Theo bài ra , ta có : 

77x² + 23x² + 77.46 

= 77x² + 2.23.77x + 23² ( bn sai đề mik sửa lại một chút nhé =)) ) 

= ( 77x + 23 )²

77² + 23² + 77.46

= 23²+77.2.46+77²

=(23+77)²

=100²

=10000

\(a.101^2-99^2=\left(101+99\right)\left(101-99\right)=200.2=400\)

\(b.98.102=98.\left(100+2\right)=9800+196=9996\)

\(c,77^2+23^2+77.46=77^2+23^2+2.77.23=\left(77+23\right)^2=100^2=10000\)

77² + 23² + 77.46

= 77² + 2.77.23 + 23²

= (77 + 23)²

= 100²

= 10000

Tính nhanh

77² + 23² + 77.46=77²+2.77.23+23²=(77+23)²=100²=10000

77²+2*23*77+23²=(77+23)²=10000

a. \(^{77^2}\) + \(23^2\) + 77 . 46

= \(77^2\) + 2. 77 . 23 + \(23^2\)

= \(\left(77+23\right)^2\)

= \(100^2\)

= 10000

b. \(105^2\) - \(5^2\)

= ( 105 - 5)( 105 + 5)

= 100 . 110

= 11000

101² = (100 + 1)² = 100² + 2.100.1 + 1² = 10000 + 200 + 1 = 10201

97 . 103 = (100 - 3)(100 + 3) = 100² - 3² = 10000 - 9 = 9991

77² + 2. 23. 77 + 23² = (77 + 23)² = 100² = 10000

105² - 5² = (105 - 5)(105 + 5) = 100 . 110 = 11000

tick nha

a) \(101^2\)

\(=\left(100+1\right)^2\)

\(=100^2+2.100.1+1^2\)

\(=10000+200+1\)

\(=10200+1\)

\(=10201\)

b) \(97.103\)

\(=\left(100-3\right).\left(100+3\right)\)

\(=100^2-3^2\)

\(=10000-9\)

\(=9991\)

c) \(77^2+23^2+77.46\)

\(=77^2+77.46+23^2\)

\(=77^2+2.77.23+23^2\)

\(=\left(77+23\right)^2\)

\(=100^2\)

\(=10000\)

d) \(105^2-5^2\)

\(=\left(105-5\right)\left(105+5\right)\)

\(=100.110\)

\(=11000\)

lâu lắm r moi lên h24, tớ giúp bn nhé:

*101² = (100+1)² = 10⁴ + 2.100.1 +1² = 10201

*97.103= (100-3)(100+3) = 10² - 3² = 9991

* = 77² + 2.77.23 + 23² = (77+23)² = 10⁴