a)      Ta có \(\frac{{ - 2}}{3} < 0\) và \(\frac{1}{{200}} > 0\) nên \(\frac{{ - 2}}{3}\)<\(\frac{1}{{200}}\).

b)      Ta có: \(\frac{{139}}{{138}} > 1\) và \(\frac{{1375}}{{1376}} < 1\) nên \(\frac{{139}}{{138}}\) > \(\frac{{1375}}{{1376}}\).

c)      Ta có: \(\frac{{ - 11}}{{33}} = \frac{{ - 1}}{3}\) và \(\frac{{25}}{{ - 76}} = \frac{{ - 25}}{{76}} > \frac{{ - 25}}{{75}} = \frac{{ - 1}}{3}\,\,\,\, \Rightarrow \frac{{25}}{{ - 76}} > \frac{{ - 11}}{33}\).

a: -2/3<0<1/200

b: 139/138>1

1375/1376<1

=>139/138>1375/1376

c: -11/33=-1/3=-25/75<-25/76

7/139

33^9<11^21

33⁹ > 11²¹

\(33^9< 11^{21}\)

\(\dfrac{11}{33}=\dfrac{11}{3.11}=\dfrac{1}{3}\)

\(\dfrac{25}{76}< \dfrac{25}{75}=\dfrac{1}{3}\)

\(\Rightarrow\dfrac{11}{33}>\dfrac{25}{76}\)

\(\Rightarrow-\dfrac{11}{33}< -\dfrac{25}{76}\)

\(\Rightarrow\dfrac{-11}{33}< \dfrac{25}{-76}\)

11/15<33/39

\(\frac{11}{15}=\frac{11\times39}{15\times39}=\frac{429}{585}\)

\(\frac{33}{39}=\frac{33\times15}{39\times15}=\frac{495}{585}\)

Vậy.................

ta có: \(\frac{33}{39}=\frac{33:3}{39:3}=\frac{11}{13}\)vì \(\frac{11}{13}>\frac{11}{15}\)nên \(\frac{33}{39}>\frac{11}{15}\)

Ta có: \(\dfrac{33}{39}\) = \(\dfrac{11}{13}\):\(\dfrac{11}{35}\) 

Vì \(\dfrac{11}{35}\)và\(\dfrac{11}{13}\)có cùng tử số

=> \(\dfrac{11}{35}\)<\(\dfrac{11}{13}\)=> \(\dfrac{11}{35}\)<\(\dfrac{33}{39}\)

\(\dfrac{33}{39}\)

11 phần 35 >  33 phần 39

So sánh $\frac{11}{35}$ và $\frac{33}{39}$

Ta có : $\frac{33}{39}=\frac{11}{13}$

    $\frac{11}{35}=\frac{11\times 13}{35\times 13}=\frac{143}{455}$

    $\frac{11}{13}=\frac{11\times 35}{13\times 35}=\frac{385}{455}$

Vì $143<385$ nên $\frac{143}{455}<\frac{385}{455}$

Vậy $\frac{11}{35}<\frac{33}{39}$

Câu hỏi của Quỳnh Anh - Toán lớp 6 - Học toán với OnlineMath

Em tham khảo câu 1 2 cách 2 bạn hướng dẫn nhé!

a: \(33^{44}=\left(33^4\right)^{11}\)

\(44^{33}=\left(44^3\right)^{11}\)

mà \(33^4>44^3\)

nên \(33^{44}>44^{33}\)