a, Đặt \(\frac{x}{5}=\frac{y}{9}=k\)
=> x=5.k , y=9k
Mà 3y - 2y = 6
=> 3.9.k- 2.5.k = 6
=> 27.k - 10.k = 6
=> (27-10).k = 6
=> 17.k =6
=> k= 6/17
x=6/17.5=3/17
y=6/17.9=54/17
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Câu 1 The function mm is defined on the real numbers by m(k) dfrac{k+2}{k+8}m(k) k+8 k+2 . What is the value of 10times m(2)10×m(2)? Answer: Câu 2 The function ff is defined on the real numbers by f(x) ax-3f(x)ax−3. What is the value of a if f(3)9f(3)9? Answer: Câu 3 The function ff is defined on the real numbers by f(x) 2x+a-3f(x)2x+a−3. What is the value of a if f(-5)11f(−5)11? Answer: Câu 4 The function ff is defined on the real numbers by f(x) 2 + x-x^2f(x)2+x−x 2 . What is the value of...
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Câu 1 The function mm is defined on the real numbers by m(k) = \dfrac{k+2}{k+8}m(k)= k+8 k+2 . What is the value of 10\times m(2)10×m(2)? Answer: Câu 2 The function ff is defined on the real numbers by f(x)= ax-3f(x)=ax−3. What is the value of a if f(3)=9f(3)=9? Answer: Câu 3 The function ff is defined on the real numbers by f(x)= 2x+a-3f(x)=2x+a−3. What is the value of a if f(-5)=11f(−5)=11? Answer: Câu 4 The function ff is defined on the real numbers by f(x) = 2 + x-x^2f(x)=2+x−x 2 . What is the value of f(-3)f(−3)? Answer: Câu 5 Given a real number aa and a function ff is defined on the real numbers by f(x)=-6\times|3x|-4f(x)=−6×∣3x∣−4. Compare: f(a)f(a) f(-a)f(−a) Câu 6 There are ordered pairs (x;y)(x;y) where xx and yy are integers such that \dfrac{5}{x}+\dfrac{y}{4}=\dfrac{1}{8} x 5 + 4 y = 8 1 Câu 7 Given a negative number kk and a function ff is defined on the real numbers by f(x)=\dfrac{6}{13}xf(x)= 13 6 x. Compare: f(k)f(k) f(-k)f(−k) Câu 8 Given a positive number kk and a function ff is defined on the real numbers by f(x)=\dfrac{-3}{4}x+4f(x)= 4 −3 x+4. Compare: f(k)f(k) f(-k)f(−k). Câu 9 A=(1+2+3+\ldots+90) \times(12 \times34-6 \times 68):(\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{1}{6})=A=(1+2+3+…+90)×(12×34−6×68):( 3 1 + 4 1 + 5 1 + 6 1 )= Câu 10 Given that \dfrac{2x+y+z+t}{x}=\dfrac{x+2y+z+t}{y}=\dfrac{x+y+2z+t}{z}=\dfrac{x+y+z+2t}{t} x 2x+y+z+t = y x+2y+z+t = z x+y+2z+t = t x+y+z+2t . The negative value of \dfrac{x+y}{z+t}+\dfrac{y+z}{t+x}+\dfrac{z+t}{x+y}+\dfrac{t+x}{y+z} z+t x+y + t+x y+z + x+y z+t + y+z t+x is
Cho đa thức : f(x)=x(x^19-x^5-x^2018) và g(x)= x^2019-x^2020+9+(x^4+x^2+2)
1)Tính k(x)=f(x)+g(x)
2)Tính giá trị của k(x) tại x bằng \(\left(2-\frac{5}{3}+\frac{7}{6}-\frac{9}{10}+\frac{11}{15}-\frac{13}{21}+\frac{15}{28}-\frac{17}{36}+\frac{19}{45}\right)\cdot\frac{5}{6}\)
3) CMR k(x) không nhận giá trị 2019 với mọi giá trị nguyên x
Giai phương trình : sqrt{3}cosleft(x+frac{Pi}{2}right)+sinleft(x-frac{Pi}{2}right)2sin2x .
A . left[{}begin{matrix}xfrac{5Pi}{6}+k2Pixfrac{Pi}{18}+kfrac{2Pi}{3}end{matrix}right.,kin Z}
B . left[{}begin{matrix}xfrac{7Pi}{6}+k2Pix-frac{Pi}{18}+kfrac{2Pi}{3}end{matrix}right.,kin Z}
C . left[{}begin{matrix}xfrac{5Pi}{6}+k2Pixfrac{7Pi}{6}+k2Piend{matrix}right.,kin Z}
D . left[{}begin{matrix}xfrac{Pi}{18}+kfrac{2Pi}{3}x-frac{Pi}{18}+kfrac{2Pi}{3}end{matrix}right.,kin Z}
Trình bày bài giải chi t...
