5.(x+7) -10 =23.5
5+5/23.5/27+5/2018
________________
7+7/23.7/27+7/2018
=5.(1+1/23+1/27+1/2018)
_______________________=5/7
7.(1+1/23+1/27+1/2018)
\(\frac{5.\left(1+\frac{1}{23}+\frac{1}{27}+\frac{1}{2018}\right)}{7.\left(1+\frac{1}{23}+\frac{1}{27}+\frac{1}{2018}\right)}\)
=5/7
3.(x - 32) – 7 = 23.5 -50
`#3107.101107`
\(3\left(x-32\right)-7=23\cdot5-50\)
\(\Rightarrow3\left(x-32\right)-7=115-50\)
\(\Rightarrow3\left(x-32\right)-7=65\)
\(\Rightarrow3\left(x-32\right)=65+7\)
\(\Rightarrow3\left(x-32\right)=72\)
\(\Rightarrow x-32=72\div3\)
\(\Rightarrow x-32=24\)
\(\Rightarrow x=24+32\)
\(\Rightarrow x=56\)
Vậy, `x = 56.`
\(3\left(x-32\right)-7=23.5-50\)
\(3\left(x-32\right)-7=115-50\)
\(3\left(x-32\right)-7=65\)
\(3\left(x-32\right)=65+7\)
\(3\left(x-32\right)=72\)
\(x-32=72:3\)
\(x-32=24\)
\(x=24+32\)
\(x=56\)
a; \(\dfrac{9}{27}\) + \(\dfrac{7}{-49}\)
= \(\dfrac{1}{3}\) - \(\dfrac{1}{7}\)
= \(\dfrac{7}{21}\) - \(\dfrac{3}{21}\)
= \(\dfrac{4}{21}\)
b; - \(\dfrac{12}{10}\) + \(\dfrac{-25}{30}\)
= - \(\dfrac{6}{5}\) - \(\dfrac{5}{6}\)
= -\(\dfrac{36}{30}\) - \(\dfrac{25}{30}\)
= \(\dfrac{-61}{30}\)
c; \(\dfrac{-20}{35}\) + \(\dfrac{-16}{-24}\)
= - \(\dfrac{4}{7}\) + \(\dfrac{2}{3}\)
= - \(\dfrac{12}{21}\) + \(\dfrac{14}{21}\)
= \(\dfrac{2}{21}\)
d; - \(\dfrac{21}{77}\) + \(\dfrac{10}{-35}\)
= - \(\dfrac{3}{11}\) - \(\dfrac{2}{7}\)
= - \(\dfrac{21}{77}\) - \(\dfrac{22}{77}\)
= - \(\dfrac{43}{77}\)
Điền vào ô vuông các dấu thích hợp (=; <; >):
a) 2 3 . 5 + 3 4 . 2 - 4 . ( 5 7 : 5 5 ) □ 15 : ( 3 5 : 3 4 ) + 5 . 2 4 - 7 2 - 4 ;
b) ( 3 5 . 3 7 ) : 3 1 0 + 5 . 2 4 □ 5 . 2 2 . 2 3 - 4 . ( 5 8 : 5 6 ) ;
c) 2 [ ( 7 - 3 3 : 3 2 ) : 2 2 + 99 ] - 100 □ 3 4 . 2 + 2 3 . 5 - 7 ( 5 2 - 5 ) ;
d) 207 : { 2 ^ 3 . [ ( 156 - 128 ) : 14 ] + 7 ] □ 117 : { [ 79 - 3 ( 3 ^ 3 - 17 ) ] : 7 + 2 }
Giá trị của x để x + 23.5 + 70 ⋮ 5 là
A. 37
B. 75
C. 99
D. 104
Ta có: 23.5 ⋮ 5 ; 70 ⋮ 5 .
Để x + 23.5 + 70 ⋮ 5 thì x phải chia hết cho 5 .
Trong các đáp án có 75 ⋮ 5 .
Vậy 75 là đáp án đúng.
