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nguyễn thảo hân
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Thắng Nguyễn
15 tháng 5 2016 lúc 17:38

\(B=7\left(\frac{5}{2.1}+\frac{4}{1.11}+...+\frac{13}{15.4}\right)\)

\(B=7\left(\frac{5}{2.7}+\frac{4}{7.11}+...+\frac{13}{15.28}\right)\)

\(B=7\left(\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{15}-\frac{1}{28}\right)\)

\(B=7\left(\frac{1}{2}-\frac{1}{28}\right)\)

\(B=7\times\frac{13}{28}\)

\(B=\frac{13}{4}\)

Nguyễn Thảo Hân
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Nguyễn Huy Tú
23 tháng 5 2016 lúc 19:30

\(\frac{1}{7}\)B=\(\frac{5}{2.7.1}+\frac{4}{1.7.11}+\frac{3}{11.2.7}+\frac{1}{2.7.15}+\frac{13}{15.4.7}\)

\(\frac{1}{7}\)B=\(\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.28}\)

\(\frac{1}{7}B=\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{28}\)

\(\frac{1}{7}B=\frac{1}{2}-\frac{1}{28}\)

\(\frac{1}{7}B=\frac{13}{28}\)

B=\(\frac{13}{28}:\frac{1}{7}\)

B=\(\frac{13}{4}\)

