Tìm x :
a. ( x - 15 ) .35 = 0
b. 32 ( x - 10 ) = 32
Nhớ trình bày cách làm .
Tìm x eN biết
a) (x –15) .15 = 0 b) 32 (x –10 ) = 32 c/ ( x – 5)(x – 7) = 0 d/ (x – 35).35 = 3
Tìm x thuộc N biết
A . (x-15)×15=0
B 32(x-10)=32
C (x-5) (x-7)=0
D(x-35) ×35=35
A.\(\left(x-15\right).15=0\)
\(x-15=0:15\)
\(x-15=0\)
\(x=15+0\)
\(x=15\)
B.\(32\left(x-10\right)=32\)
\(x-10=32:32\)
\(x-10=1\)
\(x=10+1\)
\(x=11\)
`a) `
`(x-15)xx15=0`
`<=> x-15 = 0 : 15`
`<=> x-15 = 0`
`<=> x = 0 + 15`
`<=> x =15`
`b)`
`32.(x-10)=32`
`<=> x - 10 = 32:32`
`<=>x-10=1`
`<=> x = 1+10`
`<=> x =11`
`c)`
`(x-5).(x-7)=0`
`<=>` \(\left[ \begin{array}{l}x-5 = 0\\x-7=0\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x=5\\x=7\end{array} \right.\)
`d)`
`(x-35)xx35=35`
`<=> x - 35 = 35:35`
`<=> x - 35 = 1`
`<=> x = 1+35`
`<=> x = 36`
(x –15) .15 = 0 b) 32 (x –10 ) = 32
c) ( x – 5)(x – 7) = 0 d) (x – 35).35 = 35
c)(x-5)(x-7)=0
x=5 hoặc x=7
Vậy \(x\in\left\{5;7\right\}\)
Tìm x
a, \(\frac{13x-16}{15}+\frac{x-32}{35}< \frac{x-6}{21}\)
b, \(\frac{5x+12}{14}+\frac{11x+28}{3}>\frac{4x+9}{17}\)
c, \(\left(2x-5\right).\left(x^2+4\right)< 0\)
trình bày cách làm nữa nha . lm dc 1 câu cx lm giúp mk nha
\(a.\)\(\frac{13x-16}{15}+\frac{x-32}{35}< \frac{x-6}{21}\)\(MC:105\)
\(\Leftrightarrow\frac{7\left(13x-16\right)}{105}+\frac{3\left(x-2\right)}{105}< \frac{5\left(x-6\right)}{105}\)
\(\text{Khử mẫu ta dc pt tương đương vs pt:}\)
\(\Leftrightarrow7\left(13x-16\right)+3\left(x-2\right)< 5\left(x-6\right)\)
\(\Leftrightarrow91x-112+3x-6< 5x-30\)
\(\Leftrightarrow94x-118< 5x-30\)
\(\Leftrightarrow94x-5x< 118-30\)
\(\Leftrightarrow89x< 88\)
\(\Leftrightarrow x< \frac{88}{89}\)
.\(b.\)\(\frac{5x+12}{14}+\frac{11x+28}{3}>\frac{4x+9}{17}\)\(MC:714\)
\(\text{Khi khử mẫu pt ta dc pt tương đương}:\):
\(\Leftrightarrow51\left(5x+12\right)+238\left(11x+28\right)>42\left(4x+9\right)\)
\(\Leftrightarrow255x+612+2618x+6664>168x+378\)
\(\Leftrightarrow2873x+7276>168x+378\)
\(\Leftrightarrow2873x-168x>-7276+378\)
\(\Leftrightarrow2705x>-6898\)
\(\Leftrightarrow x>-\frac{6898}{2705}\)
a) (5.9.x-25):12=0
b) 30.(x-28)=120
c) 84-4.(2.x+1)=48
d) [(X+32)-15].2=60
[.là dấu nhân]
trình bày cách làm ra.ai nhanh mình kb và tick cho
a,(5.9.x-25):12=0
(45.x-25):12=0
(45.x-25) =0x12
(45.x-25)=0
45.x=0+25
45.x=25
x=25:45
x=5/9
b,30.(x-28)=120
(x-28)=120:30
(x-28)=4
x=4+28
x=32
c'84-4.(2.x+1)=48
4.(2.x+1)=84-48
4.(2.x+1)=36
(2.x+1)=36:4
(2.x+1)=9
2.x=9-1
2.x=8
x=8:2
x=4
d,[(x+32)-15].2=60
[(x+32)-15]=60:2
[(x+32)-15]=30
(x+32)=30+15
(x+32)=45
x=45-32
x=13
a,
(5.9.x-15):12=0
45x-15=0
45x=0+15=15
x=45:15
x=3
b,
30(x-28)=120
x-28=120:30=4
x=4+28
x=32
c,
84-4(2.x+1)=48
4(2.x+1)=84-48=36
2x+1=36:4=9
2x=9-1=8
x=8:2
x=4
d,
[(x+32)-15].2=60
(x+32)-15=60:2=30
x+32=30+15=45
x=45-32
x=13
Bài 6. Tìm x ϵ N biết
a) (x –15) .15 = 0
b) 32 (x –10 ) = 32
c) ( x – 5)(x – 7) = 0
d) (x – 35).35 = 35
các bạn làm đầy đủ giúp mik với
Bài 6:
a)(x-15).15=0
⇔x-15=0
⇔x=15
b)32(x-10)=32
⇔x-10=1
⇔x=11
c)(x-5)(x-7)=0
⇔x-5=0 hay x-7=0
⇔x=5 hay x=7
d)(x-35)35=35
⇔x-35=1
⇔x=36
Bài 1 : Tìm X :
a) ( X - 140 ) : 7 = 33 - 23 x 3
b) X - 6 : 2 - ( 48 - 24 ) : 2 : 6 - 3 = 0
c) X + 5 x 2 - ( 32 + 18 x 3 : 6 - 15 ) = 0
Nhớ viết cách làm ra nha
Ai xong trước mình cho 2 tick
Bài 6. Tìm x ϵ N biết
a) (x –15) .15 = 0
b) 32 (x –10 ) = 32
c) ( x – 5)(x – 7) = 0
d) (x – 35).35 = 35
Bài 6:
a)(x-15).15=0
⇔x-15=0
⇔x=15
b)32(x-10)=32
⇔x-10=1
⇔x=11
c)(x-5)(x-7)=0
⇔x-5=0 hay x-7=0
⇔x=5 hay x=7
d)(x-35)35=35
⇔x-35=1
⇔x=36
a, x = 15
b, x = 11
c, x = 7 hoặc x = 5
d, x = 36
Bài 1 : Tìm X :
a) ( X - 140 ) : 7 = 33 - 23 x 3
b) X - 6 : 2 - ( 48 - 24 ) : 2 : 6 - 3 = 0
c) X + 5 x 2 - ( 32 + 18 x 3 : 6 - 15 ) = 0
Nhớ viết cách làm ra nha
Ai xong trước mình cho 2 tick