52-10xy+5y2-20z2
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Phân tích thành nhân tử: 5 x 2 - 10 x y + 5 y 2 - 20 z 2
5 x 2 - 10 x y + 5 y 2 - 20 z 2 = 5 x 2 – 2 x y + y 2 – 4 z 2 = 5 x – y 2 – 2 z 2 = 5 x – y + 2 z x – y – 2 z
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5x2 – 10xy + 5y2 – 20z2 = ??? (phân tích thành nhân tử)
\(5x^2-10xy+5y^2-20z^2\)
\(=5\left(x^2-2xy+y^2-4z^2\right)\)
\(=5\left(x-y-2z\right)\left(x-y+2z\right)\)
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b) (3x + 1)2 – (2x + 1)2
c) - 5x2 + 10xy – 5y2 + 20z2
\(a,=\left(3x+1-2x-1\right)\left(3x+1+2x+1\right)=x\left(5x+2\right)\\ b,=5\left[4z^2-\left(x-y\right)^2\right]=5\left(2z-x+y\right)\left(2z+x-y\right)\)
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\(b,\left(3x+1\right)^2-\left(2x+1\right)^2\\ =\left[\left(3x+1\right)+\left(2x+1\right)\right]\left[\left(3x+1\right)-\left(2x+1\right)\right]\)
\(=\left(3x+1+2x+1\right)\left(3x+1-2x-1\right)\\ =x\left(5x+2\right)\)
\(c,-5x^2+10xy-5y^2+20z^2\\ =-5\left(x^2-2xy+y^2-4z^2\right)\\ =-5\left[\left(x^2-2xy+y^2\right)-\left(2z\right)^2\right]\\ =-5\left[\left(x-y\right)^2-\left(2z\right)^2\right]\\ =-5\left(x-y+2z\right)\left(x-y-2z\right)\)
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1.
\(5x^2-10xy+5y^2-20z^2\)
\(=5\left(x^2-2xy+y^2-4z^2\right)\)
\(=5\left[\left(x-y\right)^2-4z^2\right]\)
\(=5\left(x-y-2z\right)\left(x-y+2z\right)\)
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5x2-10xy+5y2-20z2
=5(x2-2xy+y2-4z2)
=5[(x2-2xy+y2)-(2z)2]
=5[(x-y)2-(2z)2]
=5[(x-y-2z)(x-y+2z)]
chúc bn hc tốt
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Ta có: \(5x^2-10xy+5y^2-20z^2\)
\(=5\cdot\left(x^2-2xy+y^2-4z^2\right)\)
\(=5\cdot\left[\left(x^2-2xy+y^2\right)-\left(2z\right)^2\right]\)
\(=5\cdot\left[\left(x-y\right)^2-\left(2z\right)^2\right]\)
\(=5\cdot\left(x-y-2z\right)\left(x-y+2z\right)\)
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.Phân tích các đa thức sau thành nhân tử:
a) 5x2y- 10xy2
b) x2 + 2xy + y2 - 5x - 5y
c) x2 – 6x + 8
d)5x2 – 10xy + 5y2 – 20z2
\(a,5x^2y-10xy^2=5xy\left(x-2y\right)\\ b,x^2+2xy+y^2-5x-5y=\left(x+y\right)^2-5\left(x+y\right)=\left(x+y\right)\left(x+y-5\right)\\ c,x^2-6x+8=\left(x^2-2x\right)-\left(4x-8\right)=x\left(x-2\right)-4\left(x-2\right)=\left(x-2\right)\left(x-4\right)\\ d,5x^2-10xy+5y^2-20z^2=5\left(x^2-2xy+y^2-4z^2\right)=5\left[\left(x-y\right)^2-\left(2z\right)^2\right]=5\left(x-y-2z\right)\left(x-y+2z\right)\)
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11,18y2 - 12xy + 2x2 12,(x2+x)2 + 3(x2+x) + 213,5x2 - 10xy + 5y2 - 20z2 14,x3 - 9x + 2x2 - 1815,x2 - 2x - 4y2 - 4y16,a2 + 2ab + b2 - 2a - 2b + 117,x3 - x + 3x2 y + 3xy2 + y3 - y 18,x3 + y3 + z3 - 3xyz19,x2 + 4x - 520,2x2 - 6x - 821,x2 - 10xy + 9y222,5xz - 5xy - x2 + 2xy - y223,(x2 + x + 1) ( x2 + x + 2) - 1224,(x+1) (x+2) (x+3) (x+4) - 2425,x3 + 2x2 - 2x - 12
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11,18y2 - 12xy + 2x2
12,(x2+x)2 + 3(x2+x) + 2
13,5x2 - 10xy + 5y2 - 20z2
14,x3 - 9x + 2x2 - 18
15,x2 - 2x - 4y2 - 4y
16,a2 + 2ab + b2 - 2a - 2b + 1
17,x3 - x + 3x2 y + 3xy2 + y3 - y
18,x3 + y3 + z3 - 3xyz
19,x2 + 4x - 5
20,2x2 - 6x - 8
