\(3\sqrt{50}-2\sqrt{98}-5\sqrt{18}-\sqrt{63}+2\sqrt{28}\)
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3\(\sqrt{56}-2\sqrt{98}-5\sqrt{18}-\sqrt{63}+2\sqrt{28}\)
\(3\sqrt{56}-2\sqrt{98}-5\sqrt{18}-\sqrt{63}+2\sqrt{28}=3\sqrt{4.14}-2\sqrt{49.2}-5\sqrt{9.2}-\sqrt{9.7}+2\sqrt{4.7}=3.2\sqrt{14}-2.7\sqrt{2}-5.3\sqrt{2}-3\sqrt{7}+2.2\sqrt{7}=6\sqrt{14}-14\sqrt{2}-15\sqrt{2}-3\sqrt{7}+4\sqrt{7}=6\sqrt{14}-29\sqrt{2}+\sqrt{7}\)
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Tinh
a, \(3\sqrt{50}-2\sqrt{98}-5\sqrt{18}-\sqrt{63}-2\sqrt{28}\)
b, \(\sqrt{42-10\sqrt{17}}+\sqrt{3-8\sqrt{17}}\)
c, \(\frac{4}{\sqrt{3}+1}+\frac{6}{\sqrt{3}-3}-\frac{5}{\sqrt{3}-2}\)
Rút Gọn1.3sqrt{3}+4sqrt{12}-5sqrt{27}2.sqrt{32}-sqrt{50}+sqrt{18}3.sqrt{72}+sqrt{4frac{1}{2}}-sqrt{32}-sqrt{162}4.left(sqrt{325}-sqrt{117}+2sqrt{208}right):sqrt{13}5.left(sqrt{12}-sqrt{48}-sqrt{108}-sqrt{192}right):2sqrt{3}6.left(2sqrt{112}-5sqrt{7}+2sqrt{63}-2sqrt{28}right)sqrt{7}7.left(2sqrt{27}-3sqrt{48}+3sqrt{75}-sqrt{192}right)left(1-sqrt{3}right)8.7sqrt{24}-sqrt{150}-5sqrt{54}9.2sqrt{20}-sqrt{50}+3sqrt{80}-sqrt{320}10.sqrt{32}-sqrt{50}+sqrt{98}-sqrt{72}11.3sqrt{2}-4sqrt{18}+2sqrt{32}-sqrt{...
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Rút Gọn
1.\(3\sqrt{3}+4\sqrt{12}-5\sqrt{27}\)
2.\(\sqrt{32}-\sqrt{50}+\sqrt{18}\)
3.\(\sqrt{72}+\sqrt{4\frac{1}{2}}-\sqrt{32}-\sqrt{162}\)
4.\(\left(\sqrt{325}-\sqrt{117}+2\sqrt{208}\right):\sqrt{13}\)
5.\(\left(\sqrt{12}-\sqrt{48}-\sqrt{108}-\sqrt{192}\right):2\sqrt{3}\)
6.\(\left(2\sqrt{112}-5\sqrt{7}+2\sqrt{63}-2\sqrt{28}\right)\sqrt{7}\)
7.\(\left(2\sqrt{27}-3\sqrt{48}+3\sqrt{75}-\sqrt{192}\right)\left(1-\sqrt{3}\right)\)
8.\(7\sqrt{24}-\sqrt{150}-5\sqrt{54}\)
9.\(2\sqrt{20}-\sqrt{50}+3\sqrt{80}-\sqrt{320}\)
10.\(\sqrt{32}-\sqrt{50}+\sqrt{98}-\sqrt{72}\)
11.\(3\sqrt{2}-4\sqrt{18}+2\sqrt{32}-\sqrt{50}\)
12.\(5\sqrt{48}-4\sqrt{27}-2\sqrt{75}+\sqrt{108}\)
13.\(2\sqrt{24}-2\sqrt{54}+3\sqrt{6}-\sqrt{150}\)
14.\(\sqrt{125}-2\sqrt{20}-3\sqrt{80}+4\sqrt{45}\)
15.\(2\sqrt{28}+2\sqrt{63}-3\sqrt{175}+\sqrt{112}\)
16.\(10\sqrt{28}-2\sqrt{275}-3\sqrt{343}-\frac{3}{2}\sqrt{396}\)
\(2\sqrt{8\sqrt{3}}-\sqrt{2\sqrt{3}}-\sqrt{9\sqrt{12}}\)
\(\sqrt{3}+\sqrt{7-4\sqrt{3}}\)
