( 12 x X -64 ) x512 + 4x 1096
\(\dfrac{x+8}{1092}+\dfrac{x+10}{1094}=\dfrac{x+12}{1096}+\dfrac{x+14}{1098}\)
Giải giúp mình!
\(\dfrac{x+8}{1092}+\dfrac{x+10}{1094}=\dfrac{x+12}{1096}+\dfrac{x+14}{1098}\)
\(\Leftrightarrow\left(\dfrac{x+8}{1092}-1\right)+\left(\dfrac{x+10}{1094}-1\right)\)\(=\left(\dfrac{x+12}{1096}-1\right)+\left(\dfrac{x+14}{1098}-1\right)\)
\(\Leftrightarrow\dfrac{x-1084}{1092}+\dfrac{x-1084}{1094}=\dfrac{x-1084}{1096}+\dfrac{x-1084}{1098}\)
\(\Leftrightarrow\dfrac{x-1084}{1092}+\dfrac{x-1084}{1094}-\dfrac{x-1084}{1096}-\dfrac{x-1084}{1098}=0\)
\(\Leftrightarrow\left(x-1084\right).\left(\dfrac{1}{1092}+\dfrac{1}{1094}-\dfrac{1}{1096}-\dfrac{1}{1098}\right)=0\)
\(\Rightarrow x-1084=0\Rightarrow x=1084\)
Vậy x=1084
Tim x
\(\sqrt{4x^2-16x+64}+2x=12\)
ĐKXĐ: \(x\ge4\)
\(\sqrt{4x^2-16x+64}+2x=12\)
\(\Leftrightarrow\sqrt{\left(2x-8\right)^2}+2x=12\)
\(\Leftrightarrow\left|2x-8\right|+2x=12\)
Vì \(x\ge4\) \(\Rightarrow2x-8+2x=12\)
\(\Leftrightarrow4x=20\)
\(\Leftrightarrow x=5\left(TM\right)\)
Vậy x = 5
(4x-12)(x³+64)=0
Ta có (4x-12)(x³+64)=0
Suy ra 4x - 12 = 0 hoặc x³ + 64 = 0
=> 4x = 12 hoặc x³ = - 64
=> x = 3 hoặc x = - 4
Vậy x = 3 hoặc x = - 4
(4x-12)(x³+64)=0
\(\Rightarrow\orbr{\begin{cases}4x-12=0\\x^3+64=0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}4x=12\\x^3=-64\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=3\\x^3=\left(-4\right)^3\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=3\\x=-4\end{cases}}\)
Vậy \(x\in\left\{3;-4\right\}\)
Hok tốt !
Giải các phương trình sau: 1)√3x²-√12=0
2)√(x-3)²=9
3)√4x²+4x+1=6
4)√(2x-1)²=3
5)√(x-3)²=3-x 6)√4x²-20x+25+2x=5
7)√1-12x+36x²=5
1.
$\sqrt{3x^2}-\sqrt{12}=0$
$\Leftrightarrow \sqrt{3x^2}=\sqrt{12}$
$\Leftrightarrow 3x^2=12$
$\Leftrightarrow x^2=4$
$\Leftrightarrow (x-2)(x+2)=0\Leftrightarrow x=\pm 2$
2.
$\sqrt{(x-3)^2}=9$
$\Leftrightarrow |x-3|=9$
$\Leftrightarrow x-3=9$ hoặc $x-3=-9$
$\Leftrightarrow x=12$ hoặc $x=-6$
3.
$\sqrt{4x^2+4x+1}=6$
$\Leftrightarrow \sqrt{(2x+1)^2}=6$
$\Leftrightarrow |2x+1|=6$
$\Leftrightarrow 2x+1=6$ hoặc $2x+1=-6$
$\Leftrightarrow x=\frac{5}{2}$ hoặc $x=\frac{-7}{2}$
5 x X + 3 x X = 1096
5*X + 3*X = 1096
=> (5+3)*X = 1096
=> 8X = 1096
=>X = 1096 : 8 = 137
5 x X + 3 x X =1096
<=> X x ( 5 + 3 ) = 1096
<=> X x 8 = 1096
=> X = 1096 : 8
X = 137
5x X + 3 x X = 1096
5x + 3x = 1096
x.(5+3) = 1096
x. 8 = 1096
x = 1096 : 8
x = 137
Cho x+ y=12 và x khác 4.Tìm GTLN của biểu thức A= x^2 -4x+xy-4y/x^3-64
\(\sqrt{16x-64}-12\sqrt{\dfrac{x-4}{4}}+2\sqrt{4x-16}=6\)
\(\Leftrightarrow\sqrt{x-4}\left(4-12\cdot\dfrac{1}{2}+2\cdot2\right)=6\)
=>x-4=9
hay x=13
5 * x + 3 * x = 1096
5x + 3x = 1096
➡️8x = 1096
➡️x = 1096 ÷ 8 = 137
Hok tốt~
5 x x+ 3 x x = 1098
8x =1098
X = 1098 :8
X = 137
Vậy x = 137
5*x+3*x=1096
5*x+3*x=1096
=> x*(5+3) = 1096
=> x * 8 = 1096
=> x = 1096 : 8
=> x = 137
5*x+3*x=1096
(5+3)*x=1096
8*x=1096
x=1096:8
x=137
vậy x = 137
5*x+3*x=1096
=> x*(5+3) = 1096
=> x * 8 = 1096
=> x = 1096 : 8
=> x = 137
Ai k mk mk k lại!