Câu 1: 

a,MCD: R1//R2

\(R_{12}=\dfrac{R_1R_2}{R_1+R_2}=\dfrac{30\cdot20}{30+20}=12\left(\Omega\right)\)

b, MCD: R3nt(R1//R2)

\(R_{tđ}=R_3+R_{12}=30+12=42\left(\Omega\right)\)

Câu 2

a Điện trở và cường độ dòng điện tối đa mà biến trở đó có thể có

b,\(S=\dfrac{l\cdot\rho}{R}=\dfrac{100\cdot1,1\cdot10^{-6}}{200}=5,5\cdot10^{-7}\)

\(R=\sqrt{\dfrac{S}{\pi}}=\sqrt{\dfrac{5,5\cdot10^{-7}}{\pi}}=4,18\cdot10^{-4}\left(m\right)=0,418\left(mm\right)\)

Bài 3: 

Sau 60 ngày

lx đề r bn

Câu hỏi đâu bạn?

đề bài đou?

a) \(A=\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)

\(A=\dfrac{\left(2^2\right)^5\cdot\left(3^2\right)^4-2\cdot2^9\cdot3^9}{2^{10}\cdot3^8+2^8\cdot3^8\cdot2^2\cdot5}\)

\(A=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}\)

\(A=\dfrac{2^{10}\cdot3^8\cdot\left(1-3\right)}{2^{10}\cdot3^8\cdot\left(1+5\right)}\)

\(A=\dfrac{1-3}{1+5}\)

\(A=-\dfrac{2}{6}\)

\(A=-\dfrac{1}{3}\)

b) \(B=\dfrac{\dfrac{1}{9}-\dfrac{1}{7}-\dfrac{1}{11}}{\dfrac{4}{9}-\dfrac{4}{7}-\dfrac{4}{11}}+\dfrac{0,6-\dfrac{3}{25}-\dfrac{3}{125}-\dfrac{3}{625}}{\dfrac{4}{5}-0,16-\dfrac{4}{125}-\dfrac{4}{625}}\)

\(B=\dfrac{\dfrac{1}{9}-\dfrac{1}{7}-\dfrac{1}{11}}{4\cdot\left(\dfrac{1}{9}-\dfrac{1}{7}-\dfrac{1}{11}\right)}+\dfrac{\dfrac{3}{5}-\dfrac{3}{25}-\dfrac{3}{125}-\dfrac{3}{625}}{\dfrac{4}{5}-\dfrac{4}{25}-\dfrac{4}{125}-\dfrac{4}{625}}\)

\(B=\dfrac{1}{4}+\dfrac{3\cdot\left(\dfrac{1}{5}-\dfrac{1}{25}-\dfrac{1}{125}-\dfrac{1}{625}\right)}{4\cdot\left(\dfrac{1}{5}-\dfrac{1}{25}-\dfrac{1}{125}-\dfrac{1}{625}\right)}\)

\(B=\dfrac{1}{4}+\dfrac{3}{4}\)

\(B=\dfrac{1+3}{4}\)

\(B=\dfrac{4}{4}\)

\(B=1\)

1.A
2.A
3.B
4.C
5.B
6.C
7.A
8.A
9.B
10.A
11.B
12.A
13.C
14.B
15.B
16.A
17.A
18.A
19.A
20.C

a: =-5/6-3/7=-35/42-18/42=-53/42

b: =2/5-4/9=18/45-20/45=-2/45

c: =-24/35

d: =2/3x-5/4=-10/12=-5/6

1. I do not have any money in my bag.

2. They did their homework carefully.

3. My bed is more comfortable than that one.

4. There weren't any students in the classroom yesterday.

5. The red flowers are the most beautiful.

6. Minh was late because his bike broke yesterday.

7. Lili's sister is afraid of tigers and lions.

8. Does Tony always read comic books in the evening?

1. I do not have any money in my bag.

2. They did their homework carefully.

3. My bed is comfortable more than that one.

4.There weren't any students in the classroom yesterday.

5. The red flowers are the most beautiful.

6. Minh was late because his bike broke yesterday.

7. Lili's sister is afraid of tigers and lions.

8. Does Tony always read comic books in the evening?

Học tốt

a) \(\Leftrightarrow\left(3x+1\right)\left(x-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{3}\\x=1\end{matrix}\right.\)

b) \(\Leftrightarrow\left(2x-5\right)\left(2x+5\right)-\left(2x-5\right)\left(2x+7\right)=0\\ \Leftrightarrow\left(2x-5\right)\left(2x+5-2x-7\right)=0\\ \Leftrightarrow-2\left(2x-5\right)=0\\ \Leftrightarrow2x-5=0\\ \Leftrightarrow x=\dfrac{5}{2}\)

c) \(\Leftrightarrow2\left(x+3\right)-x\left(x+3\right)=0\\ \Leftrightarrow\left(x+3\right)\left(2-x\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-3\\x=2\end{matrix}\right.\)

d) \(\Leftrightarrow\left(x+3\right)\left(x^2-3x+9\right)+\left(x+3\right)\left(x-9\right)=0\\ \Leftrightarrow\left(x+3\right)\left(x^2-3x+9+x-9\right)=0\\ \Leftrightarrow\left(x+3\right)\left(x^2-2x\right)=0\\ \Leftrightarrow x\left(x+3\right)\left(x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=-3\\x=2\end{matrix}\right.\)

a) 3x(x-1)+(x-1).1=0

(x-1)(3x+1)=0

=> x-1=0 hoặc 3x+1 =0 

=> x=1 hoặc x= -1/3