\(\sqrt{\left(\sqrt{7}-4\right)^2}-\sqrt{28}+\sqrt{63}\)
\(\left(15\sqrt{50}+5\sqrt{200}-3\sqrt{450}\right):\sqrt{10}\)
\(\sqrt{3}-2\sqrt{48}+3\sqrt{75}-4\sqrt{108}\)
a: \(2\sqrt{8\sqrt{3}}-\sqrt{2\sqrt{3}}-\sqrt{9\sqrt{12}}\)
\(=2\sqrt{4\cdot2\sqrt{3}}-\sqrt{2\sqrt{3}}-\sqrt{9\cdot2\sqrt{3}}\)
\(=4\sqrt{2\sqrt{3}}-\sqrt{2\sqrt{3}}-3\sqrt{2\sqrt{3}}\)
=0
b: \(\sqrt{3}+\sqrt{7-4\sqrt{3}}\)
\(=\sqrt{3}+\sqrt{\left(2-\sqrt{3}\right)^2}\)
\(=\sqrt{3}+\left|2-\sqrt{3}\right|\)
\(=\sqrt{3}+2-\sqrt{3}\)
=2
c: \(\sqrt{\left(\sqrt{7}-4\right)^2}-\sqrt{28}+\sqrt{63}\)
\(=\left|\sqrt{7}-4\right|-2\sqrt{7}+3\sqrt{7}\)
\(=4-\sqrt{7}+\sqrt{7}\)
=4
d: \(\left(15\sqrt{50}+5\sqrt{200}-3\sqrt{450}\right):\sqrt{10}\)
\(=\dfrac{\sqrt{10}\left(15\sqrt{5}+5\sqrt{20}-3\sqrt{45}\right)}{\sqrt{10}}\)
\(=15\sqrt{5}+5\sqrt{20}-3\sqrt{45}\)
\(=15\sqrt{5}+5\cdot2\sqrt{5}-3\cdot3\sqrt{5}\)
\(=16\sqrt{5}\)
e: \(\sqrt{3}-2\sqrt{48}+3\sqrt{75}-4\sqrt{108}\)
\(=\sqrt{3}-2\cdot4\sqrt{3}+3\cdot5\sqrt{3}-4\cdot6\sqrt{3}\)
\(=\sqrt{3}-8\sqrt{3}+15\sqrt{3}-24\sqrt{3}\)
\(=-16\sqrt{3}\)
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Rút Gọn 1.3sqrt{2}-4sqrt{18}-2sqrt{32}-sqrt{50}2,5sqrt{48}-4sqrt{27}-2sqrt{75}+sqrt{108}3,2sqrt{24}-2sqrt{54}+3sqrt{6}-sqrt{150}4,sqrt{125}-2sqrt{20}-3sqrt{80}+4sqrt{45}5,2sqrt{28}+2sqrt{63}-3sqrt{175}+sqrt{112}6,10sqrt{28}-2sqrt{275}-3sqrt{343}-frac{3}{2}sqrt{396}
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Rút Gọn
1.\(3\sqrt{2}-4\sqrt{18}-2\sqrt{32}-\sqrt{50}\)
2,\(5\sqrt{48}-4\sqrt{27}-2\sqrt{75}+\sqrt{108}\)
3,\(2\sqrt{24}-2\sqrt{54}+3\sqrt{6}-\sqrt{150}\)
4,\(\sqrt{125}-2\sqrt{20}-3\sqrt{80}+4\sqrt{45}\)
5,\(2\sqrt{28}+2\sqrt{63}-3\sqrt{175}+\sqrt{112}\)
6,\(10\sqrt{28}-2\sqrt{275}-3\sqrt{343}-\frac{3}{2}\sqrt{396}\)
bài 2a) 4sqrt{28}+3sqrt{63}-3sqrt{11.2}-2sqrt{175}b) sqrt{5}.left(sqrt{5}-3sqrt{20}+2sqrt{80}right)c) left(sqrt{dfrac{16}{3}}-sqrt{dfrac{25}{3}}right).sqrt{3}e) left(sqrt{dfrac{32}{3}}-sqrt{54}+sqrt{dfrac{50}{3}}right).sqrt{6}f) left(sqrt{6}-2right).left(sqrt{3}+sqrt{2}right)
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bài 2
a) \(4\sqrt{28}+3\sqrt{63}-3\sqrt{11.2}-2\sqrt{175}\)
b) \(\sqrt{5}.\left(\sqrt{5}-3\sqrt{20}+2\sqrt{80}\right)\)
