a) \(\Rightarrow2^x=32\Rightarrow2^x=2^5\Rightarrow x=5\)

b) \(\Rightarrow\left(2x+1\right)^3=5^3\)

\(\Rightarrow2x+1=5\Rightarrow x=2\)

c) \(\Rightarrow2^x=32\Rightarrow x=5\)

d) \(\Rightarrow4^3.4^x=4^5\Rightarrow4^x=4^2\Rightarrow x=2\)

e) \(\Rightarrow3^3.3^x=3^5\Rightarrow3^x=3^2\Rightarrow x=2\)

f) \(\Rightarrow7^2.7^x=7^4\Rightarrow7^x=7^2\Rightarrow x=2\)

a. 2^x . 4 = 128

<=> 2^{x + 2} = 2⁷

<=> x + 2 = 7

<=> x = 5

b. (2x + 1)³ = 125

<=> (2x + 1)³ - 5³ = 0

<=> (2x + 1 - 5)\(\left[\left(2x+1\right)^2+\left(2x+1\right).5+25\right]=0\)

<=> (2x - 4)(4x² + 4x + 1 + 10x + 5 + 25) = 0

<=> (2x - 4)(4x² + 14x + 31) = 0

<=> \(\left[{}\begin{matrix}2x-4=0\\4x^2+14x+31=0\end{matrix}\right.\)

<=> \(\left[{}\begin{matrix}x=2\\VôNghiệm\end{matrix}\right.\)

c. 2^x - 26 = 6

<=> 2^x = 32

<=> x = 5

d. 64 . 4^x = 4⁵

<=> 4³ . 4^x = 4⁵

<=> 4^{3 + x} = 4⁵

<=> 3 + x = 5

<=> x = 2

e. 27 . 3^x = 243

<=> 3³ . 3^x = 3⁵

<=> 3^{3 + x} = 3⁵

<=> 3 + x = 5

<=> x = 2

g. 49 . 7^x = 2401 (Bn xem lại đề câu này)

<=> 7² . 7^x = 7⁴

<=> 7^{2 + x} = 7⁴

<=> 2 + x = 4

<=> x = 2

a, 2^x.4= 128

=> 2^x= 128:4

=>2^x= 32

=> 2^x=2⁵

=> x=5

\(\left(2x+1\right)^3=125\)

\(\Rightarrow\left(2x+1\right)^3=\left(\pm5\right)^3\)

\(\Rightarrow\left[{}\begin{matrix}2x+1=5\\2x+1=-5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=4\\2x=-6\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=2\\x=-3\end{matrix}\right.\)

c, 2^x - 26 = 6

=> 2^x = 32

=> 2^x= 2⁵

=> x=5 

d, 64. 4^x = 4⁵

=> 4³. 4^x= 4⁵

=> 3+x=5

=> x=2

e, 27. 3^x= 243

=> 3³. 3^x= 3⁵

=> 3+x=5

=> x=2

Hoctot

`a) 27.3^x =243`

`3^x=243/27=9`

`3^x=3^2`

`=>x=2`

`b) 49.7^x =2401`

`7^x = 2401/49=49`

`7^x=7^2`

`=>x=2`

`c) 3^x +25 =26*2^2+2.3^0`

`3^x = 26.4+2.1-25 = 81`

`3^x =3^4`

`=>x=4`

\(e,27.3^x=243\\ \Leftrightarrow3^3.3^x=3^5\\ \Leftrightarrow3^{3+x}=3^5\\ \Rightarrow3+x=5\\ \Leftrightarrow x=2\\ g,49.7^x=2401\\ \Leftrightarrow7^2.7^x=7^4\\ \Leftrightarrow7^{2+x}=7^4\\ \Rightarrow2+x=4\\ \Leftrightarrow x=2\\ h,3^x+25=26.2^2+2.3^0\\ \Leftrightarrow3^x+25=26.4+2.1\\ \Leftrightarrow3^x=104+2-25\\ \Leftrightarrow3^x=81=3^4\\ Vậy:x=4\)

Tách ?

