\(x^2 +5x-6\)
\(5x^2 +5xy-x-y\)
\(7x-6x^2 -2\)
Phân tích thành nhân tử
Phân tích thành nhân tử:
x^2 + 5x - 6
5x^2 + 5xy - x - y
7x - 6x^2 - 2
\(x^2+5x-6=x^2-x+6x-6=x\left(x-1\right)+6\left(x-1\right)=\left(x+6\right)\left(x-1\right)\)
\(5x^2+5xy-x-y=5x\left(x+y\right)-\left(x+y\right)=\left(5x-1\right)\left(x+y\right)\)
\(7x-6x^2-2=3x-6x^2+4x-2=3x\left(1-2x\right)-2\left(1-2x\right)=\left(3x-2\right)\left(1-2x\right)\)
\(a,x^2+5x-6=x^2-x+6x-6\)
\(=x\left(x-1\right)+6\left(x-1\right)=\left(x-1\right)\left(x+6\right)\)
\(b,5x^2+5xy-x-y=5x\left(x+y\right)-\left(x+y\right)\)
\(=\left(x+y\right)\left(5x-1\right)\)
\(c,7x-6x^2-2=-6x^2+3x+4x-2\)
\(=-3x\left(2x-1\right)+2\left(2x-1\right)=\left(2x-1\right)\left(2-3x\right)\)
1) x2 + 5x - 6
= (x2 - x) + (6x - 6)
= x(x - 1) + 6(x - 1)
= (x - 1)(x + 6)
2) 5x2 + 5xy - x - y
= (5x2 + 5xy) + (-x - y)
= -(x + y) + 5x(x + y)
= (x + y)(5x - 1)
3) 7x - 6x2 - 2
= -(6x2 - 7x + 2)
= -(2x - 1)(3x - 2)
phân tích thành nhân tử
a, x2 + 5x - 6
b, 5x2 + 5xy - x - y
c, 7x - 6x2 - 2
Ta có : x2 - x + 6x - 6
= x(x - 1) + 6(x - 1)
= (x + 6)(x - 1)
b) 5x2 + 5xy - x - y
= 5x(x + y) - (x + y)
= (5x - 1)(x + y)
câu a,b làm như trên. câu c:
c, 7x - 6x2 - 2 = -6x^2 + 7x - 2 = -( 6x^2-3x-4x+2) = -[ 3x ( 2x-1)-2(2x-1)]=-(3x-2)(2x-1)
Phân tích thành nhân tử
\(x^2+5x-6\)
\(5x^2+5xy-x-y\)
\(7x-6x^2-2\)
\(x^2+5x-6=x^2-6x+x-6=x\left(x-6\right)+\left(x-6\right)=\left(x+1\right)\left(x-6\right)\)
\(5x^2+5xy-x-y=5x\left(x+y\right)-\left(x+y\right)=\left(5x-1\right)\left(x+y\right)\)
\(7x-6x^2-2=-6x^2+7x-2=-6\left(x^2-\frac{7}{6}x+\frac{1}{3}\right)=-6\left(x^2-\frac{7}{6}x+\frac{49}{144}-\frac{1}{144}\right)=-6\left[\left(x-\frac{7}{12}\right)^2-\frac{1}{144}\right]\)
1) x2-x+6x-6 = x(x-1)+6(x-1)=(x+6)(x-1)
2) 5x(x+y)-(x+y) =(5x-1)(x+y)
3) -6x2+7x-2 = -6x2+3x+4x-2= -6x(x-\(\frac{1}{2}\)) +4(x-\(\frac{1}{2}\)) =(-3x+2)(2x-1)
Phân tích đa thức thành nhân tử:
1, x^3-x+y^3-4
2, 4x^2-y^2+4x+1
3, x^4+2x^3+x^2
4, x^2+5x-6
5, 7x-6x^2-2
6, 5x^2+5xy-x-y
7, 2x^2+3x-5
8,x^4-5x^2+4
9, x^3-5x^2+45-9x
10, x^4-2x^3-2x^2-2x-3
11, 81x^4+4
12,x^5+x+1
13, x^4+6x^3+7x^2-6x+1
14, x(x+4)(x+6)(x+10)+128
2: =(2x+1)^2-y^2
=(2x+1+y)(2x+1-y)
3: =x^2(x^2+2x+1)
=x^2(x+1)^2
4: =x^2+6x-x-6
=(x+6)(x-1)
5: =-6x^2+3x+4x-2
=-3x(2x-1)+2(2x-1)
=(2x-1)(-3x+2)
6: =5x(x+y)-(x+y)
=(x+y)(5x-1)
7: =2x^2+5x-2x-5
=(2x+5)(x-1)
8: =(x^2-1)*(x^2-4)
=(x-1)(x+1)(x-2)(x+2)
9: =x^2(x-5)-9(x-5)
=(x-5)(x-3)(x+3)
Phân tích thành nhân tử :
a) \(x^2+5x-6\)
b) \(5x^2+5xy-x-y\)
c) \(7x-6x^2-2\)
a) \(x^2+5x-6\)
\(=x^2-2x+3x-6\\ =\left(x^2-2x\right)+\left(3x-6\right)\\ =x\left(x-2\right)+3\left(x-2\right)\\ =\left(x-2\right)\left(x+3\right)\)
b) \(5x^2+5xy-x-y\)
\(=\left(5x^2+5xy\right)-\left(x+y\right)\\ =5x\left(x+y\right)-\left(x+y\right)\\ =\left(x+y\right)\left(5x+1\right)\)
