c)  5 8 : 5 6 + 2 2 . 3 3 - 2010 0  = 52 + 4 . 27 – 1 = 25 + 108 – 1 = 132

a) [ 316 – ( 25 . 4 + 16 )] : 8 – 24

=( 316 – 116 ) : 8 – 24 = 200 ∶ 8 – 24 = 25 – 24 = 1

b) | -15| + (-27) + 8 + | - 23|

= 15 – 27 + 8 + 23 = 19

c)  5 8   :   5 6   +   2 2   .   3 3   -   2010 0  =  5 2 + 4 . 27 – 1 = 25 + 108 – 1 = 132

\(=200-100:5+1\)

\(=200-20+1\)

=\(180+1\)

\(=181\)

181

5: =5/7(5/11+2/11-14/11)

=5/7*(-7/11)

=-5/11

6: =-5/4(2/11+9/11)+1+3/4

=7/4-5/4=1/2

7: =-5/7(3/13+10/13)+1+5/7

=1

8: =7/4(29/5-9/5)+3+2/13

=3+2/13+7/4*4

=10+2/13

=132/13

(-26) + 16 + (-34) + 26          

`=(-26+26)+[16+(-34)]`

`=0+(-18)`

`=-18`                         

\((-26) + 16 + ( - 34) + 26 \)

\(=-26+16-34+26\)

\(=(26-26)+(16-34)\)

\(=0-18\)

\(=-18\)

(-26) + 16 + (-34) + 26          

\(5:\left(-\dfrac{5}{2}\right)^2+\dfrac{2}{15}\cdot\sqrt{\dfrac{9}{4}}-\left(-2020\right)^0+\left|-0,25\right|\)

\(=5:\dfrac{25}{4}+\dfrac{2}{15}\cdot\dfrac{3}{2}-1+0,25\)

\(=5\cdot\dfrac{4}{25}+\dfrac{3}{15}-0,75\)

\(=\dfrac{4}{5}+\dfrac{1}{5}-\dfrac{3}{4}\)

\(=1-\dfrac{3}{4}\)

\(=\dfrac{1}{4}\)

\(5:\left(-\dfrac{5}{2}\right)^2+\dfrac{2}{15}\cdot\sqrt{\dfrac{9}{4}}-\left(-2020\right)^0+\left|-0,25\right|\)
\(=5:\dfrac{25}{4}+\dfrac{2}{15}\cdot\dfrac{3}{2}-1+0,25\)
\(=\dfrac{4}{5}+\dfrac{1}{5}-1+\dfrac{1}{4}\)
\(=1-1+\dfrac{1}{4}\)
\(=\dfrac{1}{4}\)

#kễnh