11/10,5=6,32/x
Tim x biet 11/10,5=6,32/x
\(\frac{11}{10,5}=\frac{6,32}{x}\)\(\Rightarrow\) 11x = 10,5 . 6,32
11x = 66,36
x = 6,032(72)
tìm x biết: \(\frac{11}{10,5}=\frac{6,32}{x}\)
\(\frac{11}{10,5}=\frac{6,32}{x}\Rightarrow x=\frac{6,32.10,5}{11}=\frac{1659}{275}\)
\(\frac{11}{10,5}=\frac{6,32}{x}\)
\(\Rightarrow11.x=6,32.10,5\)
\(\Rightarrow11.x=66,36\)
\(\Rightarrow x=66,36:11\)
\(\Rightarrow x=\frac{1659}{275}\)
Vậy \(x=\frac{1659}{275}.\)
Chúc bạn học tốt!
Tìm x
a, \(\frac{11}{10,5}=\frac{6,32}{-x}\) b,\(\frac{x-1}{x+5}=\frac{6}{7}\) c, \(\frac{x^2}{6}=\frac{24}{25}\) d,x:0,16 = 9:x
a) \(\frac{11}{10,5}=\frac{6,32}{-x}\)
\(6,32:\frac{11}{10,5}=x\)
\(\frac{1659}{275}=x\)
b) \(\frac{x-1}{x+5}=\frac{6}{7}\)
\(\Rightarrow7x-7=6x+30\)
\(7x-6x=30+7\)
\(x=37\)
c) \(\frac{x^2}{6}=\frac{24}{25}\)
\(x^2=\frac{144}{25}\)
\(x=\frac{12}{5}\)
d) \(x:0,16=9:x\)
\(\frac{x}{0,16}=\frac{9}{x}\)
\(x^2=1,44\)
\(x=1,2\)
Tìm các số hữu tỉ x trong các tỉ lệ thức
a) 0,4 : x = x : 0,9
b) 0,2 : 1 1/5 = 2/3 : (6x + 7)
c) 13 1/3 : 1 1/3 = 26 : (2x + 1)
d) 37 - x/x + 13= 3/7
e) 3x + 2/5x + 7= 3 x - 1/5x + 1
h) x / 3,15 = 0,15 / 7,2
i) -2,6/x = -12/42
K) 11/10,5 = 6,32
L) 41/10//9/4= x/ 7,3
Tính thuận tiện:
3 x ( 32,1 - 6,32 ) + 7 x 32,1 + 3 x 6,32
Mk chỉ biết đáp án là 321 thôi
= 3 x 32,1 - 3 x 6,32 + 7 x 32,1 + 3 x 6,32
= 32,1 x (3 + 7) + 6,32 x (3 - 3)
= 321 + 0
=321
\(\dfrac{7,5+1,5+\dfrac{5}{4}+\dfrac{5}{11}}{10,5+2,1+\dfrac{7}{4}+\dfrac{7}{11}}\)+ x =\(\dfrac{6}{7}\)
\(\dfrac{7,5+1,5+\dfrac{5}{4}+\dfrac{5}{11}}{10,5+2,1+\dfrac{7}{4}+\dfrac{7}{11}}+x=\dfrac{6}{7}\)
\(\dfrac{9+\dfrac{5}{4}+\dfrac{5}{11}}{\dfrac{63}{5}+\dfrac{7}{4}+\dfrac{7}{11}}+x=\dfrac{6}{7}\)
\(\dfrac{\dfrac{36}{4}+\dfrac{5}{4}+\dfrac{5}{11}}{\dfrac{252}{20}+\dfrac{35}{20}+\dfrac{7}{11}}+x=\dfrac{6}{7}\)
\(\dfrac{\dfrac{41}{4}+\dfrac{5}{11}}{\dfrac{287}{20}+\dfrac{7}{11}}+x=\dfrac{6}{7}\)
\(\dfrac{\dfrac{451}{44}+\dfrac{20}{44}}{\dfrac{3157}{220}+\dfrac{140}{220}}+x=\dfrac{6}{7}\)
\(\dfrac{\dfrac{471}{44}}{\dfrac{3297}{220}}+x=\dfrac{6}{7}\)
\(\dfrac{5}{7}+x=\dfrac{6}{7}\)
\(x=\dfrac{6}{7}-\dfrac{5}{7}\)
\(x=\dfrac{1}{7}\)
Tính nhanh:
3 x { 32,1 - 6,32 } + 7 x 32,1 + 3 x 6,32
14,7 x 345 + 14,7 x 475 + 85,3 x 82
243,93 x { 76,1 - 13,2 } - 143,93 x { 72 + 4,1 } + 243,93 x 13,2
C = 3 x (32,1 - 6,32) + 7 x 32,1 + 3 x 0,32
\(=3\cdot32.1-3\cdot6.32+7\cdot32.1+3\cdot0.32\)
\(=32.1\cdot10-3\cdot6=321-18=303\)
3 x ( 32,1 + 6,32 ) + 7 x 32,1 - 3 x 0,32
Tôi cũng có đề bài đó nhưng là 32,1-6,32
Kết quả là 303