Ta có:

\(\dfrac{-1234}{1244}=-1+\dfrac{10}{1244}\)

\(\dfrac{-4321}{4331}=-1+\dfrac{10}{4331}\)

Vì \(\dfrac{10}{1244}>\dfrac{10}{4331}\)

\(\Rightarrow-1+\dfrac{10}{1244}>-1+\dfrac{10}{4331}\)

hay \(\dfrac{-1234}{1244}>\dfrac{-4321}{4331}\)

\(\dfrac{1234}{1244}< \dfrac{1234+3037}{1244+3037}=\dfrac{4331}{4321}\)

\(\Rightarrow\dfrac{1234}{1244}< \dfrac{4331}{4321}\)

\(\Rightarrow-\dfrac{1234}{1244}>-\dfrac{4331}{4321}\)

\(\Rightarrow\dfrac{-1234}{1244}>\dfrac{4331}{-4321}\)

Thành ko chép mạng nhé

a) ta có \(\frac{1234}{1235}=1-\frac{1}{1235}\)

\(\frac{4319}{4320}=1-\frac{1}{4320}\)

vì \(\frac{1}{1235}>\frac{1}{4320}\Rightarrow1-\frac{1}{1235}< 1-\frac{1}{4320}\)

\(\Rightarrow\frac{1234}{1235}< \frac{4319}{4320}\)

b) ta có \(\frac{1234}{1244}=1-\frac{10}{1244}\)

\(\frac{4321}{4331}=1-\frac{10}{4331}\)

vì \(\frac{10}{1244}>\frac{10}{4331}\Rightarrow1-\frac{10}{1244}< 1-\frac{10}{4331}\)

\(\Rightarrow\frac{1234}{1244}< \frac{4321}{4331}\)

\(\Rightarrow\frac{-1234}{1244}>\frac{-4321}{4331}\) 

A)

1- 1234/1235= 1/1235

1- 4319/4320= 1/4320

Vậy 1/1235 > 1/4320

1234/1235 > 4329/4320

Đ/s:...

Ko chắc, sai bỏ qa

a) 

\(\frac{1234}{1235}=1-\frac{1}{1235}\)

\(\frac{4319}{4320}=1-\frac{1}{4320}\)

Ta có: 4320>1235 => \(\frac{1}{4320}< \frac{1}{1235}\Rightarrow1-\frac{1}{4320}>1-\frac{1}{1235}\Rightarrow\frac{4319}{4320}>\frac{1234}{1235}\)

b) Em tham khảo link Câu hỏi của Jenna - Toán lớp 7 - Học toán với OnlineMath

\(\frac{-1234}{1244}=\frac{10}{1234}-\frac{1244}{1244}=\frac{10}{1234}-1\)

\(\frac{-4321}{4331}=\frac{10}{4331}-\frac{4331}{4331}=\frac{10}{4331}-1\)

Vì 1234<4331 nên \(\frac{10}{1234}>\frac{10}{4331}\)

=>\(\frac{10}{1234}-1

a) \(\frac{1}{1235}>\frac{1}{4320}\Rightarrow-\frac{1}{1235}< -\frac{1}{4320}\Rightarrow1-\frac{1}{1235}< 1-\frac{1}{4320}\Rightarrow\frac{1234}{1235}< \frac{4319}{4320}.\)

b) \(\frac{10}{1244}< \frac{10}{4331}\Rightarrow\frac{10}{1244}-1< \frac{10}{4331}-1\Rightarrow-\frac{1234}{1244}< -\frac{4321}{4331}\)

a)  Ta có:

1234/1235 = 1 - 1/1235

4319/4320 = 1 - 1/4320

Vì 1/1235 > 1/4320

=> 1234/1235 < 4319/4320

b) -1234/1244 = -1 + 10/1244

-4321/4331 = -1 + 10/4331

Vì 10/1244 > 10/4331

=> -1 + 10/4331 > -1/4331

Ủng hộ mk nha ♡_♡

mình mới học lớp 4 nên ko bít

em ko biết,xin lỗi chị nhiều lắm

1234 phần 1235 bằng 4319 phần 4320

đúng máy tính mà tính

hok tốt nhé

tk tuii nhé

\(1+1=2\)

\(2.3=6\)

\(8.72:9=576:9=64\)

\(\frac{1234+4321}{4.7+5}=\frac{5555}{28+5}=\frac{5555}{33}=\frac{505.11}{3.11}=\frac{505}{3}\)

\(4,5.5+3,2.\frac{2}{1}=22,5+6,4=28,9\)

b] \(\frac{127}{-128}>-1\)\(;\)\(\frac{-1345}{1244}< -1\)

\(\Rightarrow\frac{127}{-128}>-1>\frac{-1345}{1244}\Rightarrow\frac{127}{-128}>\frac{-1345}{1244}\)

c]\(\frac{-11}{33}=\frac{-1}{3}\)\(;\)\(\frac{25}{-76}>\frac{25}{-75}=\frac{-1}{3}\)\(\Rightarrow\frac{-11}{33}=\frac{-1}{3}< \frac{25}{-76}\Rightarrow\frac{-11}{33}< \frac{25}{-76}\)

d] \(\frac{-171717}{232323}=\frac{-17\times10101}{23\times10101}=\frac{-17}{23}\)\(\Rightarrow\frac{-17}{23}=\frac{-171717}{232323}\)

\(=\dfrac{7408}{12963-5555}\cdot999=999\)

\(7408/12963-5555*999=7408/7408*999=1*999=999\)

\(\dfrac{8642-1234}{4321\times3-\left(4321+1234\right)}\times999=\dfrac{7408}{12963-5555}\times999=\dfrac{7408}{7408}\times999=1\times999=999\)