1/4 x 12/13 + 1/6 x 12/13 + 1/8 x 12/13=?
tính nhanh
a) 12/13 + 2/7 + 8/13 + 6/13 + 5/7 =
b) (1 - 1/2) x (1 - 1/3) x ( 1 - 1/4) x (1 - 1/5) =
câu a) lấy mẫu số chung cộng với nhau
câu b) lấy 1 để ngoài nhân r 1/2-1/3 rồi tương tự
Bài 1 Tìm x,biết
x.3/5=2/3
x.7/17=17/8
3/4 chia x=-7/12
3/8 - 1/6.x=1/4
1/3+1/2 chia x=-4
Bài 2 Tính
-6/11 chia [3/5 . 4/11]
7/12 + 5/12 chia 6 -11/36
[4/5 + 1/2] chia [3/13 - 8/13]
[2/3 - 1/4 + 5/11] chia [5/12 + 1 -7/11]
*Dấu . là dấu nhân nha mn*
Bài 1:
a: \(x=\dfrac{2}{3}:\dfrac{3}{5}=\dfrac{2}{3}\cdot\dfrac{5}{3}=\dfrac{10}{9}\)
b: \(x=\dfrac{17}{8}:\dfrac{7}{17}=\dfrac{17}{8}\cdot\dfrac{17}{7}=\dfrac{289}{56}\)
c: \(x=-\dfrac{3}{4}:\dfrac{7}{12}=\dfrac{-3}{4}\cdot\dfrac{12}{7}=\dfrac{-63}{28}=-\dfrac{9}{4}\)
d: \(\Leftrightarrow x\cdot\dfrac{1}{6}=\dfrac{3}{8}-\dfrac{1}{4}=\dfrac{1}{4}\)
hay \(x=\dfrac{1}{4}:\dfrac{1}{6}=\dfrac{3}{2}\)
e: \(\Leftrightarrow\dfrac{1}{2}:x=-4-\dfrac{1}{3}=-\dfrac{17}{3}\)
hay \(x=-\dfrac{1}{2}:\dfrac{17}{3}=\dfrac{-3}{34}\)
a) x/8 = 3/4 + -5/8
b) x/12 = 3/4 + -2/3
c) 1 + 11/13 = 24/x
d) x/6 - 3/4 = 1/12
`x/8 = 3/4 +(-5/8)`
`=>x/8 = 6/8 +(-5/8)`
`=>x/8 = 1/8`
`=>x=1`
`-----`
`x/12 =3/4 +(-2/3)`
`=>x/12 = 9/12 + (-8/12)`
`=> x/12=1/12`
`=>x=1`
`----`
`1+11/13=24/x`
`=> 13/13 +11/13=24/x`
`=> 24/13 =24/x`
`=>x=13`
`----`
`x/6 -3/4=1/12`
`=>x/6 = 1/12 +3/4`
`=>x/6 = 1/12 + 9/12`
`=>x/6 = 10/12`
`=>x/6= 5/6`
`=>x=5`
\(a)\)
\(\dfrac{x}{8}=\dfrac{3}{4}+\dfrac{-5}{8}\)
\(\Rightarrow\dfrac{x}{8}=\dfrac{1}{8}\)
\(\Rightarrow x.8=1.8\)
\(\Rightarrow x.8=8\)
\(\Rightarrow x=8:8\)
\(\Rightarrow x=1\)
\(b)\)
\(\dfrac{x}{12}=\dfrac{3}{4}+\dfrac{-2}{3}\)
\(\Rightarrow\dfrac{x}{12}=\dfrac{1}{12}\)
\(\Rightarrow x.12=1.12\)
\(\Rightarrow x.12=12\)
\(\Rightarrow x=12:12\)
\(\Rightarrow x=1\)
\(c)\)
\(1+\dfrac{11}{13}=\dfrac{24}{x}\)
\(\Rightarrow\dfrac{24}{13}=\dfrac{24}{x}\)
\(\Rightarrow x.24=24.13\)
\(\Rightarrow x.24=312\)
\(\Rightarrow x=312:24\)
\(\Rightarrow x=13\)
\(d)\)
\(\dfrac{x}{6}-\dfrac{3}{4}=\dfrac{1}{12}\)
\(\Rightarrow\dfrac{x}{6}=\dfrac{1}{12}+\dfrac{3}{4}\)
\(\Rightarrow\dfrac{x}{6}=\dfrac{5}{6}\)
\(\Rightarrow x.6=5.6\)
\(\Rightarrow x.6=30\)
\(\Rightarrow x=30:6\)
\(\Rightarrow x=5\)
2 x 6 = .....; 3 x 4 = .....; 4 x 9 = .....; 5 x 8 = .....?
