a)      Ta có: \(\frac{2}{{ - 5}} = \frac{{ - 16}}{{40}}\) và \(\frac{{ - 3}}{8} = \frac{{ - 15}}{{40}}\)

Do \(\frac{{ - 16}}{{40}} < \frac{{ - 15}}{{40}}\,\, \Rightarrow \,\frac{2}{{ - 5}} < \frac{{ - 3}}{8}\).

b)      Ta có: \( - 0,85 = \frac{{ - 85}}{{100}} = \frac{{ - 17}}{{20}}\). Vậy \( - 0,85\)=\(\frac{{ - 17}}{{20}}\).

c)      Ta có: \(\frac{{37}}{{ - 25}} = \frac{{ - 296}}{{200}}\)  

Do  \(\frac{{ - 137}}{{200}} > \frac{{ - 296}}{{200}}\) nên \(\frac{{ - 137}}{{200}}\) > \(\frac{{37}}{{ - 25}}\) .

d)      Ta có: \( - 1\frac{3}{{10}}=\frac{-13}{10}\) ;

\(-\left( {\frac{{ - 13}}{{ - 10}}} \right) = \frac{{-13}}{{10}}\).

Vậy \(- 1\frac{3}{{10}} =-(\frac{{-13}}{{-10}})\,\).

a)      Ta có \(\frac{{ - 2}}{3} < 0\) và \(\frac{1}{{200}} > 0\) nên \(\frac{{ - 2}}{3}\)<\(\frac{1}{{200}}\).

b)      Ta có: \(\frac{{139}}{{138}} > 1\) và \(\frac{{1375}}{{1376}} < 1\) nên \(\frac{{139}}{{138}}\) > \(\frac{{1375}}{{1376}}\).

c)      Ta có: \(\frac{{ - 11}}{{33}} = \frac{{ - 1}}{3}\) và \(\frac{{25}}{{ - 76}} = \frac{{ - 25}}{{76}} > \frac{{ - 25}}{{75}} = \frac{{ - 1}}{3}\,\,\,\, \Rightarrow \frac{{25}}{{ - 76}} > \frac{{ - 11}}{33}\).

a: -2/3<0<1/200

b: 139/138>1

1375/1376<1

=>139/138>1375/1376

c: -11/33=-1/3=-25/75<-25/76

a) Ta có: \(\dfrac{325}{260}< 2< \dfrac{876}{320}\) => \(\dfrac{325}{260}< \dfrac{876}{320}\)

b) Ta có: \(\dfrac{13}{9}< \dfrac{24}{9}=\dfrac{8}{3}\) => \(\dfrac{13}{9}< \dfrac{8}{3}\)

c) Ta có: \(\dfrac{18}{-39}=\dfrac{-18}{39}< \dfrac{-17}{39}< \dfrac{-17}{41}\) => \(\dfrac{18}{-39}< \dfrac{-17}{41}\)

d) Ta có: \(\dfrac{-151515}{232323}=\dfrac{-151515\div10101}{232323\div10101}=\dfrac{-15}{23}\)

Mà \(\dfrac{-15}{25}>\dfrac{-15}{23}\) => \(\dfrac{-15}{25}>\dfrac{-151515}{232323}\)

a) \(\dfrac{325}{260}=\dfrac{5}{4}=\dfrac{100}{80}< \dfrac{219}{80}=\dfrac{876}{320}\)

b) \(\dfrac{13}{9}< \dfrac{24}{9}=\dfrac{8}{3}\)

c) \(\dfrac{18}{-39}=\dfrac{-738}{1599}< \dfrac{-663}{1599}=\dfrac{-17}{41}\)

d) \(\dfrac{-15}{25}=\dfrac{-151515}{252525}< \dfrac{-151515}{232323}\)

Bài 2 

e)2001/-2002<0

4587/4565>0

=>4587/4565>2001/-2002

a.\(\frac{13}{17}\)=1-\(\frac{4}{17}\);    \(\frac{46}{50}\)=1-\(\frac{4}{50}\)

Vì \(\frac{4}{17}\)>\(\frac{4}{50}\)=> 1-\(\frac{4}{17}\)<1-\(\frac{4}{50}\)

Vậy\(\frac{13}{17}\)<\(\frac{46}{50}\)

c.\(\frac{41}{91}\)=1-\(\frac{50}{91}\)=1-\(\frac{500}{910}\);    \(\frac{411}{911}\)=1-\(\frac{500}{911}\)

Vì \(\frac{500}{910}\)>\(\frac{500}{911}\)=>1-\(\frac{500}{910}\)<1-\(\frac{500}{911}\)=>\(\frac{41}{91}\)<\(\frac{411}{911}\)

d. \(\frac{2001}{2002}< \frac{2002}{2002}=1;\frac{2005}{2003}>\frac{2003}{2003}=1\text{ hay }\frac{2001}{2002}< 1< \frac{2005}{2003}\)

Vậy \(\frac{2001}{2002}< \frac{2005}{2003}\).

e. \(-\frac{2005}{2010}< 0;\frac{2001}{2002}>0\text{ hay }-\frac{2005}{2010}< 0< \frac{2001}{2002}\)

Vậy \(-\frac{2005}{2010}< \frac{2001}{2002}\).

b. \(\frac{33}{131}>\frac{33}{132}=\frac{1}{4};\frac{53}{217}< \frac{53}{212}=\frac{1}{4}\text{ hay }\frac{53}{217}< \frac{1}{4}< \frac{33}{131}\)

Vậy \(\frac{53}{217}< \frac{33}{131}\).

a)

\(\frac{13}{27}=\frac{13.101}{27.101}=\frac{1313}{2727}\)

=> \(\frac{13}{27}=\frac{1313}{2727}\)

b)

\(-\frac{15}{23}=-\frac{15.10101}{23.10101}=-\frac{151515}{232323}\)

=>\(-\frac{15}{23}=-\frac{151515}{232323}\)

a) \(\frac{1313}{2727}=\frac{1313:101}{2727:101}=\frac{13}{27}\)

Vậy \(\frac{13}{27}=\frac{1313}{2727}\)

b) \(-\frac{151515}{232323}=\frac{-151515:10101}{232323:10101}=-\frac{15}{23}\)

Vậy \(-\frac{15}{23}=-\frac{151515}{232323}\)