`a, 70 -5.(x-3) =45`

`=> 5.(x-3)= 70-45`

`=> 5.(x-3)=25`

`=>x-3=25:5`

`=>x-3=5`

`=>x= 5+3`

`=>x=8`

______

`b,10 + 2.x = 4^5:4^3`

`=> 10 + 2.x = 4^(5-3)`

`=> 10 + 2.x =4^2=16`

`=> 2.x=16-10`

`=>2.x=6`

`=>x=6:2`

`=>x=3`

_____

`c,60-3.x-2=51`

`=>  60-3.x= 51+2`

`=> 60-3.x=53`

`=>3.x=60-53`

`=> 3.x= 7`

`=>x= 7/3`

____

`d, 4.x-20=2^5:2^3`

`=> 4.x-20=2^(5-3)`

`=> 4.x-20=2^2`

`=> 4.x= 4+20`

`=>4.x=24`

`=>x=24:4`

`=>x=6`

____

`2^x . 4=16`

`=> 2^x=16:4`

`=>2^x= 4`

`=>2^x=2^2`

`=>x=2`

____

`f, 3^x . 3=243`

`=>3^x=243:3`

`=> 3^x=81`

`=> 3^x=3^3`

`=>x=3`

_____

`g, 64. 4^x =16^8`

`=> 4^3 . 4^x=(4^2)^8`

`=> 4^3 . 4^x = 4^(16)`

`=> 4^x= 4^(16-3)`

`=>4^x=4^(13)`

`=>x=13`

_____

`2^x . 16^2 =1024`

`=> 2^x= 1024 : 16^2`

`=>2^x=4`

`=>2^x=2^2`

`=>x=2`

a: =>5(x-3)=25

=>x-3=5

=>x=8

b: =>2x=16-10=6

=>x=3

c: =>58-3x=51

=>3x=7

=>x=7/3

d: =>4x-20=4

=>4x=24

=>x=6

e: =>2^x=4

=>2^x=2^2

=>x=2

f: =>3^x=81

=>3^x=3^4

=>x=4

g: =>4^x*4^3=4^16

=>x+3=16

=>x=13

h: =>2^x=1024/256=4=2^2

=>x=2

a) \(\left(2x+1\right)^3=125\)

\(\left(2x+1\right)^3=5^3\)

\(2x+1=5\)

\(2x=4\)

\(x=2\)

b) \(3^x+25=26\times2^2+2\times3^0\)

\(3^x+25=26\times4+2\times1\)

\(3^x+25=106\)

\(3^x=106-25\)

\(3^x=81\)

\(3^x=3^4\)

\(x=4\)

(2x+1)3 = 125 

a)<=> (2x+1)3 = 53

<=> 2x+1 = 5

<=> 2x = 4

<=> x = 2

3^x+25=26 . 2^2 + 2. 3^0

b)3^x+25=104 +2

3^x+25=106

3^x=106+25

3^x=81=3^4

=> x=4                                                                      

a: Ta có: \(2^{x-1}=32\)

\(\Leftrightarrow x-1=5\)

hay x=6

b: Ta có: \(3^{2x+1}=81\)

\(\Leftrightarrow2x+1=4\)

\(\Leftrightarrow2x=3\)

hay \(x=\dfrac{3}{2}\)

c: Ta có: \(2^x-26=6\)

\(\Leftrightarrow2^x=32\)

hay x=5

d: Ta có: \(27\cdot3^x=243\)

\(\Leftrightarrow3^x=9\)

hay x=2

a,  2 x . 2 2 = 32

2 x + 2 = 2 5

x + 2 = 5

x = 3

Vậy x = 3

b,  27 . 3 x = 243

3 3 . 3 x = 3 5

3 3 + x = 3 5

x + 3 = 5

x = 2

Vậy x = 2

c,  2 x . 2 4 = 1024

2 x + 4 = 2 10

x + 4 = 10

x = 6

Vậy x = 6

d,  49 . 7 x = 2401

7 2 . 7 x = 7 4

7 2 + x = 7 4

2 + x = 4

x = 2

Vậy x = 2

3:

a: 3^x*3=243

=>3^x=81

=>x=4

b; 2^x*16^2=1024

=>2^x=4

=>x=2

c: 64*4^x=16^8

=>4^x=4^16/4^3=4^13

=>x=13

d: 2^x=16

=>2^x=2^4

=>x=4

a)\(2x.4=128\)                                       

   \(2x=128:4\)                                                                                                 

  \(2x=32\)                                                        

    \(x=32:2\)

    \(x=16\)

Đề bạn hơi rối , mình dịch đề sai thì thông cảm ạ !

a) 2x . 4 = 128

=> 8x = 128

=> x = 16

b) ( 2x + 1 )³ = 125

=> ( 2x + 1 )³ = 5³

=> 2x + 1 = 5

=> 2x = 4

=> x = 2

c) Sửa đề : ( 2x - 2 ) . 6 = 6

=> 2x - 2 = 1

=> 2x = 3

=> x = 1,5

d) 64 . 4x = 45

=> 256x = 15

=> \(x=\frac{15}{256}\)

e) 27 . 3x = 243

=> 81x = 243

=> x = 3

f) 49 . 7x = 2401 

=> 343x = 2401

=> x = 7

g) 3x = 81

=> x = 81 : 3 = 27

h) 3⁴ . 3^x = 3⁷

=> 3^4+x = 3⁷

=> x + 4 = 7

=> x = 3

k) 3x + 2⁵ = 2⁶ . 2 + 2 . 3⁰

=> 3x + 2⁵ = 2⁷ + 2

=> 3x - 2 = 2⁷ - 2⁵

=> 3x - 2 = 2⁵ . ( 2² - 1 )

=> 3x - 2 = 32 . 3

=> 3x - 2 = 96

=> 3x = 98

Câu nài tui ko biết