c) \(\left(\sqrt{\dfrac{16}{3}}-\sqrt{\dfrac{25}{3}}\right).\sqrt{3}\)
e) \(\left(\sqrt{\dfrac{32}{3}}-\sqrt{54}+\sqrt{\dfrac{50}{3}}\right).\sqrt{6}\)
f) \(\left(\sqrt{6}-2\right).\left(\sqrt{3}+\sqrt{2}\right)\)
a) Ta có: \(4\sqrt{28}+3\sqrt{63}-3\sqrt{112}-2\sqrt{175}\)
\(=8\sqrt{7}+9\sqrt{7}-12\sqrt{7}-10\sqrt{7}\)
\(=-5\sqrt{7}\)
b) Ta có: \(\sqrt{5}\left(\sqrt{5}-3\sqrt{20}+2\sqrt{80}\right)\)
\(=\sqrt{5}\left(\sqrt{5}-6\sqrt{5}+8\sqrt{5}\right)\)
\(=\sqrt{5}\cdot3\sqrt{5}=15\)
c) Ta có: \(\left(\sqrt{\dfrac{16}{3}}-\sqrt{\dfrac{25}{3}}\right)\cdot\sqrt{3}\)
\(=\dfrac{-1}{\sqrt{3}}\cdot\sqrt{3}\)
=-1
e) Ta có: \(\left(\sqrt{\dfrac{32}{3}}-\sqrt{54}+\sqrt{\dfrac{50}{3}}\right)\cdot\sqrt{6}\)
\(=\left(\dfrac{4\sqrt{2}}{\sqrt{3}}+\dfrac{5\sqrt{2}}{\sqrt{3}}-3\sqrt{6}\right)\cdot\sqrt{6}\)
\(=\dfrac{9\sqrt{12}}{\sqrt{3}}-18\)
\(=0\)
f) Ta có: \(\left(\sqrt{6}-2\right)\left(\sqrt{3}+\sqrt{2}\right)\)
\(=3\sqrt{2}+2\sqrt{3}-2\sqrt{2}-2\sqrt{2}\)
\(=\sqrt{2}\)
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rút gọn biểu thức
a) 3sqrt{8}-4sqrt{18}+5sqrt{32}-sqrt{50}
b) (15sqrt{50}+5sqrt{200}-3sqrt{450}) : 10
c) 2sqrt{28}+2sqrt{63}-3sqrt{175}+sqrt{112}
d) (sqrt{14}-3sqrt{2})^2 +6sqrt{28}
e) sqrt{left(1-sqrt{2018}right)^2}. sqrt{2019+2sqrt{2018}}
f) left(sqrt{6}-sqrt{5}right)^2-sqrt{120}
g)12left(2sqrt{3}-3sqrt{2}right)^2+2sqrt{6}+3sqrt{4}
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rút gọn biểu thức
a) \(3\sqrt{8}-4\sqrt{18}+5\sqrt{32}-\sqrt{50}\)
b) (\(15\sqrt{50}+5\sqrt{200}-3\sqrt{450}\)) : 10
c) \(2\sqrt{28}+2\sqrt{63}-3\sqrt{175}+\sqrt{112}\)
d) (\(\sqrt{14}-3\sqrt{2}\))\(^2\) +\(6\sqrt{28}\)
e) \(\sqrt{\left(1-\sqrt{2018}\right)^2}\). \(\sqrt{2019+2\sqrt{2018}}\)
f) \(\left(\sqrt{6}-\sqrt{5}\right)^2-\sqrt{120}\)
g)\(12\left(2\sqrt{3}-3\sqrt{2}\right)^2+2\sqrt{6}+3\sqrt{4}\)
a) \(3\sqrt{8}-4\sqrt{18}+5\sqrt{32}-\sqrt{50}=3\sqrt{4.2}-4\sqrt{9.2}+5\sqrt{16.2}-\sqrt{25.2}=6\sqrt{2}-12\sqrt{2}+20\sqrt{2}-5\sqrt{2}=9\sqrt{2}\)b) \(\left(15\sqrt{50}+5\sqrt{200}-3\sqrt{450}\right):10=\left(15\sqrt{50}+5\sqrt{50.4}-3\sqrt{50.9}\right):10=\left(15\sqrt{50}+10\sqrt{50}-9\sqrt{50}\right):10=\dfrac{16\sqrt{50}}{10}=\dfrac{16\sqrt{25.2}}{10}=\dfrac{80\sqrt{2}}{10}=8\sqrt{2}\) c) \(2\sqrt{28}+2\sqrt{63}-3\sqrt{175}+\sqrt{112}=2\sqrt{7.4}+2\sqrt{7.9}-3\sqrt{7.25}+\sqrt{7.16}=4\sqrt{7}+6\sqrt{7}-15\sqrt{7}+4\sqrt{7}=-\sqrt{7}\)