21,x2 - 10xy + 9y2
22,5xz - 5xy - x2 + 2xy - y2
23,(x2 + x + 1) ( x2 + x + 2) - 12
24,(x+1) (x+2) (x+3) (x+4) - 24
25,x3 + 2x2 - 2x - 12
11: \(2x^2-12xy+18y^2\)
\(=2\left(x^2-6xy+9y^2\right)\)
\(=2\left(x-3y\right)^2\)
12: \(\left(x^2+x\right)^2+3\left(x^2+x\right)+2\)
\(=\left(x^2+x+2\right)\left(x^2+x+1\right)\)
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Bài 9: Phân tích đa thức thành nhân tử1, 5x2 – 10xy + 5y2 – 20z2 2, 16x – 5x2 – 3 3, x2 – 5x + 5y – y24, 3x2 – 6xy + 3y2 – 12z25, x2 + 4x + 3 6, (x2 + 1)2 – 4x2 7, x2 – 4x – 5
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Bài 9: Phân tích đa thức thành nhân tử
1, 5x2 – 10xy + 5y2 – 20z2 2, 16x – 5x2 – 3 3, x2 – 5x + 5y – y2 | 4, 3x2 – 6xy + 3y2 – 12z2 5, x2 + 4x + 3 6, (x2 + 1)2 – 4x2 7, x2 – 4x – 5
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1.\(=5\left(x^2-2xy+y^2-4z^2\right)=5\left[\left(x+y\right)^2-\left(2z\right)^2\right]=5\left(x+y-2z\right)\left(x+y+2z\right)\)
2. \(=\left(-5x^2+15x\right)+\left(x-3\right)=-5x\left(x-3\right)+\left(x-3\right)=\left(1-5x\right)\left(x-3\right)\)
3. \(=\left(x-y\right)\left(x+y\right)-5\left(x-y\right)=\left(x-y\right)\left(x+y-5\right)\)
4.\(=3\left(x^2-2xy+y^2-4z^2\right)=3\left[\left(x-y\right)^2-\left(2z\right)^2\right]=3\left(x-y-2z\right)\left(x-y+2z\right)\)
5. \(=\left(x^2+x\right)+\left(3x+3\right)=x\left(x+1\right)+3\left(x+1\right)=\left(x+1\right)\left(x+3\right)\)
6. \(=\left(x^2-2x+1\right)\left(x^2+2x+1\right)=\left(x-1\right)^2\left(x+1\right)^2\)
7. \(=\left(x^2+x\right)-\left(5x+5\right)=x\left(x+1\right)-5\left(x+1\right)=\left(x-5\right)\left(x+1\right)\)
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\(1,=5\left[\left(x-y\right)^2-4z^2\right]=5\left(x-y-2z\right)\left(x-y+2z\right)\\ 2,=-5x^2+15x+x-3=\left(x-3\right)\left(1-5x\right)\\ 3,=\left(x-y\right)\left(x+y\right)-5\left(x-y\right)=\left(x-y\right)\left(x+y-5\right)\\ 4,=3\left[\left(x-y\right)^2-4z^2\right]=3\left(x-y-2z\right)\left(x-y+2z\right)\\ 5,=x^2+x+3x+3=\left(x+3\right)\left(x+1\right)\\ 6,=\left(x^2+2x+1\right)\left(x^2-2x+1\right)=\left(x-1\right)^2\left(x+1\right)^2\\ 7,=x^2+x-5x-5=\left(x+1\right)\left(x-5\right)\)
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13 tháng 12 2023 lúc 19:20
Bài 1:
a) 5x2-10xy+5y2-20z2
b) x2+4x+3
Bài 2: Tính
a. (2x-3y)2
Bài 1:
\(a)5x^2-10xy+5y^2-20z^2\\=5(x^2-2xy+y^2-4z^2)\\=5[(x^2-2xy+y^2)-4z^2]\\=5[(x-y)^2-(2z)^2]\\=5(x-y-2z)(x-y+2z)\\---\\b)x^2+4x+3\\=x^2+x+3x+3\\=x(x+1)+3(x+1)\\=(x+1)(x+3)\)
Bài 2:
\(a.(2x-3y)^2\\=(2x)^2-2\cdot2x\cdot3y+(3y)^2\\=4x^2-12xy+9y^2\)
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Phân tích đa thức sau thành nhân tử:
a) x3 + 2x2y + xy2 - 9x b) 5x2 - 10xy + 5y2
a) x3 + 2x2y + xy2 - 9x
= x(x2 + 2xy + y2 - 9)
= x(x+y)2 - 9
= x(x + y - 3) ( x + y + 3).
b) 5x2 - 10xy + 5y2
= 5(x2 - 2xy + y2)
= 5(x-y)2
Có sai thì xin lỗi ạ
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phân tích đa thức sau thành nhân tử
a) 3ab - 6a2b b) x3 - 6x
c) x2 - y2 - 9x + 9y d) 5x2 + 10xy + 5y2
giải bài toán: cho tam giác MNP, NTlà phân giác của góc N biết MN=4cm, NT=10cm, MP=8cm:TínhTM, TP?
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