Tim x, biet: I 2x-1 I + I 1-2x I = 8
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Tim x ,y biet :
2x+1 /5 =3y-2 /7 =2x +3y-1/6x
làm giùm đi mình đang cần gấp lắm
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tim x biet :
a) ( 2x^2+4 ) - (x^2-3/2 ) = (-3+4x^2)+ ( -4x^2/3+1)
b) ( I xI -4) - ( 2- I-xI ) = 1/3 . I xI -5
tim x biet :
a) ( 2x2+4 ) - (x2-3/2 ) = (-3+4x2)+ ( -4x2/3+1)
b) ( I xI -4) - ( 2- I-xI ) = 1/3 . I xI -5
Không có ngiệm nguyên hay hữu tỉ mà bạn
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tim x biet :
a) ( 2x2+4 ) - (x2-3/2 ) = (-3+4x2)+ ( -4x2/3+1)
b) ( I xI -4) - ( 2- I-xI ) = 1/3 . I xI -5
Tim x:
2x-/x+1/=-1/2
\(2x-\left|x+1\right|=-\frac{1}{2}\)
=> \(\left|x+1\right|=2x-\left(-\frac{1}{2}\right)\)
=> \(\left|x+1\right|=2x+\frac{1}{2}\)
=> \(\left[{}\begin{matrix}x+1=2x+\frac{1}{2}\\x+1=-\left(2x+\frac{1}{2}\right)\end{matrix}\right.\) => \(\left[{}\begin{matrix}x-2x=\frac{1}{2}-1\\x+1=-2x-\frac{1}{2}\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}-1x=-\frac{1}{2}\\x+2x=\left(-\frac{1}{2}\right)-1\end{matrix}\right.\) => \(\left[{}\begin{matrix}x=\left(-\frac{1}{2}\right):\left(-1\right)\\3x=-\frac{3}{2}\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}x=\frac{1}{2}\\x=\left(-\frac{3}{2}\right):3\end{matrix}\right.\) => \(\left[{}\begin{matrix}x=\frac{1}{2}\\x=-\frac{1}{2}\end{matrix}\right.\)
Vậy \(x\in\left\{\frac{1}{2};-\frac{1}{2}\right\}.\)
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\(2x-\left|x+1\right|=-\frac{1}{2}\)
\(\Leftrightarrow\left|x+1\right|=2x+\frac{1}{2}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+1=2x+\frac{1}{2}\\x+1=-\left(2x+\frac{1}{2}\right)\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\frac{1}{2}\\x+1=-2x-\frac{1}{2}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\frac{1}{2}\\3x=-\frac{3}{2}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\frac{1}{2}\\x=-\frac{1}{2}\end{matrix}\right.\)
Vậy : \(x\in\left\{\frac{1}{2},-\frac{1}{2}\right\}\)
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Tim x biết I 2x - 1 I -x = 4
\(\left|2x-1\right|-x=4\Leftrightarrow\left|2x-1\right|=4+x\) (1)
+)TH1: \(2x-1\ge0\Leftrightarrow x\ge\frac{1}{2}\) thì ph(1) trở thành
\(2x-1=4+x\Leftrightarrow x=5\) (tm)
+)TH2: \(2x-1< 0\Leftrightarrow x< \frac{1}{2}\) thì pt(1) trở thành
\(1-2x=4+x\Leftrightarrow-3x=3\Leftrightarrow x=-1\) (tm)
Vậy x={-1;5}
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tim x biet :
a) ( 2x2+4 ) - (x2-3/2 ) = (-3+4x2)+ ( -4x2/3+1)
b) ( I xI -4) - ( 2- I-xI ) = 1/3 . I xI -5
a: \(\Leftrightarrow2x^2+4-x^2+\dfrac{3}{2}=-3+4x^2-\dfrac{4}{3}x^2+1\)
\(\Leftrightarrow x^2+\dfrac{11}{2}=\dfrac{8}{3}x^2-2\)
\(\Leftrightarrow x^2\cdot\dfrac{-5}{3}=-\dfrac{15}{2}\)
\(\Leftrightarrow x^2=\dfrac{9}{2}\)
hay \(x\in\left\{\dfrac{3\sqrt{2}}{2};-\dfrac{3\sqrt{2}}{2}\right\}\)
b: \(\Leftrightarrow\left|x\right|-4-2+\left|x\right|-\dfrac{1}{3}\left|x\right|+5=0\)
\(\Leftrightarrow\left|x\right|\cdot\dfrac{5}{3}=1\)
hay \(x\in\left\{\dfrac{3}{5};-\dfrac{3}{5}\right\}\)
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đây mik giải bài 43 cho bạn nè nhu quynh
a)x^2+6x+9 b)10-25-x^2
x^2+2.x.3+3^2 -(x^2+10x+25)
(x+3)^2 -(x^2+2.x.5+5)^2
-(5-x^2)
c)8x^3-1/8(2x)^3-(1/2)^3(2x-1/2).[(2x)^2+2x.1/2+(1/2)^2](2x-1/2)(4x^2+x+1/4)
d)1/25x^2-64y^2(1/5x)^2-(8y)^2(1/...
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đây mik giải bài 43 cho bạn nè nhu quynh
a)x^2+6x+9 b)10-25-x^2
=x^2+2.x.3+3^2 = -(x^2+10x+25)
=(x+3)^2 =-(x^2+2.x.5+5)^2
=-(5-x^2)
c)8x^3-1/8=(2x)^3-(1/2)^3=(2x-1/2).[(2x)^2+2x.1/2+(1/2)^2]=(2x-1/2)(4x^2+x+1/4)
d)1/25x^2-64y^2=(1/5x)^2-(8y)^2=(1/5x+8y)(1/5x-8y)
tìm x
a, I 2x + 1 I = 7
b, 3 I x + 1 I + 1 = 28
c, I 7x - 1 I + 8 = 7
d, I 2x + 1 I = I x - 1 I
cần gấp lắm nha mn, tick 3 ngày
a) |2x +1| = 7
Th1: 2x + 1 = 7
<=> x = 3
Th2: 2x + 1 = -7
<=> x = -4
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