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Giai phương trình : \(\sqrt{3}cos\left(x+\frac{\Pi}{2}\right)+sin\left(x-\frac{\Pi}{2}\right)=2sin2x\) .
A . \(\left[{}\begin{matrix}x=\frac{5\Pi}{6}+k2\Pi\\x=\frac{\Pi}{18}+k\frac{2\Pi}{3}\end{matrix}\right.,k\in Z}\)
B . \(\left[{}\begin{matrix}x=\frac{7\Pi}{6}+k2\Pi\\x=-\frac{\Pi}{18}+k\frac{2\Pi}{3}\end{matrix}\right.,k\in Z}\)
C . \(\left[{}\begin{matrix}x=\frac{5\Pi}{6}+k2\Pi\\x=\frac{7\Pi}{6}+k2\Pi\end{matrix}\right.,k\in Z}\)
D . \(\left[{}\begin{matrix}x=\frac{\Pi}{18}+k\frac{2\Pi}{3}\\x=-\frac{\Pi}{18}+k\frac{2\Pi}{3}\end{matrix}\right.,k\in Z}\)
Trình bày bài giải chi tiết rồi ms chọn đáp án nha các bạn .
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Cho x-2y=6
a) Tính K= \(\frac{x-y}{x+6}\)
b)Tính L = \(\frac{2x+6}{3x-2y}+\frac{2y-6}{4y-x}\)
a) K= x-y/x+6
K=x-y/x+(x-2y)
K=x-y/x+x-2y
K=x-y/2x-2y
K=x-y/2(x-y)=> K=2
b) L= 2x+( x-2y)/3x-2y + 2y-(x-2y)/4y-x
L= 2x+x-2y/3x-2y + 2y-x+2y/4y-x
L=3x-2y/3x-2y + 4y-x/4y-x
L=1+1=2
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Giai phương trình : frac{cosx-sqrt{3}sinx}{sinx-frac{1}{2}}0
A . xfrac{Pi}{6}+kPi,kin Z
B . xfrac{Pi}{6}+k2Pi,kin Z
C . xfrac{7Pi}{6}+k2Pi,kin Z
D . xfrac{7Pi}{6}+kPi,kin Z
Trình bày bài giải chi tiết rồi mới chọn đáp án nha các bạn .
HELP ME !!!!
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Giai phương trình : \(\frac{cosx-\sqrt{3}sinx}{sinx-\frac{1}{2}}=0\)
A . \(x=\frac{\Pi}{6}+k\Pi,k\in Z\)
B . \(x=\frac{\Pi}{6}+k2\Pi,k\in Z\)
C . \(x=\frac{7\Pi}{6}+k2\Pi,k\in Z\)
D . \(x=\frac{7\Pi}{6}+k\Pi,k\in Z\)
Trình bày bài giải chi tiết rồi mới chọn đáp án nha các bạn .
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cho 2 đường thẳng y(k−2)xy(k−2)x +m−1+m−1 và y(6−2k)x+5−2my(6−2k)x+5−2mbiết m 3 tìm k để 2 đường thẳng cắt nhau trên trục hoành
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cho 2 đường thẳng và
biết m = 3 tìm k để 2 đường thẳng cắt nhau trên trục hoành
m=3 nên (d1): y=(k-2)x+2 và (d2): y=(6-2k)x-1
Để (d1) cắt (d2) trên trục hoành thì
\(\left\{{}\begin{matrix}6-2k< >k-2\\\dfrac{-2}{k-2}=\dfrac{1}{6-2k}=\dfrac{-1}{2k-6}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}-3k< >-4\\2\left(2k-6\right)=k-2\end{matrix}\right.\)
=>k<>4/3 và 4k-12-k+2=0
=>k=10/3
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Cắt nhau trên trục hoành `=>y=0`
Thay `y=0;m=3` vào `2` đường thẳng có hệ:
`{(0=(k-2)x+3-1),(0=(6-2k)x+5-2.3):}`
`<=>{(kx-2x=-2),(2kx-6x=-1):}`
`<=>{(2kx-4x=-4),(2kx-6x=-1):}`
`<=>{(x=-3/2),(3k. (-3/2)-4.(-3/2)=-4):}`
`<=>{(x=-3/2),(k=20/9):}`
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Bài1 :Tìm x:
( 6 : 3/5 - 17/16 . 6/7 / 21/5 . 10/11 + 57/11 - (3/20 + 1/2 - 1/15) . 12/49 / 10/3 + 2/9 ) . x = 215/96
Ai nhanh mk K ạ.