d)
\(\left(\sqrt{14}-3\sqrt{2}\right)^2+6\sqrt{28}=14-2.3\sqrt{2.14}+18+6\sqrt{28}=32-6\sqrt{28}+6\sqrt{28}=32\)
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tính1.sqrt{147}+sqrt{54}-4sqrt{27}2.sqrt{28}-4sqrt{63}+7sqrt{112}3.sqrt{49}-5sqrt{28}+dfrac{1}{2}sqrt{63}4.left(2sqrt{6}-4sqrt{3}-dfrac{1}{4}sqrt{8}right).3sqrt{6}5.(2sqrt{1dfrac{9}{16}}-5sqrt{5dfrac{1}{16}}):sqrt{16}6.left(sqrt{48}-3sqrt{27}-sqrt{147}right):sqrt{3}7.left(sqrt{50}-3sqrt{49}right):sqrt{2}-sqrt{162}:sqrt{2}8.left(2sqrt{1dfrac{9}{10}}-sqrt{5dfrac{1}{10}}right):sqrt{10}9.2sqrt{dfrac{16}{3}}-3sqrt{dfrac{1}{27}}-6sqrt{dfrac{4}{75}}10.2sqrt{27}-6sqrt{dfrac{4}{3}}+dfrac{3}{5}sqrt{75}11....
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tính
1.\(\sqrt{147}+\sqrt{54}-4\sqrt{27}\)
2.\(\sqrt{28}-4\sqrt{63}+7\sqrt{112}\)
3.\(\sqrt{49}-5\sqrt{28}+\dfrac{1}{2}\sqrt{63}\)
4.\(\left(2\sqrt{6}-4\sqrt{3}-\dfrac{1}{4}\sqrt{8}\right).3\sqrt{6}\)
5.(\(2\sqrt{1\dfrac{9}{16}}-5\sqrt{5\dfrac{1}{16}}\)):\(\sqrt{16}\)
6.\(\left(\sqrt{48}-3\sqrt{27}-\sqrt{147}\right):\sqrt{3}\)
7.\(\left(\sqrt{50}-3\sqrt{49}\right):\sqrt{2}-\sqrt{162}:\sqrt{2}\)
8.\(\left(2\sqrt{1\dfrac{9}{10}}-\sqrt{5\dfrac{1}{10}}\right):\sqrt{10}\)
9.\(2\sqrt{\dfrac{16}{3}}-3\sqrt{\dfrac{1}{27}}-6\sqrt{\dfrac{4}{75}}\)
10.\(2\sqrt{27}-6\sqrt{\dfrac{4}{3}}+\dfrac{3}{5}\sqrt{75}\)
11.\(\dfrac{\sqrt{18}}{\sqrt{2}}-\dfrac{\sqrt{12}}{\sqrt{3}}\)
12.\(\dfrac{\sqrt{27}}{\sqrt{3}}+\dfrac{\sqrt{98}}{\sqrt{2}}-\sqrt{175}:\sqrt{7}\)
13.\(\left(\dfrac{\sqrt{8}}{\sqrt{2}}-\dfrac{\sqrt{180}}{\sqrt{5}}\right).\sqrt{5}-\sqrt{\dfrac{81}{11}}.\sqrt{11}\)
14.\(\sqrt{8\sqrt{3}}-2\sqrt{25\sqrt{12}}+4\sqrt{\sqrt{192}}\)
15.\(\left(3\sqrt{2}-2\sqrt{3}\right)\left(3\sqrt{2}+2\sqrt{3}\right)\)
16.\(\left(1+\sqrt{5}-\sqrt{3}\right)\left(1+\sqrt{5}+\sqrt{3}\right)\)
Thực hiện phép tính \(\sqrt{50}-3\sqrt{98}+2\sqrt{8}+3\sqrt{32}-5\sqrt{18}\)
\(\sqrt{50}-3\sqrt{98}+2\sqrt{8}+3\sqrt{32}-5\sqrt{18}\)
\(=5\sqrt{2}-21\sqrt{2}+4\sqrt{2}+12\sqrt{2}-15\sqrt{12}\)
\(=-15\sqrt{2}\)
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