nguyenzuka
1 tháng 5 2019 lúc 15:02

1717B=52.7.1+41.7.11+311.2.7+12.7.15+1315.4.752.7.1+41.7.11+311.2.7+12.7.15+1315.4.7

1717B=52.7+47.11+311.14+114.15+1315.2852.7+47.11+311.14+114.15+1315.28

17B=12−17+17−111+111−114+114−115+115−12817B=12−17+17−111+111−114+114−115+115−128

17B=12−12817B=12−128

17B=132817B=1328

B=1328:171328:17

B=134

1717B=52.7.1+41.7.11+311.2.7+12.7.15+1315.4.752.7.1+41.7.11+311.2.7+12.7.15+1315.4.7

1717B=52.7+47.11+311.14+114.15+1315.2852.7+47.11+311.14+114.15+1315.28

17B=12−17+17−111+111−114+114−115+115−12817B=12−17+17−111+111−114+114−115+115−128

17B=12−12817B=12−128

17B=132817B=1328

B=1328:171328:17

B=134

1717B=52.7.1+41.7.11+311.2.7+12.7.15+1315.4.752.7.1+41.7.11+311.2.7+12.7.15+1315.4.7

1717B=52.7+47.11+311.14+114.15+1315.2852.7+47.11+311.14+114.15+1315.28

17B=12−17+17−111+111−114+114−115+115−12817B=12−17+17−111+111−114+114−115+115−128

17B=12−12817B=12−128

17B=132817B=1328

B=1328:171328:17

B=134

1717B=52.7.1+41.7.11+311.2.7+12.7.15+1315.4.752.7.1+41.7.11+311.2.7+12.7.15+1315.4.7

1717B=52.7+47.11+311.14+114.15+1315.2852.7+47.11+311.14+114.15+1315.28

17B=12−17+17−111+111−114+114−115+115−12817B=12−17+17−111+111−114+114−115+115−128

17B=12−12817B=12−128

17B=132817B=1328

B=1328:171328:17

B=134

1717B=52.7.1+41.7.11+311.2.7+12.7.15+1315.4.752.7.1+41.7.11+311.2.7+12.7.15+1315.4.7

1717B=52.7+47.11+311.14+114.15+1315.2852.7+47.11+311.14+114.15+1315.28

17B=12−17+17−111+111−114+114−115+115−12817B=12−17+17−111+111−114+114−115+115−128

17B=12−12817B=12−128

17B=132817B=1328

B=1328:171328:17

B=134

1717B=52.7.1+41.7.11+311.2.7+12.7.15+1315.4.752.7.1+41.7.11+311.2.7+12.7.15+1315.4.7

1717B=52.7+47.11+311.14+114.15+1315.2852.7+47.11+311.14+114.15+1315.28

17B=12−17+17−111+111−114+114−115+115−12817B=12−17+17−111+111−114+114−115+115−128

17B=12−12817B=12−128

17B=132817B=1328

B=1328:171328:17

B=134

1717B=52.7.1+41.7.11+311.2.7+12.7.15+1315.4.752.7.1+41.7.11+311.2.7+12.7.15+1315.4.7

1717B=52.7+47.11+311.14+114.15+1315.2852.7+47.11+311.14+114.15+1315.28

17B=12−17+17−111+111−114+114−115+115−12817B=12−17+17−111+111−114+114−115+115−128

17B=12−12817B=12−128

17B=132817B=1328

B=1328:171328:17

B=134

1717B=52.7.1+41.7.11+311.2.7+12.7.15+1315.4.752.7.1+41.7.11+311.2.7+12.7.15+1315.4.7

1717B=52.7+47.11+311.14+114.15+1315.2852.7+47.11+311.14+114.15+1315.28

17B=12−17+17−111+111−114+114−115+115−12817B=12−17+17−111+111−114+114−115+115−128

17B=12−12817B=12−128

17B=132817B=1328

B=1328:171328:17

B=134

Nguyễn Thảo Hân
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Tài Nguyễn Tuấn
15 tháng 5 2016 lúc 18:14

Ta có : 

\(B=\frac{5}{2\cdot1}+\frac{4}{1\cdot11}+\frac{3}{11\cdot2}+\frac{1}{2\cdot15}+\frac{13}{15\cdot4}\)

\(=>\frac{B}{7}=\frac{5}{2\cdot7}+\frac{4}{7\cdot11}+\frac{3}{11\cdot14}+\frac{1}{14\cdot15}+\frac{13}{15\cdot28}\)

\(=>\frac{B}{7}=\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{28}\)

\(=>\frac{B}{7}=\frac{1}{2}-\frac{1}{28}=\frac{14}{28}-\frac{1}{28}=\frac{13}{28}\)

\(=>B=\frac{13}{28}\cdot7=\frac{13}{4}\)

Phạm Nguyễn Tất Đạt
15 tháng 5 2016 lúc 17:57

Khó wá

Phạm Nguyễn Tất Đạt
15 tháng 5 2016 lúc 18:19

Hay

Rhider
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ILoveMath
19 tháng 11 2021 lúc 7:26

\(a,\Rightarrow A=-1\left(\dfrac{1}{4.5}+\dfrac{1}{5.6}+\dfrac{1}{6.7}+...+\dfrac{1}{9.10}\right)\)

\(\Rightarrow A=-1\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}+...+\dfrac{1}{9}-\dfrac{1}{10}\right)\)

\(\Rightarrow A=-1\left(\dfrac{1}{4}-\dfrac{1}{10}\right)\)

\(\Rightarrow A=\dfrac{-3}{20}\)

 

Nguyễn Hoàng Minh
19 tháng 11 2021 lúc 7:31

Bài 2:

\(a,\dfrac{1717}{8585}=\dfrac{1717:1717}{8585:1717}=\dfrac{1}{5};\dfrac{1313}{5151}=\dfrac{1313:101}{5151:101}=\dfrac{13}{51}\\ \dfrac{1}{5}=\dfrac{51}{255}< \dfrac{65}{255}=\dfrac{13}{51}\\ \Rightarrow\dfrac{1717}{8585}< \dfrac{1313}{5151}\)

\(b,\dfrac{201201}{202202}=\dfrac{201201:1001}{202202:1001}=\dfrac{201}{202}=\dfrac{201\cdot1001001}{202\cdot1001001}=\dfrac{201201201}{202202202}\)

トランホンアントゥ
19 tháng 11 2021 lúc 7:33

b1 ko bit

b2

1717/8585  <  1313/5151       201201/202202  >  201201201/202202202

( vì khi có tử số và mẫu số lớn hơn số kia thì số đó bé hơn)

♥Bạch Kim Hoàng Tử♥
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bímậtnhé
3 tháng 9 2018 lúc 21:25

\(\frac{1}{7}B=\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.28}\)

\(\frac{1}{7}B=\frac{1}{2}-\frac{1}{7}+...+\frac{1}{15}-\frac{1}{28}\)

\(\frac{1}{7}B=\frac{1}{2}-\frac{1}{28}=\frac{13}{28}\)

\(\Rightarrow B=\frac{13}{28}.7=\frac{13}{4}\)

pham mai linh
Xem chi tiết
huynh tran van thi
15 tháng 2 2017 lúc 7:55

\(\frac{13}{4}\)