A. 8; 7; 13; 13
B. 12; 12; 36; 40
C. 11; 13; 35; 41
D. 12; 12; 38; 30
Thực hiện các phép tính:
\(a.\dfrac{-5}{9}-\dfrac{-5}{12} \) \(b.\dfrac{-5}{12}:\dfrac{15}{4}\) c. \(\dfrac{1}{13}\) x \(\dfrac{8}{13}\) + \(\dfrac{5}{13}\) x \(\dfrac{1}{13}\) - \(\dfrac{14}{13}\)
a) \(\dfrac{-5}{9}-\dfrac{-5}{12}=\dfrac{-5}{9}+\dfrac{5}{12}=\dfrac{-20}{36}+\dfrac{15}{36}=-\dfrac{5}{36}\)
b) \(\dfrac{-5}{12}:\dfrac{15}{4}=\dfrac{-5}{12}\times\dfrac{4}{15}=\dfrac{-1}{9}\)
c) \(\dfrac{1}{13}\cdot\dfrac{8}{13}+\dfrac{5}{13}\cdot\dfrac{1}{13}-\dfrac{14}{13}=\dfrac{1}{13}\cdot\left(\dfrac{8}{13}+\dfrac{5}{13}\right)-\dfrac{14}{13}=\dfrac{1}{13}\cdot1-\dfrac{14}{13}=\dfrac{1}{13}-\dfrac{14}{13}=-1\)
a)=--5/36
b)=-1/9
c) =-1
cách làm như trên
Giúp mik câu này mik đag cần gấp
Tính :
1)3/5 x1/7 +3/5 x6/7 -3/5
2)6/7 x4/9 + 6/7 x5/9 + 6/7
3) 9/13 x 7/12 + 9/13 x 5/12 - 9/13
4) 4/13 x5/12 +4/13 x 7/12 - 4/13
1) = \(\frac{3}{5}\)
2) =\(\frac{6}{7}\)
3)\(\frac{9}{13}\)
4)\(\frac{4}{13}\)
Tính 1/4 *12/13+1/6 *12/13+1/8*12/13
(13-12+11-10)+( 9-8+7) – (6+5-4+3-2+1+x) = 7- ( -15+x ) - [ - ( 1-x )]
=>2+8-9-x=7+15-x-x+1
=>1-x=23-2x
=>-x+2x=23+1
hay x=24
1) 9/13 x 7/12 +9/13 x 5/12 - 9/13
2) 4/13 x5/12 + 4/13 x 7/12 -4/3
Giải chi tiết cho mik nha mik đag can gap
9/13 x 7/12 + 9/13 x 5/12 - 9/13
= 9/13 x (7/12 + 5/12 - 1)
= 9/13 x 0
= 0
4/13 x 5/12 + 4/13 x 7/12 - 4/3
= 4/13 x (5/12 + 7/12) - 4/3
= 4/13 x 1 - 4/3
= 4/13 - 4/3
= -40/39
a) 9/13 x 7/12 + 9/13 x 5/12 - 9/13
= 9/13 x ( 5/12 + 7/12 - 1 )
= 9/13 x 0
= 0
b) 4/13 x 5/12 + 4/13 x 7/ 12 - 4/3
= 4/13 x ( 5/12 + 7/12 - 13/3 )
= 4/13 x ( - 10/3 )
= -40/39
a) \(\frac{9}{13}\cdot\frac{7}{12}+\frac{9}{13}\cdot\frac{5}{12}-\frac{9}{13}\)
\(=\frac{9}{13}.\left(\frac{7}{12}+\frac{5}{12}-1\right)=\frac{9}{13}.\left(1-1\right)=\frac{9}{13}.0=0\)
b) \(\frac{4}{13}\cdot\frac{5}{12}+\frac{4}{13}\cdot\frac{7}{12}-\frac{4}{3}\)
\(=\frac{4}{13}.\left(\frac{5}{12}+\frac{7}{12}\right)-\frac{4}{3}=\frac{4}{13}.1-\frac{4}{3}=\frac{4}{13}-\frac{4}{3}\)