\(\dfrac{x+8}{12}+\dfrac{x+9}{11}+\dfrac{x+10}{10}+3=0\\ \Leftrightarrow\dfrac{x+8}{12}+1+\dfrac{x+9}{11}+1+\dfrac{x+10}{10}+1=0\\ \Leftrightarrow\dfrac{x+20}{12}+\dfrac{x+20}{11}+\dfrac{x+20}{10}=0\\ \Leftrightarrow\left(x+20\right)\left(\dfrac{1}{12}+\dfrac{1}{11}+\dfrac{1}{10}\right)=0\\ \Leftrightarrow x+20=0\Leftrightarrow x=-20\\ KL:...\)

`<=>((x+8)/12+1)+((x+9)/11+1)+((x+10)/10+1)=0`

`<=>(x+20)/12+(x+20)/11+(x+20)/10=0`

`<=>(x+20)(1/12+1/11+1/10)=0`

Vì `1/12+1/11+1/10 ≠ 0`

`=>x+20=0`

`=>x=0-20`

`=>x=-20`

\(a,\Leftrightarrow\left(x-9\right)^2-2\left(x-9\right)+1=0\\ \Leftrightarrow\left(x-9-1\right)^2=0\Leftrightarrow x=10\\ b,Sửa:49x^2-14x\sqrt{5}+5=0\\ \Leftrightarrow\left(7x-\sqrt{5}\right)^2=0\Leftrightarrow x=\dfrac{\sqrt{5}}{7}\)

-12+(x-9) < 0

=> -12+x-9 < 0

=> x - 21 < 0

=> x < 21

Vậy x < 21

Tk mk nha

            \(-12+\left(x-9\right)< 0\)

\(\Leftrightarrow\)\(x-21< 0\)

\(\Leftrightarrow\)\(x< 21\)

Vậy.....

      -12 + (x - 9) < 0

<=> x - 9 < 12

<=> x < 21

Đố xàm vcl

Ta có :\(\frac{x+8}{12}+\frac{x+9}{11}+\frac{x+10}{10}+3=0\)

=> \(\left(\frac{x+8}{12}+1\right)+\left(\frac{x+9}{11}+1\right)+\left(\frac{x+10}{10}+1\right)=0\)

=> \(\frac{x+20}{12}+\frac{x+20}{11}+\frac{x+20}{10}=0\)

=> \(\left(x+20\right)\left(\frac{1}{12}+\frac{1}{11}+\frac{1}{10}\right)=0\)

Vì \(\frac{1}{12}+\frac{1}{11}+\frac{1}{10}\ne0\)

=> x + 20 = 0

=> x = -20

Vậy x = -20

\(\frac{x+8}{12}+\frac{x+9}{11}+\frac{x+10}{10}+3=0\)

\(\Leftrightarrow\left(\frac{x+8}{12}+1\right)+\left(\frac{x+9}{11}+1\right)+\left(\frac{x+10}{10}+1\right)=0\)

\(\Leftrightarrow\frac{x+20}{12}+\frac{x+20}{11}+\frac{x+20}{10}=0\)

\(\Leftrightarrow\left(x+20\right)\left(\frac{1}{12}+\frac{1}{11}+\frac{1}{10}\right)=0\)

Vì \(\frac{1}{12}+\frac{1}{11}+\frac{1}{10}\ne0\)

\(\Rightarrow x+20=0\Rightarrow x=-20\)

cái bên vế phải chả hiểu là j ?? Tớ tạm đặt là    \(\alpha\)    nhé      (   \(\alpha\)là 1 hằng số    )

pt <=>   \(\left(\frac{x+8}{12}+1\right)+\left(\frac{x+9}{11}+1\right)+\left(\frac{x+10}{10}+1\right)=\alpha\)

<=>   \(\frac{x+20}{12}+\frac{x+20}{11}+\frac{x+20}{10}=\alpha\)

<=>   \(\left(x+20\right)\left(\frac{1}{12}+\frac{1}{11}+\frac{1}{10}\right)=\alpha\)

<=>   \(\frac{\left(x+20\right).181}{660}=\alpha\)

