c)(x-5)(x-7)=0
x=5 hoặc x=7
Vậy \(x\in\left\{5;7\right\}\)
a, ⇒ x - 15 =0
⇒ x = 15
b, ⇒ x - 10 = 1
⇒ x = 11
c, \(\Rightarrow\left[{}\begin{matrix}x-5=0\\x-7=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=7\end{matrix}\right.\)
d, ⇒ x - 35 = 1
⇒ x = 36
\(\left(x-15\right).15=\)
\(\Rightarrow x-15=0\)
\(\Rightarrow x=15\)
\(\text{ 32 .(x –10 ) = 32 }\)
\(\Rightarrow x-10=1\)
\(\Rightarrow x=11\)
\(\text{( x – 5)(x – 7) = 0 }\)
\(\Rightarrow x-5=0\)
\(\Rightarrow x=5\)
\(\text{(x – 35).35 = 35}\)
\(\Rightarrow x-35=1\)
\(\Rightarrow x=36\)