Bài 2: Tính bằng cách thuận tiện nhất:
a) 239 x 45 + 55 x 239                            b) 459 x 107 – 7 x 459
=  239 x (45 + 55)                                    =  459 x (107 - 7)
=  239 x     100                                         =  495 x    100
=      23900                                               =      49500

c) 784 x 98 +784 +784                            d) 982 x 1003 – 982 x2 – 982
=  784 x 98 + 784 x 2                              =  982 x (1003 -2 -1)
=  784 x (98+2)                                        =  982 x    1000
=  784 x   100                                          =   982000
=      78400

\(a,\Leftrightarrow x^2-x-x^2+4x-4=2\\ \Leftrightarrow3x=6\Leftrightarrow x=2\\ b,\Leftrightarrow\left(x-3\right)\left(x+3\right)-\left(x-3\right)\left(6-x\right)=0\\ \Leftrightarrow\left(x-3\right)\left(x+3-6+x\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{3}{2}\end{matrix}\right.\\ c,\Leftrightarrow x^2+2x-3x-6=0\\ \Leftrightarrow\left(x+2\right)\left(x-3\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=3\end{matrix}\right.\)

a: Ta có: \(\left(x-5\right)\left(x+3\right)=x\left(x-3\right)\)

\(\Leftrightarrow x^2-2x-15-x^2+3x=0\)

\(\Leftrightarrow x=15\)

b: Ta có: \(\left(x+2\right)^2=\left(x-1\right)\left(x+2\right)\)

\(\Leftrightarrow x+2=0\)

hay x=-2

c: Ta có: \(\left(x-6\right)\left(x+6\right)=x^2\)

\(\Leftrightarrow x^2-36=x^2\)(vô lý)

a. (x - 5)(x + 3) = x(x - 3)

<=> x² + 3x - 5x - 15 = x² - 3x

<=> x² - x² + 3x - 5x + 3x - 15 = 0

<=> x = 15

b. (x + 2)² = (x - 1)(x + 2)

<=> x² + 4x + 4 = x² + 2x - x - 2

<=> x² - x² + 4x - 2x + x = -2 - 4

<=> 3x = -5

<=> \(x=\dfrac{-5}{3}\)

c. (x - 6)(x + 6) = x²

<=> x² - 36 - x² = 0

<=> x² - x² = 36

<=> 0 = 36 (vô lí)

Vậy nghiệm của PT là \(S=\varnothing\)

d. (2x - 3)² = 4x² - 8 

<=> 4x² - 12x + 9 - 4x² + 8 = 0

<=> 4x² - 4x² - 12x = -8 - 9

<=> -12x = -17

<=> \(x=\dfrac{17}{12}\)

a.\(x+\dfrac{4}{7}=\dfrac{38}{21}\)

\(x=\dfrac{38}{21}-\dfrac{4}{7}\)

\(x=\dfrac{38}{21}-\dfrac{12}{21}=\dfrac{26}{21}\)

b.\(x-\dfrac{1}{3}=\dfrac{7}{45}:\dfrac{2}{15}\)

\(x-\dfrac{1}{3}=\dfrac{7}{6}\)

\(x=\dfrac{7}{6}+\dfrac{1}{3}\)

\(x=\dfrac{7}{6}+\dfrac{2}{6}=\dfrac{9}{6}\)

x = 38/21 - 4/7

x = 26/21

x - 1/3 = 7/6

x = 7/6 + 1/3

x = 3/2

x . 45 + x . 55 = 1000

x . ( 45 + 55 ) = 1000

x . 100 = 1000

x = 1000 : 100

x = 10

Vậy x = 10

6 / x + 1 / 2 = 2

6 / x = 2 - 1 / 2

6 / x = 3 / 2

6 / x = 6 / 4 

=> x = 4

Vậy x = 4

1. x = 10

2. x = 2

...

x . 45 + x . 55 = 1000

x . ( 45 + 55 ) = 1000

x . 100 = 1000

x = 1000 : 100

x = 10

..............................................

Bài 2:

a: Ta có: \(2x+79=x+45\)

nên 2x-x=45-79

hay x=-24

b: Ta có: \(15-\left(x+7\right)=\left(x-8\right)+22\)

\(\Leftrightarrow8-x-x-14=0\)

\(\Leftrightarrow2x=22\)

hay x=11