c)\(7x-6x^2-2\)
\(=3x+4x-6x^2-2\\ =\left(3x-6x^2\right)+\left(4x-2\right)\\ =3x\left(1-2x\right)+2\left(2x-1\right)\\ =3x\left(1-2x\right)-2\left(1-2x\right)\\ =\left(1-2x\right)\left(3x-2\right)\)
a, x2 + 5x + 6
x2+2x+3x+6
x(x+2)+3(x+2)
(x+2)(x+3)
b,5x(x+y)-(x+y)
(x+y)(5x-1)
c,-6x2+7x-2
-6x2 +3x+4x-2
-3x(2x-1)+2(2x-1)
(2x-1)(1-3x)
Phân tích thành nhân tử
a) x^2+5x-6
b) 5x^2+5xy-x-y
c) 7x-6x^2-2
d) x^2+4x+3
e) 2x^2+3x-5
f) 16x-5x^2-3
giải chi tiết
nhiều quá, các bn ngại làm, chia nhỏ ra,mk làm cho 2 câu
a) x2 +5x -6 = x2 -x +x + 5x -6
= x2 -x +6x -6
= x( x-1) + 6(x-1) = (x-1)(x+6)
b) 5x2 +5xy -x-y = 5x(x+y) -(x+y)
= (x+y)(5x-1)
e) \(2x^2+3x-5\)
\(=2x^2+5x-2x-5\)
\(=x\cdot\left(2x+5\right)-\left(2x+5\right)\)
\(=\left(x-1\right)\left(2x+5\right)\)
f) \(16x-5x^2-3\)
\(=-5x^2+16x-3\)
\(=-5x^2+15+x-3\)
\(=-5\cdot\left(x-3\right)+x-3\)
\(=\left(-5x+1\right)\left(x-3\right)\)
c)7x-\(6x^2\)-2
=3x + 4x - \(6x^2\) - 2
=(3x - \(6x^2\)) - (2 - 4x)
= 3x(1 - 2x) - 2(1 - 2x)
=(1-2x)(3x-2)
Phân tích đa thức thành nhân tử bằng cách phối hợp nhiều phương pháp.
1/ x2 + 5x - 6
2/ 5x2 + 5xy x - y
3/ 7x - 6x2 - 2
\(1,x^2+5x-6=x^2-x+6x-6=x\left(x-1\right)+6\left(x-1\right)=\left(x-1\right)\left(x+6\right)\)
\(3,7x-6x^2-2=-6x^2+7x-2=-6x^2+3x+4x-2=3x\left(-2x+1\right)+2\left(2x-1\right)\)
\(=3x\left(1-2x\right)-2\left(1-2x\right)=\left(1-2x\right)\left(3x-2\right)\)
\(2,5x^2+5xy-x-y=5x\left(x+y\right)-\left(x+y\right)=\left(x+y\right)\left(5x-1\right)\)
Phân tích đa thức thành nhân tử
1, x\(^2\)-xy+x-y
2, xz+yz-5x-5y
3, 3x\(^2\)-3xy-5x+5y
4, x\(^2\)-2xy+y\(^2\)-xz+yz
5, 3x\(^2\)+6xy+3y\(^2\)-3z\(^2\)
6, 45+x\(^{^{ }3}\)-5x\(^2\)-9x
7, x\(^2\)-6x+5
8,x\(^2\)+7x+12
9, 2x\(^2\)-7x+3
10, 3x\(^2\)-12y\(^2\)
11, 5xy\(^2\)-10xyz+5xz\(^2\)
12,x\(^2\)-y\(^2\)-x+y
13, a\(^3\)x-ab+b-x
14, (1+x\(^2\))-4x(1-x\(^2\))
CÁC CẬU GIẢI CHI TIẾT GIÚP MÌNH VỚI Ạ
13: =x(a^3-1)-b(a-1)
=x(a-1)(a^2+a+1)-b(a-1)
=(a-1)(a^2x+a*x+x-b)
12: =(x-y)(x+y)-(x-y)
=(x-y)(x+y-1)
10: =3(x^2-4y^2)
=3(x-2y)*(x+2y)
7: =x^2-x-5x+5=(x-1)(x-5)
8: =x^2+3x+4x+12=(x+3)(x+4)
9: =2x^2-6x-x+3=(x-3)(2x-1)
phân tích thành nhân tử
\(x^2 +xy-2x-2y\)
\(x^2 -xy-6x+6y\)
\(5xy^2 -5x+y^2 -1\)
`@` `\text {Ans}`
`\downarrow`
`x^2 + xy - 2x - 2y`
`= (x^2 - 2x) + (xy - 2y)`
`= x(x - 2) + y(x - 2)`
`= (x + y)(x - 2)`
____
`x^2 - xy - 6x + 6y`
`= (x^2 - 6x) - (xy - 6y)`
`= x(x - 6) - y(x - 6)`
`= (x - y)(x - 6)`
____
`5xy^2 - 5x + y^2 - 1`
`= (5xy^2 + y^2) - (5x + 1)`
`= y^2(5x + 1) - (5x + 1)`
`= (y^2 - 1)(5x + 1)`
`= (y - 1)(y + 1)(5x + 1)`
a: =(x^2+xy)-(2x+2y)
=x(x+y)-2(x+y)
=(x+y)(x-2)
b: =(x^2-xy)-(6x-6y)
=x(x-y)-6(x-y)
=(x-y)(x-6)
c: =5xy^2+y^2-5x-1
=y^2(5x+1)-(5x+1)
=(5x+1)(y^2-1)
=(5x+1)(y+1)(y-1)