\(M=xy^3+5xyz-4x^2+6-x^3y+2xyz-xy^3+x^2-5\)

     \(=7xyz-3x^2-x^3y+1\)

Ta có: \(M-2xyz+xy^3-x^2+5=xy^3+5xyz-4x^2+6-x^3y\)

\(\Leftrightarrow M=xy^3+5xyz-4x^2+6-x^3y+2xyz-xy^3+x^2-5\)

\(\Leftrightarrow M=7xyz-3x^2-x^3y+1\)

`M-2xyz+xy^3-x^2+5=xy^3+5xyz-4x^2+6-x^3y`
`<=>M=xy^3+5xyz-4x^2+-x^3y+2xyz-xy^3+x^2-5`
`<=>M=-3x^2-x^3y+7xyz+1`

M = xy^3 + 5xyz -4x^2 +6 -x^3y+(-2xyz+xy^3-x^2+5)

M= xy^3+5xyz -4x^2 +6-X^3y+-2xyz+xy^3-x^2+5

M=(xy^3+xy^3)+(5xyz-2xyz)+(-4x^2-x^2)+(6+5)-x^3y

M= 2xy^3+3xyz+-5x^2+11-X^3y

1) \(4x^2-7x-2=4x^2-8x+x-2=\left(4x^2-8x\right)+\left(x-2\right)\)

\(=4x\left(x-2\right)+\left(x-2\right)=\left(x-2\right)\left(4x+1\right)\)

2) \(4x^2+5x-6=4x^2+8x-3x-6=\left(4x^2+8x\right)-\left(3x+6\right)\)

\(=4x\left(x+2\right)-3\left(x+2\right)=\left(x+2\right)\left(4x-3\right)\)

3) \(5x^2-18x-8=5x^2-20x+2x-8=\left(5x^2-20x\right)+\left(2x-8\right)\)

\(=5x\left(x-4\right)+2\left(x-4\right)=\left(x-4\right)\left(5x+2\right)\)

4) \(xy\left(x+y\right)-yz\left(y+z\right)+xz\left(x-z\right)\)

\(=xy\left(x+y\right)-y^2z-yz^2+x^2z-xz^2\)

\(=xy\left(x+y\right)+\left(x^2z-y^2z\right)-\left(yz^2+xz^2\right)\)

\(=xy\left(x+y\right)+z\left(x^2-y^2\right)-z^2.\left(x+y\right)\)

\(=xy\left(x+y\right)+z\left(x-y\right)\left(x+y\right)-z^2\left(x+y\right)\)

\(=xy\left(x+y\right)+\left(zx-zy\right)\left(x+y\right)-z^2\left(x+y\right)\)

\(=\left(x+y\right)\left(xy+xz-yz-z^2\right)=\left(x+y\right).\left[x\left(y+z\right)-z\left(y+z\right)\right]\)

\(=\left(x+y\right)\left(y+z\right)\left(x-z\right)\)

1) 4x² - 7x - 2 = 4x² - 8x + x - 2 = 4x( x - 2 ) + ( x - 2 ) = ( x - 2 )( 4x + 1 )

2) 4x² + 5x - 6 = 4x² - 8x + 3x - 6 = 4x( x - 2 ) + 3( x - 2 ) = ( x - 2 )( 4x + 3 )

3) 5x² - 18x - 8 = 5x² - 20x + 2x - 8 = 5x( x - 4 ) + 2( x - 4 ) = ( x - 4 )( 5x + 2 )

4) xy( x + y ) - yz( y + z ) + xz( x - z )

= x²y + xy² - y²z - yz² + xz( x - z )

= ( x²y - yz² ) + ( xy² - y²z ) + xz( x - z )

= y( x² - z² ) + y²( x - z ) + xz( x - z )

= y( x - z )( x + z ) + y²( x - z ) + xz( x - z )

= ( x - z )[ y( x + z ) + y² + xz ]

= ( x - z )( xy + yz + y² + xz )

= ( x - z )[ ( xy + y² ) + ( xz + yz ) ]

= ( x - z )[ y( x + y ) + z( x + y ) ]

= ( x - z )( x + y )( y + z )

5) xy( x + y ) + yz + xz( x + z ) + 2xyz ( đề có thiếu không vậy .-. )

\(4x^2-7x-2=\left(4x^2-8x\right)+\left(x-2\right)=4x\left(x-2\right)+\left(x-2\right)=\left(4x-1\right)\left(x-2\right)\)

\(=4x^2+8x-3x-6=4x\left(x+2\right)-3\left(x+2\right)=\left(4x-3\right)\left(x+2\right)\)

\(=5x^2-18x-8=5x^2-20x+2x-8=5x\left(x-4\right)+2\left(x-4\right)=\left(5x+2\right)\left(x-4\right)\)

\(5=\left(x+y\right)\left(y+z\right)\left(z+x\right)\)

* Đa thức thu gọn là đa thức không còn hai hạng tử nào đồng dạng

A = (xy⁷- xy⁷) + (x³y⁵-x³y⁵)+x⁸+10

A = x⁸+10

* M + N

= (5xyz -5x² + 8xy + 5)+(5x²+2xyz-8xy-7+y²)

= 5xyz - 5x² +8xy +5+5x² +2 xyz - 8xy -7 + y²

= ( 5xyz + 2xyz ) + ( -5x² +5x²) + ( 8xy - 8xy ) + ( 5-7) +y²

= 7xyz - 2 + y²

* M - N

= ( 5xyz - 5x² +8xy +5) - ( 5x² + 2xyz - 8xy -7 +y²)

= 5xyz - 5x² + 8xy + 5 - 5x² - 2xyz + 8xy + 7 - y²

= ( 5xyz - 2xyz) + ( -5x² - 5x²) + ( 8xy + 8xy) + ( 5+7) -y²

= 3xyz - 10x² +16xy +12 -y²

mọi người ơi giúp mk với mk đang cần gấp

a) \(-xy\cdot2x^3y^4\cdot-\dfrac{5}{4}x^2y^3\)

\(=\left(-1\cdot2\cdot-\dfrac{5}{4}\right)\cdot\left(x\cdot x^3\cdot x^2\right)\cdot\left(y\cdot y^4\cdot y^3\right)\)

\(=\dfrac{5}{2}x^6y^8\)

Bậc là: \(6+8=14\)

Hệ số: \(\dfrac{5}{2}\)

Biến: \(x^6y^8\)

b) \(5xyz\cdot4x^3y^2\cdot-2x^5y\)

\(=\left(5\cdot4\cdot-2\right)\cdot\left(x\cdot x^3\cdot x^5\right)\cdot\left(y\cdot y^2\cdot y\right)\cdot z\)

\(=-40x^9y^4z\)

Bậc là: \(9+4=13\)

Hệ số: \(-40\)

Biến: \(x^9y^4z\)

c) \(-2xy^5\cdot-x^2y^2\cdot7x^2y\)

\(=\left(-2\cdot-1\cdot7\right)\cdot\left(x\cdot x^2\cdot x^2\right)\cdot\left(y^5\cdot y^2\cdot y\right)\)

\(=14x^6y^8\)

Bậc là: \(6+8=14\)

Hệ số: \(14\)

Biến: \(x^6y^8\)

b: \(=\dfrac{3a-9-2a-6-6}{\left(a+3\right)\left(a-3\right)}=\dfrac{a-15}{a^2-9}\)