Giá trị của x để (x+23.5+70) ⋮ 5 là
A. 37
B. 75
C. 99
D. 104
1) 5/7.37 13/23-51 13/23.5/7
2) -2/3 +1/3+0,5+2 1/2
3)-0,5+2/3+1/2
4) (8+2 1/3-3/5) -(5+0,4)-(3 1/2 -2)
5) (2/9-7/12):3/4+(16/9-5/12):3/4
6) -(2021.0,7+19,75) +0,7- (8-19,75)
7)15/34+7/21+19/34-20/15
8) 2 5/6+1/6:(-5/8)
9) (-2)^2 +2/9. (4/5-2/3)
10) (-1/5+3/7):5/4+(-4/5+4/7):5/4
11) 2022,2021 . 1954,1945+ 2022,2021 . (-1954,1945)
12) -5,2 .72 +69,1 +5,2 . (-28)+(-1,1)
13) (7 -1/2-3/4) : (5-1/4-5/8)
14) (8+ 2 1/3 -3/5) -(5+0,4) -( 3 1/3 - 2)
`@` `\text {Ans}`
`\downarrow`
`1)`
`5/7*37 13/23 - 51 13/23*5/7`
`= 5/7* (37 13/23 - 51 13/23)`
`= 5/7* (-14)`
`= -10`
`2)`
`-2/3 +1/3+0,5+2 1/2`
`= -2/3 + 1/3 + 1/2 + 5/2`
`= (-2/3+1/3) + (1/2+5/2)`
`= -1/3 + 3`
`=8/3`
`3)`
`-0,5+2/3+1/2`
`= -1/2 + 2/3 + 1/2`
`= (-1/2 + 1/2) + 2/3`
`= 2/3`
`4)`
`(8+2 1/3-3/5) -(5+0,4)-(3 1/2 -2)`
`= 8+ 7/3 - 3/5 - 5 - 0,4 - 7/2 + 2`
`= (8+2-5) + (-3/5 - 2/5) + (7/3 - 7/2)`
`= 5 - 1 - 7/6`
`= 4 - 7/6 = 17/6`
`5)`
`(2/9-7/12):3/4+(16/9-5/12):3/4`
`= (2/9 - 7/12) \times 4/3 + (16/9 - 5/12) \times 4/3`
`= 4/3 *(2/9 - 7/12 + 16/9 - 5/12)`
`= 4/3 * [(2/9 + 16/9) + (-7/12 - 5/12)]`
`= 4/3 * ( 2 - 1)`
`= 4/3 * 1 = 4/3`
`6)`
`-(2021.0,7+19,75) +0,7- (8-19,75)`
`= -2021*0,7 -19,75 + 0,7 - 8 + 19,75`
`= 0,7*(-2021 + 1) - 8`
`= -1414-8`
`= -1422`
`7)`
`15/34+7/21+19/34-20/15`
`= (15/34 + 19/34) + 7/21 - 20/15`
`= 1 + 7/21 - 20/15`
`= 4/3 - 20/15 =0`
`8)`
`2 5/6+1/6:(-5/8)`
`= 17/6 + (-4/15)`
`= 77/30`
`9)`
`(-2)^2 +2/9. (4/5-2/3)`
`= 4 + 2/9*2/15`
`= 4+4/135`
`= 544/135`
`10)`
`(-1/5+3/7):5/4+(-4/5+4/7):5/4`
`= (-1/5+3/7) * 4/5 + (-4/5+4/7) * 4/5`
`= 4/5*(-1/5 +3/7-4/5+4/7)`
`= 4/5*[(-1/5-4/5)+(3/7+4/7)]`
`= 4/5* (-1+1)`
`= 4/5*0=0`
`11)`
`2022,2021 . 1954,1945+ 2022,2021 . (-1954,1945)`
`= 2022,2021 * [1954,1945 + (-1954,1945)]`
`= 2022,2021*0 `
`= 0`
`12)`
`-5,2 .72 +69,1 +5,2 . (-28)+(-1,1)`
`= -5,2*72 + 69,1 - 5,2*28 - 1,1`
`= -5,2*(72+28) + (69,1 - 1,1)`
`= -5,2*100 + 68`
`= -520 + 68`
`= -452`
`13)`
`(7 -1/2-3/4) : (5-1/4-5/8)`
`= 23/4 \div 33/8`
`=46/33`
`14)`
`(8+ 2 1/3 -3/5) -(5+0,4) -( 3 1/3 - 2)`
`= 8+ 2 1/3 - 3/5 - 5 - 0,4 - 3 1/3 + 2`
`= (8+2-5) + (2 1/3 - 3 1/3) - (0,6 + 0,4) `
`= 5 - 1 - 1`
`= 3`
2: \(=\dfrac{-1}{3}+3=\dfrac{8}{3}\)
3: =1/2-1/2+2/3=2/3
5: \(=\dfrac{4}{3}\left(\dfrac{2}{9}-\dfrac{7}{12}+\dfrac{16}{9}-\dfrac{5}{12}\right)=\dfrac{4}{3}\)
12: \(=5.2\left(-72-28\right)+68=-520+68=-452\)
13: \(\dfrac{23}{4}:\dfrac{33}{8}=\dfrac{46}{33}\)
Tìm số tự nhiên x biết rằng
720:[41-(2x-5)]=23.5
(x+1)+(x+2)+(x+3)+…+(x+100)=5750
a: =>41-(2x-5)=720:40=18
=>2x-5=23
=>2x=28
=>x=14
b: =>100x+5050=5750
=>100x=700
=>x=7
a: =>41-(2x-5)=720:40=18
=>2x-5=23
=>2x=28
=>x=14
b: =>100x+5050=5750
=>100x=700
=>x=7
(25.21 + 25.51) : 36
{188 - [ 33 + (62 - 7.3)]}:70
tìm x
(x - 1)(15-3x)=0
720: [ 41-(2x + 5)]=23.5
\(\left(25\cdot21+25\cdot51\right):36\\ =\left[25\cdot\left(21+51\right)\right]:36\\ =\left(25\cdot72\right):36\\ =1800:36\\ =50\\ \left\{188-\left[33+\left(6^2-7\cdot3\right)\right]\right\}:70\\ =\left\{188-\left[33+\left(36-21\right)\right]\right\}:70\\ =\left[188-\left(33+15\right)\right]:70\\ =\left(188-48\right):70\\ =140:70\\ =2\)
\(\left(x-1\right)\left(15-3x\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-1=0\\15-3x=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\3x=15\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=1\\x=5\end{matrix}\right.\)
\(720:\left[41-\left(2x+5\right)\right]=2^3\cdot5=8\cdot5\\ \Rightarrow720:\left[41-\left(2x+5\right)\right]=40\\ \Rightarrow41-\left(2x+5\right)=720:40\\ \Rightarrow41-\left(2x+5\right)=18\\ \Rightarrow2x+5=41-18\\ \Rightarrow2x+5=23\\ \Rightarrow2x=23-5\\ \Rightarrow2x=18\\ \Rightarrow x=18:2\\ \Rightarrow x=9\)
a) (25.21 + 25.51) : 36
= [ 25.( 21 + 51 ) ] : 36
= [ 25. 72 ] : 36
= 1800 : 36
= 50.