\(E=1.2.3+2.3.4+3.4.5+...+18.19.20\)

\(4E=1.2.3.4+2.3.4.4+3.4.5.4+...+18.19.20.4\)

\(4E=1.2.3.4+2.3.4.\left(5-1\right)+3.4.5.\left(6-2\right)+...+18.19.20.\left(21-17\right)\)

\(4E=1.2.3.4+2.3.4.5-1.2.3.4+3.4.5.6-2.3.4.5+...+18.19.20.21-17.18.19.20\)

\(4E=18.19.20.21\)

\(4E=143640\)

\(E=\frac{143640}{4}\)

\(E=35910\)

Chúc bạn học tốt ~ 

\(G=2.4.6+4.6.8+6.8.10+...+18.20.22\) ( xem lại đề có nhầm dấu ko nha bn ) 

\(8G=2.4.6.8+4.6.8.8+6.8.10.8+...+18.20.22.8\)

\(8G=2.4.6.8+4.6.8.\left(10-2\right)+6.8.10.\left(12-4\right)+...+18.20.22\left(24-16\right)\)

\(8G=2.4.6.8+4.6.8.10-2.4.6.8+6.8.10.12-4.6.8.10+...+18.20.22.24-16.18.20.22\)

\(8G=18.20.22.24\)

\(8G=190080\)

\(G=\frac{190080}{8}\)

\(G=23760\)

Chúc bạn học tốt ~ 

\(H=1.3.5+3.5.7+5.7.9+...+17.19.21\)

\(8H=1.3.5.8+3.5.7.8+5.7.9.8+...+17.19.21.8\)

\(8H=1.3.5.8+3.5.7.\left(9-1\right)+5.7.9.\left(11-3\right)+...+17.19.21.\left(23-15\right)\)

\(8H=1.3.5.8+3.5.7.9-1.3.5.7+5.7.9.11-3.5.7.9+...+17.19.21.23-15.17.19.21\)

\(8H=1.3.5.8-1.3.5.7+17.19.21.23\)

\(8H=15+156009\)

\(8H=156024\)

\(H=\frac{156024}{8}\)

\(H=19503\)

Chúc bạn học tốt ~ 

1) \(\dfrac{1}{2}+\dfrac{13}{19}-\dfrac{4}{9}+\dfrac{6}{19}+\dfrac{5}{18}\)

\(=\dfrac{1}{2}+\left(\dfrac{13}{19}+\dfrac{6}{19}\right)-\dfrac{4}{9}+\dfrac{5}{18}\)

\(=\dfrac{3}{2}-\dfrac{4}{9}+\dfrac{5}{18}\)

\(=\dfrac{19}{18}+\dfrac{5}{18}\)

\(=\dfrac{24}{18}\)

\(=\dfrac{4}{3}\)

2) \(\dfrac{-20}{23}+\dfrac{2}{3}-\dfrac{3}{23}+\dfrac{2}{5}+\dfrac{7}{15}\)

\(=\left(-\dfrac{20}{23}-\dfrac{3}{23}\right)+\dfrac{2}{3}+\dfrac{2}{5}+\dfrac{7}{15}\)

\(=-1+\dfrac{2}{3}+\dfrac{2}{5}+\dfrac{7}{15}\)

\(=-\dfrac{1}{3}+\dfrac{2}{5}+\dfrac{7}{15}\)

\(=\dfrac{1}{15}+\dfrac{7}{15}\)

\(=\dfrac{8}{15}\)

3) \(\dfrac{4}{3}+\dfrac{-11}{31}+\dfrac{3}{10}-\dfrac{20}{31}-\dfrac{2}{5}\)

\(=\left(\dfrac{-11}{31}-\dfrac{20}{31}\right)+\dfrac{4}{3}+\dfrac{3}{10}-\dfrac{2}{5}\)

\(=-1+\dfrac{4}{3}+\dfrac{3}{10}-\dfrac{2}{5}\)

\(=\dfrac{1}{3}+\dfrac{3}{10}-\dfrac{2}{5}\)

\(=\dfrac{1}{3}-\dfrac{1}{10}\)

\(=\dfrac{7}{30}\)

4) \(\dfrac{5}{7}.\dfrac{5}{11}+\dfrac{5}{7}.\dfrac{2}{11}-\dfrac{5}{7}.\dfrac{14}{11}\)

\(=\dfrac{5}{7}.\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)\)

\(=\dfrac{5}{7}.-\dfrac{7}{11}\)

\(=-\dfrac{35}{77}\)

\(=-\dfrac{5}{11}\)

A=1/2-1/3+1/3-1/4+...+1/19-1/20

=1/2-1/20

=9/20

A= 1/2 x 3 + 1/3 x 4 + 1/4 x 5 + 1/5 x 6 + 1/6 x 7 + ... + 1/19 x 20
--> A= 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7 +...+ 1/19 - 1/20
        = 1/2 - 1/20 = 10/20 - 1/20 = 9/20

\(A=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{19}-\dfrac{1}{20}\)

\(A=\dfrac{1}{2}-\dfrac{1}{20}=\dfrac{10}{20}-\dfrac{1}{20}=\dfrac{9}{20}\)

\(=-1-1-1-...-1=-1\cdot10=-10\)

1 - 2 + 3 - 4 + 5 - 6 + ...  + 19 - 20

= ( 1 - 2 ) + ( 3 - 4 ) + ( 5 - 6 ) + ...+ ( 19 - 20 )

= ( - 1 ) + ( - 1 ) + ( - 1 ) + ...+ ( - 1 ) ( gồm 20 : 2 = 10 số - 1 )

= ( - 1 ) .10 = - 10

Đúng không bạn?

Mình hỏi một bạn học lớp 8 đó.

k mình nha!

 \(1-2+3-4+5-6+...+19-20\)

\(=\left(1-2\right)+\left(3-4\right)+\left(5-6\right)+...+\left(19-20\right)\)

\(=\left(-1\right)+\left(-1\right)+\left(-1\right)+...+\left(-1\right)\)             

Dãy số trên có 20 số hạng => có 10 cặp -1

\(=\left(-1\right).10\)

\(=-10\)

1-2+3-4+...-19+20

=(1 - 2 + 3 -4 + 5 -6 + 7 -8 + 9 -10 + 11 -12 + 13 -14 + 15 -16 + 17 -18 )-19+20

=(-1 . 9)-19 + 20 

= -9 - 19 +20

=-28+20

=-8

(20-1):1+1=20

1-2+3-4+.....-19+20=-1+-1+-1+...+-1

(20:2).-1=-10

Mình sửa lại đề: 1 - 2 + 3 - 4 + 5 - 6 +....+ 19 - 20

= (1 - 2) + (3 - 4) + (5 - 6) +....+ (19 - 20)

= (-1) . 10

= -10

CAU HOI NAY Ko CO CAU TRA LOI VI:1+2=3-3=0+4=4-5

DEN DAY SAO 4 -5 DUOC

a) \(\dfrac{-25}{19}< \dfrac{-13}{19}< \dfrac{9}{19}< \dfrac{14}{19}< \dfrac{20}{19}< \dfrac{30}{19}< \dfrac{42}{19}\)

b) \(\dfrac{-2}{15}< \dfrac{-1}{10}< \dfrac{1}{6}< \dfrac{1}{5}< \dfrac{4}{15}< \dfrac{1}{3}< \dfrac{2}{5}\)