Giang ho dai ca viet nham nhé:

\(5.3^x=8.3^9+7.27^3\)

<=> \(5.3^x=8.3^9+7.\left(3^3\right)^3\) <=> \(5.3^x=8.3^9+7.3^9\)

<=> \(5.3^x=15.3^9\) <=> \(3^x=3.3^9=3^{10}\) => x = 10

nhầm chỉnh lại :

\(5.3^x=8.3^9+7.27^3\Rightarrow5.3^x=8.3^9+7.3^9=15.3^9\Rightarrow15.3^{x-1}=15.3^9\Rightarrow3^{x-1}=3^9\Rightarrow x-1=9\Rightarrow x=10\)

Có 5.3^x=8.3^9+7.27^3

=>5.3^x=8.3^9+7.(3^3)^3

=>5.3^x=8.3^9+7.3^9

=>5.3^x=3^9.(8+7)

=>5.3^x=3^9.15

=>3^x=3^9.15:5

=>3^x=3^9.3

=>3^x=3^10

=>x=10

Vậy x=10

Phần trong ngoặc.........phân tích cơ số ra thừa số nguyên tố:

\(125^3\cdot7^5-175^5:5=\left(5^3\right)^3\cdot7^5-\left(5^2\cdot7\right)^5:5=5^9\cdot7^5-5^9\cdot7^5=0\)

1) ( 125³ . 7⁵ - 175⁵ : 5 ) : 2016²⁰¹⁷ = 0: 2016^2017 = 0 

2)

a)5* 3^x = 8*3^9 + 8* 27^3 

3^x = 59049

x=10

1) = 0

2) a = 10

b) khó qá bn ạk

mk chẳng hiểu đề lắm

nha bn

Câu b

\(5\cdot3^x=8\cdot3^9+7\cdot27^3\)

\(\Leftrightarrow5\cdot3^x=8\cdot3^9+7\cdot\left(3^3\right)^3\)

\(\Leftrightarrow5\cdot3^x=8\cdot3^9+7\cdot^9\)

\(\Leftrightarrow5\cdot3^x=15\cdot3^9\)

\(\Leftrightarrow3^x=3\cdot3^9=3^{10}\)

Vậy \(x=10\)

#kido

5 . 3^x = 8. 3¹ + 7. ( 3¹) ⁸

5 . 3^x = (3¹)⁸. (7+8)

5 . 3^x = 3⁹ . 15

5 . 3^x = 295245

     3^x = 295245 : 5

     3^x =  59049

     3^x = 3¹⁰

`@` `\text {Ans}`

`\downarrow`

`9^8 \div 3^2`

`= (3^2)^8 \div 3^2`

`= 3^16 \div 3^2`

`=`\(3^{16-2}=3^{14}\)

_____

`3^7 * 27^5 * 81^3`

`= 3^7*(3^3)^5 * (3^4)^3`

`= 3^7 * 3^15 * 3^12`

`=`\(3^{7+15+12}\)

`= 3^34`

______

`36^5 \div 18^5`

`= (36 \div 18)^5`

`= 2^5 = 32`

______

`24*5^5 + 5^2*5^3`

`= 24*5^5 + 5^5`

`= 5^5*(24+1)`

`= 5^5 * 25`

`= 5^5*5^2`

`= 5^7`

______

`125^4 \div 5^8`

`= (5^3)^4 \div 5^8`

`= 5^12 \div 5^8`

`= 5^4`

_____

`@` Phép nâng lên lũy thừa: \(\left(a^m\right)^n=a^{m\cdot n}\) 

`@` Chia lũy thừa cùng cơ số: \(a^m\div a^n=a^{m-n}\)

`@` Nhân lũy thừa cùng cơ số: \(a^m\cdot a^n=a^{m+n}\)

\(9^8:3^2\)

\(=\left(3^2\right)^8:3^2\)

\(=3^{16}:3^2\)

\(=3^{14}\)

=============

\(3^7\cdot27^5\cdot81^3\)

\(=3^7\cdot\left(3^3\right)^5\cdot\left(3^4\right)^3\)

\(=3^7\cdot3^{15}\cdot3^{12}\)

\(=3^{7+12+15}\)

\(=3^{34}\)

===============

\(36^5:18^5\)

\(=\left(36:18\right)^5\)

\(=2^5\)

\(=32\)

=============

\(24\cdot5^5+5^2\cdot5^3\)

\(=24\cdot5^5+5^5\)

\(=5^5\cdot\left(24+1\right)\)

\(=5^5\cdot25\)

\(=5^5\cdot5^2\)

\(=5^7\)

==============

\(125^4:5^8\)

\(=\left(5^3\right)^4:5^8\)

\(=5^{12}:5^8\)

\(=5^4\)

a. 5x3^x= 8x19683+7x19683

    5x3^x=(8+7)x19683

   5x3^x=15x19683

   5x3^x= 295245

   3^x=295245:5

       =59049

3^x= 3^10

vậy x=10

d.x-32=0:45

  x-32=0

  x=0+32

  x=32

sắp hết giờ rồi.............huhuhu

c) 125:5^3

=125:125

=1

mik chỉ làm đc câu c thôi nha