11:

a: Số cần tìm là 3;2;1;0

b: 0

10:

\(2\dfrac{1}{2}=2.5>2.25\)

\(6>5\)

nên căn 6>căn 5

-căn 5<0

0<căn 5

=>-căn 5<căn 5

a: -91/104=-7/8=-21/24

-5/6=-20/24

=>-91/104<-5/6

b: -15/21=-5/7

-36/44=-9/11

5/7=1-2/7; 9/11=1-2/11

mà 2/7>2/11

nên 5/7<9/11

=>-15/21>-36/44

1) \(\sqrt[3]{x+1}=5\)

\(\Rightarrow x+1=125\)

\(\Rightarrow x=124\)

2) \(\sqrt[3]{1-3x^3}=-2\)

\(\Rightarrow1-3x^3=-8\)

\(\Rightarrow3x^3=9\)

\(\Rightarrow x=\sqrt[3]{3}\)

1 >

2 >

8²=(2³)²=2⁶

\(2^6< 8^2\)

\(5^3< 3^5\)

b) Ta có: \(n^{150}< 5^{225}\)

\(\Leftrightarrow\left(n^2\right)^{75}< \left(5^3\right)^{75}\)

\(\Leftrightarrow n^2< 125\)

\(\Leftrightarrow n=11\)

2/7 < 4/9

5/7 > 15/26

9/13 < 3/5

6/11 < 3/5

3/7 > 5/11

7/11 > 12/17

13/18 > 15/23

13/6 < 17/9

2/7 < 4/9

57 < 15/26

9/13 > 3/5

6/11 >3/5

7/11 < 12/17

13/18 < 15/23

13/6 < 17/9

a)  ( -18/91) < (-18/90)=-1/5

-23/114 > -23/115= -1/5

Vậy -18/91 < -23/114

Ta có:

   (-2)⁹¹ = [ (-2)¹³ ]⁷ = (-8192)⁷

   (-5)³⁵ = [ (-5)⁵ ]⁷ = (-3125)⁷

Vì -8192 < -3125 nên (-8192)⁷ < (-3125)⁷

Vậy (-2)⁹¹ < (-5)³⁵

^{HỌC TỐT !}