\(5:\left(-\dfrac{5}{2}\right)^2+\dfrac{2}{15}\cdot\sqrt{\dfrac{9}{4}}-\left(-2020\right)^0+\left|-0,25\right|\)
\(=5:\dfrac{25}{4}+\dfrac{2}{15}\cdot\dfrac{3}{2}-1+0,25\)
\(=5\cdot\dfrac{4}{25}+\dfrac{3}{15}-0,75\)
\(=\dfrac{4}{5}+\dfrac{1}{5}-\dfrac{3}{4}\)
\(=1-\dfrac{3}{4}\)
\(=\dfrac{1}{4}\)
\(5:\left(-\dfrac{5}{2}\right)^2+\dfrac{2}{15}\cdot\sqrt{\dfrac{9}{4}}-\left(-2020\right)^0+\left|-0,25\right|\)
\(=5:\dfrac{25}{4}+\dfrac{2}{15}\cdot\dfrac{3}{2}-1+0,25\)
\(=\dfrac{4}{5}+\dfrac{1}{5}-1+\dfrac{1}{4}\)
\(=1-1+\dfrac{1}{4}\)
\(=\dfrac{1}{4}\)
#kễnh
\(5:\left(\dfrac{-5}{2}\right)^2+\dfrac{2}{15}\cdot\sqrt{\dfrac{9}{4}}-\left(-2020\right)^0+\left|-0,25\right|\)
\(=5:\dfrac{25}{4}+\dfrac{2}{15}\cdot\dfrac{3}{2}-1+0,25\)
\(=5\cdot\dfrac{4}{25}+\dfrac{3}{15}-1+0,25\)
\(=\dfrac{4}{5}+\dfrac{1}{5}-\dfrac{5}{5}+0,25\)
\(=0+0,25\)
\(=0\)
#\(Toru\)