\(\left(\dfrac{6:\dfrac{3}{5}-\dfrac{17}{16}.\dfrac{6}{7}}{\dfrac{21}{5}.\dfrac{10}{11}+\dfrac{57}{11}}-\dfrac{\left(\dfrac{3}{20}+\dfrac{1}{2}-\dfrac{1}{15}\right).\dfrac{12}{49}}{\dfrac{10}{3}+\dfrac{2}{9}}\right).x=\dfrac{215}{96}\)
\(\Rightarrow\left(\dfrac{\dfrac{509}{56}}{9}-\dfrac{\dfrac{7}{12}.\dfrac{12}{49}}{\dfrac{32}{9}}\right).x=\dfrac{215}{96}\)
\(\Rightarrow\left(\dfrac{509}{504}-\dfrac{\dfrac{1}{7}}{\dfrac{32}{9}}\right).x=\dfrac{215}{96}\)
\(\Rightarrow\left(\dfrac{509}{504}-\dfrac{9}{224}\right).x=\dfrac{215}{96}\)
\(\Rightarrow\dfrac{1955}{2016}.x=\dfrac{215}{96}\)
\(\Rightarrow x=\dfrac{215}{96}:\dfrac{1955}{2016}\)
\(\Rightarrow x=\dfrac{903}{391}\)
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`[ 6 : 3/5 - 17/16 . 6/7 : 21/5 . 10/11 + 57/11 - (3/20 + 1/2 - 1/15) . 12/49 : 10/3 + 2/9 ] . x = 215/96`
`=>[ 6 . 5/3 - 17/16 . 6/7 . 5/21 . 10/11 + 57/11 - (3/20 + 1/2 - 1/15) . 12/49 . 3/10 + 2/9 ] . x = 215/96`
`=>[10- 51/56 . 6/7 . 5/21 . 10/11 + 57/11 - (3/20 + 1/2 - 1/15) . 12/49 . 3/10 + 2/9 ] . x = 215/96`
`=> [10- 153/196 . 5/21 . 10/11 + 57/11 - (3/20 + 1/2 - 1/15) . 12/49 . 3/10 + 2/9 ] . x = 215/96`
`=> [10- 255/1372 . 10/11 + 57/11 - (3/20 + 1/2 - 1/15) . 12/49 . 3/10 + 2/9 ] . x = 215/96`
`=> [10- 1275/7546 + 57/11 - (3/20 + 1/2 - 1/15) . 12/49 . 3/10 + 2/9 ] . x = 215/96`
`=> (10- 1275/7546 + 57/11 - 7/12. 12/49 . 3/10 + 2/9 ) . x = 215/96`
`=> ( 10- 1275/7546 + 57/11 -343/600 . 3/10 + 2/9 ) . x = 215/96`
`=> ( 10- 1275/7546 + 57/11 -343/2000 + 2/9 ) . x = 215/96`
`=>15,06357671 . x= 215/96`
`=> x= 215/96: 15,06357671`
`=>x= 0,1486754027`
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CMR:(10^k+8^k+6^k)-(9^k+7^k+5^k) (k thuộc N*)không chia hết cho 2
(10k+8k+6k)-(9k+7k+5k)=
=243k-213k=(24-21)3k-3k=3
Mà 3\(⋮̸2\)
⇒Hiệu trên ko chia hết cho 2 (kϵn*)
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In the figure below, x Câu 2 Find the measure of angle J if widehat{K}29^o K 29 o and angle J and K are supplementary. Answer: widehat{J} J ^o o . Câu 3 In the figure below, x Câu 4 In the figure below, x Câu 5 Solve: |2x-3|-43∣2x−3∣−43, where xx is a negative number. Answer: xx Câu 6 Calculate: 9+|-6|:1^2 9+∣−6∣:1 2 Câu 7 Compare: dfrac{36}{27} 27 36 dfrac{4}{3} 3 4 Câu 8 Find the negative number yy such that |y+dfrac{7}{2}|-dfrac{1}{2}4∣y+ 2 7 ∣− 2 1 4. Answer: yy Câu 9 Find xx su...
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In the figure below, x = Câu 2 Find the measure of angle J if \widehat{K}=29^o K =29 o and angle J and K are supplementary. Answer: \widehat{J}= J = ^o o . Câu 3 In the figure below, x = Câu 4 In the figure below, x = Câu 5 Solve: |2x-3|-4=3∣2x−3∣−4=3, where xx is a negative number. Answer: x=x= Câu 6 Calculate: 9+|-6|:1^2 =9+∣−6∣:1 2 = Câu 7 Compare: \dfrac{36}{27} 27 36 \dfrac{4}{3} 3 4 Câu 8 Find the negative number yy such that |y+\dfrac{7}{2}|-\dfrac{1}{2}=4∣y+ 2 7 ∣− 2 1 =4. Answer: y=y= Câu 9 Find xx such that \dfrac{32}{2^x}=2 2 x 32 =2. Answer: x=x= Câu 10 Find nn such that \dfrac{(-4)^n}{64}=-16 64 (−4) n =−16. Answer: n=n= Cần gấp nhé
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