(m : 1 - m  x 1) : (m x 2008 + m + 2008)

= (m - m) : (m  x 2008 + m + 2008)

= 0 : (m x 2008 + m + 2008)

= 0 

(m : 1 - m x 1) : (m x 2008 + m + 2008)

= (m - m) : (m x 2008 + m x 2008)

= 0 : (m x 2008 + m x 2008)

= 0(bất kì số nào chia cho 0 sẽ = 0)

 (m : 1 - m x 1) : (m x 2008 + m + 2008)

=(m-m):(m x 2008 + m + 2008)

=0: (m x 2008 + m + 2008)

=0

  326*728 + 327*272

= 237328 + 88944

= 326272

  { m : 1 - m * 1 } : { m * 2008 + m + 2008 }

= { m -m } :  { m * 2008 + m + 2008 }

= 0 :  { m * 2008 + m + 2008 }

= 0 

326 x 728 + 327 x 272

= 237328  + 88944

= 326272

b2 ={ m - m) : { m x 2008 + m + 2008

     = 0 : { m x 2008 + m + 200 8 }

      = 0

=64642160 nha bạn

`@` `\text {Ans}`

`\downarrow`

`a,`

\(\text{326 x 728 + 327 x 272}\)

`= 326 \times 728 + 326 \times 272 + 272`

`= 326 \times (728 + 272) + 272`

`= 326 \times 1000 + 272`

`= 362000 + 272`

`= 362272`

`b,`

\(\text{2008 x 867 + 2009 x 133}\)

`= 2008 \times 867 + 2008 \times 133 + 133`

`= 2008 \times (867 + 133) + 133`

`= 2008 \times 1000 + 133`

`= 2008000 + 133`

`= 2008133`

`c,`

\(\text{1235 x 6789 x (630 - 315 x 2 )}\)

`= 1235 \times 6789 \times (630 - 630)`

`= 1235 \times 6789 \times 0`

`= 0`

`d,`

\((m \div 1 - m \times 1 ) \div ( m \times 2008 + m + 2008)\)

`= (m - m) \div (m \times 2008 + m + 2008)`

`= 0 \div (m \times 2008 + m + 2008)`

`= 0`

a: =326*728+326*272+272

=326000+272

=326272

c: \(=1235\cdot6789\cdot\left(630-630\right)=0\)

d: \(=\left(m-m\right):\left(20009m+2008\right)=0\)

TICK CHO MÌNH NHA

Giải:

 326 x 728 + 327 x 272

= 326 x 728 + 326 x 272 + 272

= 326 x ( 728 +272 ) +272

= 326 x 1000 + 272

= 326 000 +272

= 326 272

TICK CHO MÌNH NHA

Giải:

 2008 x 867 +2009 x 133

= 2008 x 867 + 2008 x 133 +133

= 2008 x ( 867 + 133) +133

= 2008 x 1000 +133

= 2 008 000 + 133

= 2 008 133

a) Ta có: \(326\cdot728+327\cdot272\)

\(=326\cdot728+326\cdot272+272\)

\(=32600+272\)

\(=32872\)

b) Ta có: \(2008\cdot867+2009\cdot133\)

\(=2008\cdot867+2008\cdot133+133\)

\(=2008000+133\)

\(=2008133\)

c) Ta có: \(1235\cdot6789\cdot\left(630-315\cdot2\right)\)

\(=1235\cdot6789\cdot0\)

=0

\(M:N=\frac{\frac{2008}{1}+\frac{2007}{2}+\frac{2006}{3}+...+\frac{2}{2007}+\frac{1}{2008}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+...+\frac{1}{2008}+\frac{1}{2009}}\)

Ta có tử số bằng: 2008+2007/2+2006/3+2005/4+…..+2/2007+1/2008 
(Phân tích 2008 thành 2008 con số 1 rồi đưa vào các nhóm) 
= (1 + 2007/2) + (1 + 2006/3) + (1 + 2005/4) +... + (1 + 2/2007) + ( 1 + 1/2008) + (1) 
= 2009/2 + 2009/3 + 2009//4 + ……. + 2009/2007 + 2009/2008 + 2009/2009 
= 2009 x (1/2 + 1/3 + 1/4 + ... + 1/2007 + 1/2008 + 1/2009) 
Mẫu số: 1/2 + 1/3 + 1/4 + ... + 1/2007 + 1/2008 + 1/2009 
\(\Rightarrow M:N=\frac{2009.\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+...+\frac{1}{2008}+\frac{1}{2009}\right)}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+...+\frac{1}{2008}+\frac{1}{2009}}=2009\)

a: \(\Leftrightarrow\dfrac{x}{2008}-\dfrac{2}{20}-\dfrac{2}{30}-\dfrac{2}{42}-...-\dfrac{2}{240}=\dfrac{5}{8}\)

\(\Leftrightarrow\dfrac{x}{2008}-2\left(\dfrac{1}{20}+\dfrac{1}{30}+...+\dfrac{1}{240}\right)=\dfrac{5}{8}\)

\(\Leftrightarrow\dfrac{x}{2008}-2\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+...+\dfrac{1}{15}-\dfrac{1}{16}\right)=\dfrac{5}{8}\)

\(\Leftrightarrow\dfrac{x}{2008}-2\left(\dfrac{1}{4}-\dfrac{1}{16}\right)=\dfrac{5}{8}\)

\(\Leftrightarrow\dfrac{x}{2008}-2\cdot\dfrac{3}{16}=\dfrac{5}{8}\)

=>x/2008=1

hay x=2008

b: \(\dfrac{7}{x}+\dfrac{4}{5\cdot9}+\dfrac{4}{9\cdot13}+...+\dfrac{4}{41\cdot45}=\dfrac{29}{45}\)

\(\Leftrightarrow\dfrac{7}{x}+\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{13}+...+\dfrac{1}{41}-\dfrac{1}{45}=\dfrac{29}{45}\)

\(\Leftrightarrow\dfrac{7}{x}+\dfrac{8}{45}=\dfrac{29}{45}\)

=>7/x=21/45=7/15

=>x=15