<=>   \(x=\frac{660\alpha}{181}-20\)

Bạn tự thay    \(\alpha\)là 1 số nào tùy ý cũng sẽ tìm ngay ra x thôi 

a) 2 . x + 12 = 36

2 . x = 36 - 12

2 . x = 24

x = 24 : 2

x = 12

Vậy x = 12

b) (x + 21)  : 8 + 12 = 21

( x + 21 ) : 8 = 21 - 12

( x + 21 ) : 8 = 9

x + 21 = 9 . 8

x + 21 = 72

x = 72 - 21

x = 51

Vậy x = 51

c) (3 . x - 18) . (x - 9) = 0

\(\Rightarrow\begin{cases}3.x-18=0\\x-9=0\end{cases}\)

\(\Rightarrow\begin{cases}3.x=18\\x=0+9\end{cases}\)

\(\Rightarrow\begin{cases}x=18:3=6\\x=9\end{cases}\)

Vậy \(x\in\left\{6;9\right\}\)

a)

\(2x+12=36\)

\(\Rightarrow2\left(x+6\right)=36\)

\(\Rightarrow x+6=18\)

=> x = 12

Vậy x = 12

b)

\(\left(x+21\right):8+12=21\)

\(\Rightarrow\left(x+21\right):8=9\)

\(\Rightarrow x+21=72\)

=> x = 51

Vậy x = 51

c)

\(\left(3x-18\right)\left(x-9\right)=0\)

\(\Rightarrow3\left(x-6\right)\left(x-9\right)=0\)

\(\Rightarrow\left(x-6\right)\left(x-9\right)=0\)

\(\Rightarrow\left[\begin{array}{nghiempt}x-6=0\\x-9=0\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=6\\x=9\end{array}\right.\)

Vậy x = 6 ; x = 9

a) \(2x+12=36\Leftrightarrow2x=24x\Leftrightarrow x=12\)

b) \(x+21:8+12=21\)

\(\Leftrightarrow\frac{x+21}{8}=9\)

\(\Leftrightarrow x+21=72\)

\(\Leftrightarrow x=51\)

c) \(\left(3.x-18\right).\left(x-9\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}3x-18=0\\x-9=0\end{array}\right.\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=6\\x=9\end{array}\right.\)

Chúc bạn học tốt 

a) \(x+546=46\\ x=46-546\\ x=-500\)

b) \(2x-19\times3=27\\ 2x-57=27\\ 2x=27+57\\ 2x=84\\ x=84:2\\ x=42\)

c) \(x+12=23+3\times3^4\\ x+12=23+3\times81\\ x=23+243-12\\ x=254\)

d) \(x-12=3-3\times2^4\\ x-12=3-3\times16\\ x=3-48+12\\ x=-33\)

e) \(\left(27-x\right)\left(x+9\right)=0\\ \Rightarrow\left[{}\begin{matrix}27-x=0\\x+9=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=27\\x=-9\end{matrix}\right.\)

f) \(\left(-x\right)\left(x-43\right)=0\\ \Rightarrow\left[{}\begin{matrix}-x=0\\x-43=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=43\end{matrix}\right.\)

a) x + 546 = 46

x = 46 - 546

x = -500

b) 2x - 19 x 3 = 27

2x - 57 = 27

2x = 27 + 57

2x = 84

x = 84 : 2

x = 42

c) x + 12 = 23 + 3 x 3⁴

x + 12 = 23 + 3 x 81

x + 12 = 23 + 243

x + 12 = 266

x = 266 - 12

x = 254

d) x - 12 = 3 - 3 x 2⁴

x - 12 = 3 - 3 x 16

x - 12 = 3 - 48

x - 12 = -45

x = -45 + 12

x = -33

e) (27 - x) x (x + 9) = 0

TH1: 27 - x = 0

x = 27 - 0

x = 27

TH2: x + 9 = 0

x = 0 + 9

x = 9

⇒ x = 27 hoặc x = 9

f) (-x) x (x - 43) = 0

TH1: -x = 0

⇒ x = 0

TH2: x - 43 = 0

x = 0 + 43

x = 43

⇒ x = 0 hoặc x = 43.