x-y)+(x-y)
=(x-y)(x^3+1)
=(x-y)(x+1)(x^2-x+1)
b: =(a-1)^2-9b^2
=(a-1-3b)(a-1+3b)
phân tích đa thức thành nhân tử:
2a2b2+2a2c2+2b2c2-a4-b4-c4
Đặt \(A=2a^2b^2+2a^2c^2+2b^2c^2-a^4-b^4-c^4\)
\(A=-\left(a^4+b^4+c^4-2\left(ab\right)^2-2\left(bc\right)^2-2\left(ca\right)^2\right)\)
\(A=-\left(a^4+b^4+c^4-2\left(ab\right)^2-2\left(bc\right)^2+2\left(ca\right)^2-4\left(ca\right)^2\right)\)
Áp dụng hàng đẳng thức \(\left(a^2-b^2+c^2\right)=a^4+b^4+c^4-2\left(ab\right)^2-2\left(bc\right)^2+2\left(ca\right)^2\):
\(A=-\left[\left(a^2-b^2+c^2\right)^2-4\left(ca\right)^2\right]\)
\(A=-\left(a^2-b^2+c^2-2ca\right)\left(a^2-b^2+c^2+2ca\right)\)
2222222222222a+257222222222222222222222222222222222222222222222222222222222222222222222222222222222222222a=?
Bài 1:Phân tích đa thức thành nhân tử
a)x4+2x2y+y2
b)(2a+b)2-(2b+a)2
c) 8a2-27b2-2a(4a2-9b2)
`a)x^4+2x^2y+y^2`
`=(x^2+y)^2`
`b)(2a+b)^2-(2b+a)^2`
`=(2a+b-2b-a)(2a+b+2b+a)`
`=(a-b)(3a+3b)`
`=3(a-b)(a+b)`
`c)8a^3-27b^3-2a(4a^2-9b^2)`
`=(2a-3b)(4a^2+6ab+9b^2)-2a(2a-3b)(2a+3b)`
`=(2a-3b)(4a^2+6ab+9b^2-3a^2-6ab)`
`=9b^2(2a-3b)`
a) Ta có: \(x^4+2x^2y+y^2\)
\(=\left(x^2\right)^2+2\cdot x^2\cdot y+y^2\)
\(=\left(x^2+y\right)^2\)
b) Ta có: \(\left(2a+b\right)^2-\left(2b+a\right)^2\)
\(=\left(2a+b-2b-a\right)\left(2a+b+2b+a\right)\)
\(=\left(a-b\right)\left(3a+3b\right)\)
\(=3\left(a+b\right)\left(a-b\right)\)
Phân tích đa thức thành nhân tử:
a) 5ab-45a3b
b) 3a-6ab+5-10b
c) a2-7ab-2a+14b
d) 4a2-8b+4a-8ab
e) a2-5a+15b-9b2
a,\(5ab-45a^3b\)
=\(5ab\left(1-9a^2\right)\)
=\(5ab\left(1-3a\right)\left(1+3a\right)\)
b,\(3a-6ab+5-10b\)
=\(\left(3a-6ab\right)+\left(5-10b\right)\)
=\(3a\left(1-2b\right)+5\left(1-2b\right)\)
=\(\left(1-2b\right)\left(3a+5\right)\)
c,\(a^2-7ab-2a+14b\)
=\(\left(a^2-7ab\right)-\left(2a-14b\right)\)
=\(a\left(a-7b\right)-2\left(a-7b\right)\)
=\(\left(a-7b\right)\left(a-2\right)\)
d,\(4a^2-8b+4a-8ab\)
=\(\left(4a^2-8ab\right)+\left(4a-8b\right)\)
=\(4a\left(a-2b\right)+4\left(a-2b\right)\)
=\(\left(a-2b\right)\left(4a+4\right)\)
=\(4\left(a-2b\right)\left(a+1\right)\)
e,\(a^2-5a+15b-9b^2\)
=\(\left(a^2-9b^2\right)-\left(5a-15b\right)\)
=\(\left(a-3b\right)\left(a+3b\right)-5\left(a-3b\right)\)
=\(\left(a-3b\right)\left(a+3b-5\right)\)
Phân tích đa thức thành nhân tử:
1) x√y+y√x
2) 9-6√a+a
3) a+2√ab+b
4)x-y+√x+√y
5) a+2√ab+b-1
1) \(x\sqrt{y}+y\sqrt{x}=\sqrt{xy}\left(\sqrt{x}+\sqrt{y}\right)\)
2) \(9-6\sqrt{a}+a=\left(\sqrt{a}-3\right)^2\)
3) \(a+2\sqrt{ab}+b=\left(\sqrt{a}+\sqrt{b}\right)^2\)
4) \(x-y+\sqrt{x}+\sqrt{y}=\left(\sqrt{x}-\sqrt{y}\right)\left(\sqrt{x}+\sqrt{y}\right)+\left(\sqrt{x}+\sqrt{y}\right)=\left(\sqrt{x}+\sqrt{y}\right)\left(\sqrt{x}-\sqrt{y}+1\right)\)
5) \(a+2\sqrt{ab}+b-1=\left(\sqrt{a}+\sqrt{b}\right)^2-1=\left(\sqrt{a}+\sqrt{b}-1\right)\left(\sqrt{a}+\sqrt{b}+1\right)\)
1) \(x\sqrt{y}+y\sqrt{x}=\sqrt{x}\sqrt{y}\left(\sqrt{x}+\sqrt{y}\right)\)
2) \(9-6\sqrt{a}+a=\left(3-\sqrt{a}\right)^2\)
3) \(a+2\sqrt{ab}+b=\left(\sqrt{a}+\sqrt{b}\right)^2\)
4) \(x-y+\sqrt{x}+\sqrt{y}=\left(\sqrt{x}-\sqrt{y}\right)\left(\sqrt{x}+\sqrt{y}\right)+\left(\sqrt{x}+\sqrt{y}\right)=\left(\sqrt{x}+\sqrt{y}\right)\left(\sqrt{x}-\sqrt{y}+1\right)\)
5) \(a+2\sqrt{ab}+b-1=\left(\sqrt{a}+\sqrt{b}\right)^2-1^2=\left(\sqrt{a}+\sqrt{b}-1\right)\left(\sqrt{a}+\sqrt{b}+1\right)\)
\(1,=\sqrt{xy}\left(\sqrt{x}+\sqrt{y}\right)\\ 2,=\left(\sqrt{a}-3\right)^2\\ 3,=\left(\sqrt{a}+\sqrt{b}\right)^2\\ 4,=\left(\sqrt{x}-\sqrt{y}\right)\left(\sqrt{x}+\sqrt{y}\right)+\left(\sqrt{x}+\sqrt{y}\right)=\left(\sqrt{x}+\sqrt{y}\right)\left(\sqrt{x}+\sqrt{y}+1\right)\\ 5,=\left(\sqrt{a}+\sqrt{b}\right)^2-1=\left(\sqrt{a}+\sqrt{b}-1\right)\left(\sqrt{a}+\sqrt{b}+1\right)\)
Phân tích đa thức thành nhân tử
a4+b4+c4-2a2b2-2b2c2-2a2c2