tính
3^5/2^6.[-1/1,5]^4
Bài 1: Tính
3/5 + 4/3 x 5/6 2 - 7/6 + 1/3 7/6 x 3 - 3/5
giúp mình với, trả lời mình tick cho
\(\dfrac{3}{5}+\dfrac{4}{3}\times\dfrac{5}{6}=\dfrac{3}{5}+\dfrac{10}{9}=\dfrac{27}{45}+\dfrac{50}{45}=\dfrac{77}{45}\)
\(2-\dfrac{7}{6}+\dfrac{1}{3}=\dfrac{12}{6}-\dfrac{7}{6}+\dfrac{2}{6}=\dfrac{7}{6}\)
\(\dfrac{7}{6}\times3-\dfrac{3}{5}=\dfrac{7}{2}-\dfrac{3}{5}=\dfrac{35}{10}-\dfrac{6}{10}=\dfrac{29}{10}\)
tính
3 x 5/11
16/64 x 15/24
1/6 : 1/5
7/12 : 1/4
\(3\times\dfrac{5}{11}=\dfrac{15}{11}\)
\(\dfrac{16}{64}\times\dfrac{15}{24}=\dfrac{5}{32}\)
\(\dfrac{1}{6}:\dfrac{1}{5}=\dfrac{5}{6}\)
\(\dfrac{7}{12}:\dfrac{1}{4}=\dfrac{7}{3}\)
Tính
3 + 1 + 6 8 – 4 – 3
9 – 1 – 3 3 + 4 + 2
3 + 1 + 6 = 4 + 6 = 10
8 – 4 – 3 = 4 – 3 = 1
9 – 1 – 3 = 8 – 3 = 5
3 + 4 + 2 = 7 + 2 = 9
tính
3/4+1/4x2/5-1/2
\(\dfrac{3}{4}+\dfrac{1}{4}\times\dfrac{2}{5}-\dfrac{1}{2}\\ =\dfrac{3}{4}+\dfrac{1}{10}-\dfrac{1}{2}\\ =\dfrac{15}{20}+\dfrac{2}{20}-\dfrac{10}{20}\\ =\dfrac{15-10+2}{2}\\ =\dfrac{7}{2}\)
tính
3 \(\dfrac{1}{2}\) - \(\dfrac{4}{5}\) - \(8\dfrac{1}{2}\) - \(\dfrac{1}{5}\) - (2021)^0
\(=\left(3-8+\dfrac{1}{2}-\dfrac{1}{2}\right)-\left(\dfrac{4}{5}+\dfrac{1}{5}\right)-1\)
\(=-5-1-1=-7\)
rút gọn rồi tính
3 phần 6 cộng 12 phần 8 , 2 phần 5 cộng 56 phần 40 ,4 phần 6 cộng 16 phần 24
a: =1/2+3/2=2
b: =2/5+7/5=9/5
c: =2/3+2/3=4/3
3/6 + 12/8 = 1/2 + 3/2 = 4/2 = 2
2/5 + 56/40 = 2/5 + 7/5 = 9/5
4/6 + 16/24 = 2/3 + 2/3 = 4/3
a) Số?
b) Tính
3 + 1 + 1 6 + 1 + 2
b,
3 + 1 + 1 = 4 + 1 = 4
6 + 1 + 2 = 7 + 2 = 9
Tính
3 + 1 + 2 5 – 2 – 2
4 + 3 + 1 8 – 1 – 3
3 + 1 + 2 = 4 + 2 = 6
5 – 2 – 2 = 3 – 2 = 1
4 + 3 + 1 = 7 + 1 = 8
8 – 1 – 3 = 7 – 3 = 4
tim x
\dfrac{5}{6}x-\dfrac{3}{4}=\dfrac{-1}{4}+\dfrac{2}{3}65x−43=4−1+32
-1\dfrac{1}{2}-\dfrac{2}{3}x=\dfrac{5}{6}-\left(\dfrac{-2}{5}\right)−121−32x=65−(5−2)
\left(\dfrac{4}{5}:x+1,5\right):\dfrac{2}{3}=-1,5(54:x+1,5):32=−1,5
\dfrac{4}{3}x-\dfrac{2}{3}=\dfrac{1}{4}-x34x−32=41−x
giup minh nhe minh dang can gap
tính
3/7+(-18)/5+18/7+23/5
\(\dfrac{3}{7}+\dfrac{\left(-18\right)}{5}+\dfrac{18}{7}+\dfrac{23}{5}\)
\(=\left(\dfrac{3}{7}+\dfrac{18}{7}\right)+\left(\dfrac{-18}{5}+\dfrac{23}{5}\right)\)
\(=3+1\)
\(=4\)