Cô Bé Yêu Đời
15 tháng 2 2017 lúc 12:24

\(B=\frac{5}{2.1}+\frac{4}{1.11}+\frac{3}{11.2}+\frac{1}{2.15}+\frac{13}{15.4}\)

\(\Rightarrow\frac{B}{7}=\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.28}\)

\(\Rightarrow\frac{B}{7}=\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{28}\)

\(\Rightarrow\frac{B}{7}=\frac{1}{2}-\frac{1}{28}\)

\(\Rightarrow\frac{B}{7}=\frac{14}{28}-\frac{1}{28}\)

\(\Rightarrow\frac{B}{7}=\frac{13}{28}\)

\(\Rightarrow B=\frac{13}{28}.7\)

\(\Rightarrow B=\frac{13}{4}\)

H cc
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Lưu Quỳnh Anh
9 tháng 3 2017 lúc 5:55

\(B=\dfrac{5}{2.1}+\dfrac{4}{1.11}+\dfrac{3}{11.2}+\dfrac{1}{2.15}+\dfrac{13}{15.4}\)

\(\dfrac{B}{7}=\dfrac{5}{2.7}+\dfrac{4}{7.11}+\dfrac{3}{11.14}+\dfrac{1}{14.15}+\dfrac{13}{15.4}\)

\(\dfrac{B}{7}=\dfrac{1}{2}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{7}{11}+...+\dfrac{1}{15}-\dfrac{1}{28}\)

\(\dfrac{B}{7}=\dfrac{1}{2}-\dfrac{1}{28}\)

\(\dfrac{B}{7}=\dfrac{13}{28}\)

\(B=\dfrac{13}{28}.7=\dfrac{13}{4}\)

Fenny
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Nhật Hạ
13 tháng 6 2020 lúc 15:45

\(B=\frac{5}{2.1}+\frac{4}{1.11}+\frac{3}{11.2}+\frac{1}{2.15}+\frac{13}{15.4}\)

\(\Rightarrow\frac{B}{7}=\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.28}\)

\(\Rightarrow\frac{B}{7}=\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{28}\)

\(\Rightarrow\frac{B}{7}=\frac{1}{2}-\frac{1}{28}=\frac{13}{28}\)

\(\Rightarrow B=\frac{13}{28}.7=\frac{13}{4}\)

Khách vãng lai đã xóa
Bạn Thân Yêu
Xem chi tiết
Đỗ Đình Dũng
4 tháng 4 2016 lúc 12:27

\(B=\frac{5}{2.1}+\frac{4}{1.11}+\frac{3}{11.2}+\frac{1}{2.15}+\frac{13}{15.4}\)

\(B:7=\frac{5}{2.1}+\frac{4}{1.11}+\frac{3}{11.2}+\frac{1}{2.15}+\frac{13}{15.4}\)

\(\frac{B}{7}=\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.4}\)

\(\frac{B}{7}=\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{15}-\frac{1}{28}\)

\(\frac{B}{7}=\frac{1}{2}-\frac{1}{28} \)

\(\frac{B}{7}=\frac{13}{28}\)

B=\(\frac{13}{28}\cdot7\)

B=\(\frac{13}{4}\left(=3\frac{1}{4}\right)\)

Đỗ Đình Dũng
4 tháng 4 2016 lúc 12:30

\(B=\frac{5}{2.1}+\frac{4}{1.11}+\frac{3}{11.2}+\frac{1}{2.15}+\frac{13}{15.4}\)

\(\frac{B}{7}=\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.4}\)

\(\frac{B}{7}=\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{15}-\frac{1}{28}\)

\(\frac{B}{7}=\frac{1}{2}-\frac{1}{28}\)

\(\frac{B}{7}=\frac{13}{28}\)

\(B=\frac{13}{4}\left(=3\frac{1}{4}\right)\)

Đỗ Đình Dũng
4 tháng 4 2016 lúc 12:32

cái này 

\(B=\frac{5}{2.1}+\frac{4}{1.11}+\frac{3}{11.2}+\frac{1}{2.15}+\frac{13}{15.4}\)

là B=\(\frac{5}{2.1}+\frac{4}{1.11}+\frac{3}{11.2}+\frac{1}{2.15}+\frac{13}{15.4}\)