(2x+1) . (3y -2)=-5

=> 2x+1 \(\in\)Ư(-5) = { 1; 5; -1; -5}

=> 2x \(\in\){ 0; 6; -2; -6}

=> x \(\in\){ 0; 3; -1; -3}

Sau bn tự thay nha

\(\left(2x+1\right)\left(3y-2\right)=5\)

Do x,y nguyên => 2x+1; 3y-2 nguyên

=> 2x+1; 3y-2\(\inƯ\left(5\right)=\left\{-5;-1;1;5\right\}\)

Vậy (x;y)=(-1;-1);(2;1)

a)125 : x = 2² - (-1)

125 : x = 4 + 1

125 : x = 5

x = 125 : 5

x = 25

-------------------------------------------------

b) 2x - 8 = -4

2x = (-4) + 8

2x = 4

x = 4 : 2 

x = 2

-----------------------------------------------------------

c) Xem lại đề.

\(125:x=2^2-\left(-1\right)\)

\(=>125:x=4+1\)

\(=>125:x=5\)

\(=>x=125:5\)

\(=>x=25\)

_____

\(2x-8=-4\)

\(=>2x=\left(-4\right)+8\)

\(=>2x=4\)

\(=>x=4:2\)

\(=>x=2\)

_______

\(6^{2x+5}=216\)

\(=>6^{2x+5}=6^3\)

\(=>2x+5=3\)

\(=>2x=3-5\)

\(=>2x=-2\)

\(=>x=\left(-2\right):2\)

\(=>x=-1\)

\(#NqHahh\)

125:x=2² - (-1)

125:x=4+1

125:x=5

X=125:5

X=25

2x -8 = -4

2x=-4+8

2x=4

X=4:2

X=2

6²(x+5)  = 216

36(x+5) = 216

X+5 = 216:36

X+5=6

X=6-5

X=1

\(2x-3.\left(2x+1\right)=4x-5.\left(x-3\right)\) )

\(\Leftrightarrow2x-6x-3-4x+5x-15=0\)

\(\Leftrightarrow-3x-18x=0\)

\(\Leftrightarrow x=-6\)

hãy k nếu bạn thấy đây là câu tl đúng :)

chúc bạn hok tốt :P

a/ 7x(2x+x) - 7x(x+3) =14

7x(2x+x-x-3)=14

x(2x-3)=2

=> x=2

Trả lời :

          Bạn kia trả lời đúng rồi !

Hok tốt nha !

\(\Leftrightarrow2x-1\in\left\{1;-1;7;-7\right\}\)

hay \(x\in\left\{1;0;4;-3\right\}\)

\(\Leftrightarrow\left(6x-10\right)⋮\left(2x-1\right)\\ \Leftrightarrow\left[3\left(2x-1\right)-7\right]⋮\left(2x-1\right)\\ \Leftrightarrow2x-1\inƯ\left(-7\right)=\left\{-7;-1;1;7\right\}\\ \Leftrightarrow2x\in\left\{-6;0;2;8\right\}\\ \Leftrightarrow x\in\left\{-3;0;1;4\right\}\)

a) Vì 2x-1 là bội của x+5 nên 2x-1 \(⋮\)x+5

=> x+5 \(⋮\)x+5

=> ( 2x-1) - ( x+5) \(⋮\)x+5

=> (2x-1) - 2(x+5) \(⋮\)x+5

=> 2x -1 - 2x -10 \(⋮\)x+5

=> -11 \(⋮\)x+5

=> x+5 \(\in\)Ư(11) ={ 1;11; -1; -11}

=> x\(\in\){ -4; 6; -6; -16}

Vậy....

Camr own bn nha

easy vãi không làm được à bạn ???????????

\(a.\left(x-1\right)=0\Leftrightarrow x=1\)

\(b.2x+5-x-9=0\Leftrightarrow x=4\)

Lời giải:

$x^2-2x+1-4y^2=5$
$\Leftrightarrow (x^2-2x+1)-4y^2=5$

$\Leftrightarrow (x-1)^2-(2y)^2=5$

$\Leftrightarrow (x-1-2y)(x-1+2y)=5$

Vì $x,y$ nguyên nên $x-1-2y, x-1+2y$ cũng nguyên. Khi đó ta có các TH sau:

TH1: $x-1-2y=1; x-1+2y=5$

$\Rightarrow (x,y)=(4, 1)$

TH2: $x-1-2y=-1; x-1+2y=-5$

$\Rightarrow (x,y)=(-2, -1)$

TH3: $x-1-2y=5, x-1+2y=1$

$\Rightarrow (x,y)=(4, -1)$

TH4: $x-1-2y=-5, x-1+2y=-1$

$\Rightarrow (x,y)=(-2,1)$